Subhamitra Patra
2018-Nov-21 08:27 UTC
[R] [R studio] Plotting of line chart for each columns at 1 page
Sir, in the bold portion of the below code, I have some confusion which I am mentioning below that "ylab="MPG",main=names(MPG3)[i],*xaxt="n"*) axis(*1*,at=1:nrows,*labels=MPG3$Year*)" 1. Here, what *xaxt="n"* indicates? I think it indicates the no. of rows, right? 2. 1 in the 2nd line represents the no. of graphs. Let suppose, 38 plots are having the same row, I need to mention them as *axis(38, at=1:nrows)*, right? 3. *labels=**MPG3$Year *will give the name of all years in the X-axis, right? Kindly correct me if I am wrong. Sir, here one thing I would like to ask, my data frequency is not yearly. I obtained results from the daily data of the period from 1994-2017 (that means the no. of rows will be 5655). But, as the daily period is very unclear to mention in the X-axis, I wanted to give year name as the name of the X-axis (that means, 1995, 1997, 1999 with the increment of 2 years up to 2017). Sir, please suggest me how to proceed with this? Thank you very much for your kind help. [image: Mailtrack] <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> Sender notified by Mailtrack <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> 11/21/18, 1:46:50 PM On Wed, Nov 21, 2018 at 1:21 PM Jim Lemon <drjimlemon at gmail.com> wrote:> Now we're getting somewhere. I suspect that each Excel sheet looks > something like this: > > Year Tonga Samoa Fiji > 2008 21.2 32.0 18.7 > ... > 2017 23.7 31.9 19.3 > # in the above there are three columns (countries) and ten rows > # import this sheet as "MPG3" > nrows<-nrow(MPG3) # nrows equals 10 > ncols<-ncol(MPG3) # ncols equals 3 > for(i in 1:ncols) > plot(seq(1:nrows,MPG3[,i],type="l",xlab="Distance", > ylab="MPG",main=names(MPG3)[i],xaxt="n") > axis(1,at=1:nrows,labels=MPG3$Year) > > I probably have the structure of the imported data frame wrong, but I > think you can work that out. > > Jim > > > > On Wed, Nov 21, 2018 at 4:08 PM Subhamitra Patra < > subhamitra.patra at gmail.com> wrote: > >> As per your suggestion, *"you will need to adjust the number of "x" >> values to match the number of "y" values. Now with the addition of the >> nrow function, the code for each sheet will be* >> >> >> *ncolumns<-ncol(mpg)* >> * nrows<-nrow(mpg) * >> >> >> *for(i in >> 1:ncolumns) plot(seq(1,500,length.out=10),mpg[,i],type="l",xlab="Distance", >> ylab="MPG",main=names(mpg)[i]) * >> >> #####The no. of rows for the columns in one sheet will be the same. In >> the X-axis, I need to mention Year which is the same for all columns in a >> sheet. But, the starting year varies from one sheet to other. >> >> *Sir, please suggest in case of any mistakes.* >> >> Second, I will definitely consider your suggestions about the division of >> sample by similar characteristics so that it can be easier to show in >> graphical. Thank you very much, sir, for such creative and wonderful >> suggestions. >> >> >> >> [image: Mailtrack] >> <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> Sender >> notified by >> Mailtrack >> <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> 11/21/18, >> 10:35:03 AM >> >> On Wed, Nov 21, 2018 at 9:40 AM Jim Lemon <drjimlemon at gmail.com> wrote: >> >>> For your first question, yes, you will need to adjust the number of "x" >>> values to match the number of "y" values. You can use the "nrow" function >>> to get that number. I don't really know what the abscissa scale is on your >>> plots, I just made up the data I used. >>> >>> If you are comparing countries, you may want to divide the results into >>> countries of different characteristics, perhaps GDP or similar. Otherwise >>> you will end up with a quite large PDF page. This is okay if you are >>> viewing it electronically, but will present a challenge in hard copy. >>> >>> Jim >>> >>> On Wed, Nov 21, 2018 at 2:51 PM Subhamitra Patra < >>> subhamitra.patra at gmail.com> wrote: >>> >>>> Hello Sir, >>>> >>>> Thank you very much. I will try it out and will let you the result. >>>> >>>> The no. of rows varies per sheet by a different number of observations. >>>> Due to different no. of rows or observations, I separated the columns in >>>> different sheets. >>>> >>>> *Will a different number of rows create a problem for appending all >>>> plots?* >>>> >>>> Concerning your last suggestion "*This seems like a lot of plots, and >>>> I suspect that you could work out a better way to display all this >>>> information.*", I am doing a multi-country study and obtained results >>>> for each country. I would summarize the final result at the end. But, for >>>> displaying the information for each country, I thought the plot is the best >>>> way to give a supplementary result on each country. Sir, in this context, I >>>> would like to take your suggestion that Is the way what I am doing, right >>>> to proceed? If any alternative way is available, please suggest me. >>>> >>>> Thank you very much, Sir, for your kind help and suggestions. >>>> >>>> [image: Mailtrack] >>>> <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> Sender >>>> notified by >>>> Mailtrack >>>> <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> 11/21/18, >>>> 9:12:14 AM >>>> >>>> On Wed, Nov 21, 2018 at 8:18 AM Jim Lemon <drjimlemon at gmail.com> wrote: >>>> >>>>> I assume that you are importing the Excel sheets separately. When you >>>>> import a sheet, you can get the number of columns with this: >>>>> >>>>> ncol(<name of data frame>) >>>>> >>>>> Using the data frame "mpg" that I created: >>>>> >>>>> ncolumns<-ncol(mpg) >>>>> ncolumns >>>>> [1] 38 >>>>> >>>>> You can then substitute "ncolumns" each time you import another sheet. >>>>> How you want to deal with the varying numbers of columns you will get is >>>>> another matter. One way is to work out the total number of plots you want >>>>> and put them all onto one PDF page. Say you have 50 plots overall. You >>>>> could start a very big PDF page: >>>>> >>>>> pdf("allplots.pdf",width=30,height=15) >>>>> par(mfrow=c(5,10)) >>>>> # import your first sheet here (38 columns) >>>>> ncolumns<-ncol(mpg) >>>>> for(i in 1:ncolumns) >>>>> plot(seq(1,500,length.out=10),mpg[,i],type="l",xlab="Distance", >>>>> ylab="MPG",main=names(mpg)[i])# import your second sheet here, say >>>>> 10 columns >>>>> # import your second sheet here, (10 columns) >>>>> ncolumns<-ncol(mpg1) >>>>> for(i in 1:ncolumns) >>>>> plot(seq(1,500,length.out=10),mpg1[,i],type="l",xlab="Distance", >>>>> ylab="MPG",main=names(mpg)[i])# import your third sheet here, say 2 >>>>> columns >>>>> # import your second sheet here, (2 columns) >>>>> ncolumns<-ncol(mpg2) >>>>> for(i in 1:ncolumns) >>>>> plot(seq(1,500,length.out=10),mpg2[,i],type="l",xlab="Distance", >>>>> ylab="MPG",main=names(mpg)[i]) >>>>> # finish plotting >>>>> dev.off() >>>>> >>>>> You would then have 50 plots on the PDF page. I am assuming that all >>>>> of your sheets have the same number of rows and a few other things. This >>>>> seems like a lot of plots, and I suspect that you could work out a better >>>>> way to display all this information. >>>>> >>>>> Jim >>>>> >>>>> >>>>> On Wed, Nov 21, 2018 at 1:20 PM Subhamitra Patra < >>>>> subhamitra.patra at gmail.com> wrote: >>>>> >>>>>> Hello Sir, >>>>>> >>>>>> Thanks, now I understood and will check them out. >>>>>> >>>>>> One more thing I want to ask that I have 1 excel file with multiple >>>>>> (i.e. 12 sheets). Each sheet contains different number of columns, for >>>>>> instance, 1st sheet contains 38 columns, 2nd sheet contains 10 columns, >>>>>> Third 2 columns, 4th 1 column and so on. Actually, due to some missing >>>>>> observations in these columns, I couldn't add them in 1 sheet. >>>>>> >>>>>> As you suggested the below code in the last mail, >>>>>> >>>>>> par(mfrow=c(4,10)) >>>>>> for(i in 1:38) >>>>>> plot(seq(1,500,length.out=10),mpg[,i],type="l",xlab="Distance", >>>>>> ylab="MPG",main=names(mpg)[i]) >>>>>> dev.off() >>>>>> >>>>>> Do I need to run the code separately for each sheet? >>>>>> >>>>>> Actually, in par (mfrow=c(4,10)), the plot for 38 columns will be >>>>>> added, the space for extra 2 will remain as empty. So, I thought to add >>>>>> plots for the columns from the next sheet in those emptied space. >>>>>> >>>>>> Is there any way that I can add plots from the next sheets of the >>>>>> same excel file in the emptied space? In other words, Is there any way to >>>>>> append plots from all sheets? >>>>>> >>>>>> Kindly help a new R learner Sir for which I shall be always grateful >>>>>> to you. >>>>>> >>>>>> Thank you very much for your kind help. >>>>>> >>>>>> >>>>>> >>>>>> [image: Mailtrack] >>>>>> <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> Sender >>>>>> notified by >>>>>> Mailtrack >>>>>> <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> 11/21/18, >>>>>> 7:30:30 AM >>>>>> >>>>>> On Wed, Nov 21, 2018 at 7:17 AM Jim Lemon <drjimlemon at gmail.com> >>>>>> wrote: >>>>>> >>>>>>> Hi Subhamitra, >>>>>>> >>>>>>> 1. Here I manufacture some data so that the example is >>>>>>> "reproducible", that is anyone can run the code and get the same output >>>>>>> that I do. Yes, veh1...veh38 are the names of the variables. >>>>>>> >>>>>>> 2. Here I join the 38 variables I created into a data frame, which I >>>>>>> think is the input for your plotting routine. This names of the columns of >>>>>>> the data frame become the names of the variables. >>>>>>> >>>>>>> When you say that you want the column names as the "header" (title) >>>>>>> of each plot, I think if you change the plotting loop to this: >>>>>>> >>>>>>> pdf("mpg.pdf",width=30,height=12) >>>>>>> par(mfrow=c(4,10)) >>>>>>> for(i in 1:38) >>>>>>> plot(seq(1,500,length.out=10),mpg[,i],type="l",xlab="Distance", >>>>>>> ylab="MPG",main=names(mpg)[i]) >>>>>>> dev.off() >>>>>>> >>>>>>> you will get what you requested. Remember that I have done this in >>>>>>> base graphics, not ggplot. >>>>>>> >>>>>>> Jim >>>>>>> >>>>>>> On Wed, Nov 21, 2018 at 12:37 PM Subhamitra Patra < >>>>>>> subhamitra.patra at gmail.com> wrote: >>>>>>> >>>>>>>> Hello Sir, >>>>>>>> >>>>>>>> Thanks, I'll check them out. >>>>>>>> >>>>>>>> But, I am not understanding 2 points of your suggestion. >>>>>>>> >>>>>>>> 1. In the line,* "*for(i in 1:38) assign(paste0("veh",i),rep(sam >>>>>>>> ple(10:35,1),10)+runif(10,-4,*4))", *what veh, rep(sam >>>>>>>> ple(10:35,1),10)+runif(10,-4,4)) indicate? Here veh indicates >>>>>>>> columns right? >>>>>>>> *2. In the >>>>>>>> line, mpg<-data.frame(veh1,veh2,veh3,veh4,veh5,veh6,veh7,veh8,veh9,veh10,* >>>>>>>> * veh11,veh12,veh13,veh14,**veh15,veh16,veh17,veh18,veh19,**veh20,* >>>>>>>> * veh21,veh22,veh23,veh24,**veh25,veh26,veh27,veh28,veh29,**veh30,* >>>>>>>> * veh31,veh32,veh33,veh34,**veh35,veh36,veh37,veh38) ** , *veh[i] >>>>>>>> indicates column sequence, right? I need to give column names as the header >>>>>>>> of their respective graphs. Please suggest me How to add this? >>>>>>>> >>>>>>>> >>>>>>>> I am very new to R and therefore asking you these queries which >>>>>>>> might be simple for you. >>>>>>>> >>>>>>>> I expect positive help from you. >>>>>>>> >>>>>>>> Thanks for your kind help. >>>>>>>> [image: Mailtrack] >>>>>>>> <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> Sender >>>>>>>> notified by >>>>>>>> Mailtrack >>>>>>>> <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> 11/21/18, >>>>>>>> 7:02:18 AM >>>>>>>> >>>>>>>> >>>>>>>> On Wed, Nov 21, 2018 at 4:38 AM Jim Lemon <drjimlemon at gmail.com> >>>>>>>> wrote: >>>>>>>> >>>>>>>>> Hi Subhamitra, >>>>>>>>> As Bert noted, you are mixing base and grid graphics. Here is a >>>>>>>>> simple >>>>>>>>> way to get a plot like what you described. It will probably take >>>>>>>>> more >>>>>>>>> work to find what you actually do want and discover how to get it. >>>>>>>>> >>>>>>>>> for(i in 1:38) >>>>>>>>> assign(paste0("veh",i),rep(sample(10:35,1),10)+runif(10,-4,4)) >>>>>>>>> mpg<-data.frame(veh1,veh2,veh3,veh4,veh5,veh6,veh7,veh8,veh9,veh10, >>>>>>>>> veh11,veh12,veh13,veh14,veh15,veh16,veh17,veh18,veh19,veh20, >>>>>>>>> veh21,veh22,veh23,veh24,veh25,veh26,veh27,veh28,veh29,veh30, >>>>>>>>> veh31,veh32,veh33,veh34,veh35,veh36,veh37,veh38) >>>>>>>>> pdf("mpg.pdf",width=30,height=12) >>>>>>>>> par(mfrow=c(4,10)) >>>>>>>>> for(i in 1:38) >>>>>>>>> plot(seq(1,500,length.out=10),mpg[,i],type="l",xlab="Distance", >>>>>>>>> ylab=names(mpg)[i],main="MPG by distance") >>>>>>>>> dev.off() >>>>>>>>> >>>>>>>>> Jim >>>>>>>>> >>>>>>>>> On Wed, Nov 21, 2018 at 5:19 AM Subhamitra Patra >>>>>>>>> <subhamitra.patra at gmail.com> wrote: >>>>>>>>> > >>>>>>>>> > Dear R users, >>>>>>>>> > >>>>>>>>> > I have one excel file with 5 sheets. The no. of columns vary for >>>>>>>>> each >>>>>>>>> > sheet. The 1st sheet consists of 38 columns. So, I want to plot >>>>>>>>> 38 separate >>>>>>>>> > line charts and arrange them in par(mfrow = c(4, 10)) order. >>>>>>>>> Please suggest >>>>>>>>> > me how to do this. I have tried with the following code by >>>>>>>>> running a loop >>>>>>>>> > inside of a sheet, but it is not working. Further, I want to run >>>>>>>>> loops for >>>>>>>>> > each sheet. >>>>>>>>> > >>>>>>>>> > par(mfrow = c(4, 10)) >>>>>>>>> > loop.vector <- 1:38 >>>>>>>>> > for (i in loop.vector) >>>>>>>>> > x <- JJ[,i] >>>>>>>>> > library(ggplot2) >>>>>>>>> > library(cowplot) >>>>>>>>> > plot.mpg <- ggplot(mpg, aes(x, >>>>>>>>> > main = paste ("country", i), >>>>>>>>> > xlab = "Scores", >>>>>>>>> > xlim = c(1,500) >>>>>>>>> > y = colnames[i,], colour >>>>>>>>> factor(cyl))) + >>>>>>>>> > geom_line(size=2.5) >>>>>>>>> > save_plot("mpg.png", plot.mpg, >>>>>>>>> > base_aspect_ratio = 1.3) >>>>>>>>> > >>>>>>>>> > I want to give my X axis name as scores of (1,500) and Y axis as >>>>>>>>> the >>>>>>>>> > particular column names for all graphs. >>>>>>>>> > >>>>>>>>> > Please suggest. >>>>>>>>> > >>>>>>>>> > Thanks in advance. >>>>>>>>> > >>>>>>>>> > -- >>>>>>>>> > *Best Regards,* >>>>>>>>> > *Subhamitra Patra* >>>>>>>>> > *Phd. Research Scholar* >>>>>>>>> > *Department of Humanities and Social Sciences* >>>>>>>>> > *Indian Institute of Technology, Kharagpur* >>>>>>>>> > *INDIA* >>>>>>>>> > >>>>>>>>> > >>>>>>>>> > >>>>>>>>> > >>>>>>>>> > >>>>>>>>> > >>>>>>>>> > >>>>>>>>> > >>>>>>>>> > [image: Mailtrack] >>>>>>>>> > < >>>>>>>>> https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5& >>>>>>>>> > >>>>>>>>> > Sender >>>>>>>>> > notified by >>>>>>>>> > Mailtrack >>>>>>>>> > < >>>>>>>>> https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5& >>>>>>>>> > >>>>>>>>> > 11/20/18, >>>>>>>>> > 11:49:42 PM >>>>>>>>> > >>>>>>>>> > [[alternative HTML version deleted]] >>>>>>>>> > >>>>>>>>> > ______________________________________________ >>>>>>>>> > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, >>>>>>>>> see >>>>>>>>> > https://stat.ethz.ch/mailman/listinfo/r-help >>>>>>>>> > PLEASE do read the posting guide >>>>>>>>> http://www.R-project.org/posting-guide.html >>>>>>>>> > and provide commented, minimal, self-contained, reproducible >>>>>>>>> code. >>>>>>>>> >>>>>>>> >>>>>>>> >>>>>>>> -- >>>>>>>> *Best Regards,* >>>>>>>> *Subhamitra Patra* >>>>>>>> *Phd. Research Scholar* >>>>>>>> *Department of Humanities and Social Sciences* >>>>>>>> *Indian Institute of Technology, Kharagpur* >>>>>>>> *INDIA* >>>>>>>> >>>>>>> >>>>>> >>>>>> -- >>>>>> *Best Regards,* >>>>>> *Subhamitra Patra* >>>>>> *Phd. Research Scholar* >>>>>> *Department of Humanities and Social Sciences* >>>>>> *Indian Institute of Technology, Kharagpur* >>>>>> *INDIA* >>>>>> >>>>> >>>> >>>> -- >>>> *Best Regards,* >>>> *Subhamitra Patra* >>>> *Phd. Research Scholar* >>>> *Department of Humanities and Social Sciences* >>>> *Indian Institute of Technology, Kharagpur* >>>> *INDIA* >>>> >>> >> >> -- >> *Best Regards,* >> *Subhamitra Patra* >> *Phd. Research Scholar* >> *Department of Humanities and Social Sciences* >> *Indian Institute of Technology, Kharagpur* >> *INDIA* >> >-- *Best Regards,* *Subhamitra Patra* *Phd. Research Scholar* *Department of Humanities and Social Sciences* *Indian Institute of Technology, Kharagpur* *INDIA* [[alternative HTML version deleted]]
Jim Lemon
2018-Nov-21 09:11 UTC
[R] [R studio] Plotting of line chart for each columns at 1 page
1. xaxt="n" means "Don't display the X axis". See the help for "par" in the graphics package 2. axis(1,at=1:nrows,labels=names(MPG3)) This means, "Display the bottom axis (1) with ticks at 1 to the number of rows in the data frame" "Use the values of MPG$Year as labels for the ticks". see the help for "axis" in the graphics package Note that this should be in the same loop as "plot" Now I can see that my guess at the structure of the data was wrong. What you could do is to collapse the daily records into the means for the years. As I don't know what your spreadsheet looks like, I could only guess a method for this. You seem to be saying that you plot all 5655 values, but you want the axis to show just the years.Rather than tell you to convert your data to a time series, I'll suggest a quick hack. axis(1,at=seq(1,5655,by=365),labels=1994:2014) This _may_ work for you. I offer it because I can see that you do not have a lot of experience in R and you want to get the job done. If you can't get it to work, I apologize and you can blamelessly move to something else. Jim PS - If you don't know how to start HTML help - help.start() On Wed, Nov 21, 2018 at 7:26 PM Subhamitra Patra <subhamitra.patra at gmail.com> wrote:> Sir, in the bold portion of the below code, I have some confusion which I > am mentioning below that > > "ylab="MPG",main=names(MPG3)[i],*xaxt="n"*) > axis(*1*,at=1:nrows,*labels=MPG3$Year*)" > > 1. Here, what *xaxt="n"* indicates? I think it indicates the no. of rows, > right? > 2. 1 in the 2nd line represents the no. of graphs. Let suppose, 38 > plots are having the same row, I need to mention them as *axis(38, > at=1:nrows)*, right? > 3. *labels=**MPG3$Year *will give the name of all years in the X-axis, > right? > > Kindly correct me if I am wrong. > > Sir, here one thing I would like to ask, my data frequency is not yearly. > I obtained results from the daily data of the period from 1994-2017 (that > means the no. of rows will be 5655). But, as the daily period is very > unclear to mention in the X-axis, I wanted to give year name as the name of > the X-axis (that means, 1995, 1997, 1999 with the increment of 2 years up > to 2017). > > Sir, please suggest me how to proceed with this? > >[[alternative HTML version deleted]]
Subhamitra Patra
2018-Nov-21 09:39 UTC
[R] [R studio] Plotting of line chart for each columns at 1 page
OK, Sir. I will try as per your suggestions. Thank you very much for your kind help. [image: Mailtrack] <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> Sender notified by Mailtrack <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> 11/21/18, 3:07:47 PM On Wed, Nov 21, 2018 at 2:41 PM Jim Lemon <drjimlemon at gmail.com> wrote:> 1. xaxt="n" means "Don't display the X axis". See the help for "par" in > the graphics package > > 2. axis(1,at=1:nrows,labels=names(MPG3)) > This means, "Display the bottom axis (1) with ticks at 1 to the number of > rows in the data frame" > "Use the values of MPG$Year as labels for the ticks". see the help for > "axis" in the graphics package > Note that this should be in the same loop as "plot" > > Now I can see that my guess at the structure of the data was wrong. What > you could do is to collapse the daily records into the means for the years. > As I don't know what your spreadsheet looks like, I could only guess a > method for this. > > You seem to be saying that you plot all 5655 values, but you want the axis > to show just the years.Rather than tell you to convert your data to a time > series, I'll suggest a quick hack. > > axis(1,at=seq(1,5655,by=365),labels=1994:2014) > > This _may_ work for you. I offer it because I can see that you do not have > a lot of experience in R and you want to get the job done. If you can't get > it to work, I apologize and you can blamelessly move to something else. > > Jim > > PS - If you don't know how to start HTML help - help.start() > > On Wed, Nov 21, 2018 at 7:26 PM Subhamitra Patra < > subhamitra.patra at gmail.com> wrote: > >> Sir, in the bold portion of the below code, I have some confusion which >> I am mentioning below that >> >> "ylab="MPG",main=names(MPG3)[i],*xaxt="n"*) >> axis(*1*,at=1:nrows,*labels=MPG3$Year*)" >> >> 1. Here, what *xaxt="n"* indicates? I think it indicates the no. of >> rows, right? >> 2. 1 in the 2nd line represents the no. of graphs. Let suppose, 38 >> plots are having the same row, I need to mention them as *axis(38, >> at=1:nrows)*, right? >> 3. *labels=**MPG3$Year *will give the name of all years in the X-axis, >> right? >> >> Kindly correct me if I am wrong. >> >> Sir, here one thing I would like to ask, my data frequency is not yearly. >> I obtained results from the daily data of the period from 1994-2017 (that >> means the no. of rows will be 5655). But, as the daily period is very >> unclear to mention in the X-axis, I wanted to give year name as the name of >> the X-axis (that means, 1995, 1997, 1999 with the increment of 2 years up >> to 2017). >> >> Sir, please suggest me how to proceed with this? >> >>-- *Best Regards,* *Subhamitra Patra* *Phd. Research Scholar* *Department of Humanities and Social Sciences* *Indian Institute of Technology, Kharagpur* *INDIA* [[alternative HTML version deleted]]
Subhamitra Patra
2018-Dec-14 05:22 UTC
[R] [R studio] Plotting of line chart for each columns at 1 page
Dear Sir,
The method you suggested for arranging multiple plots in 1 pdf page has
finally worked.
Thank you very much.
But, I have 3 more queries as follows.
1. Is there any way that I can merge the respective plots from the
different excel files into 1? For instance, I have 3 excel files (i.e. EMs
1, EMs 2 and EMs 3) having 4 plots each. I want to merge 1st plots from 3
excel files into 1, 2nd plots from 3 excel files into 1, similarly 3rd and
4th plots from each respective files into 1?
2. Is there any way to range the scale of Y-axis for all plots because I
think if the range of the Y-axis for each plot is same, it can be easy to
interpret and compare the results. I used Ylim function. But, after using
the Ylim function, the plot is looking unclear than before. For your
convenience, I am providing my code.
pdf("EMs.pdf",width=20,height=20)
par(mfrow=c(5,4))
# import your first sheet here (38 columns)
ncolumns<-ncol(EMs1)
for(i in 1:ncolumns)
plot(EMs1[,i],type="l",col = "Red", xlab="Time",
ylab="APEn", ylim=c(0.1,2), main=names(EMs1)[i])
library(zoo)
*APEn=zoo(EMs1, seq(from = as.Date("1994-01-01"), to
as.Date("2017-08-03"), by = 1))*
#import your second sheet here, (10 columns)
ncolumns<-ncol(EMs2)
for(i in 1:ncolumns)
plot(EMs2[,i],type="l",col = "Red", xlab="Time",
ylab="APEn",ylim=c(0.1,2), main=names(EMs2)[i])
*APEn=zoo(EMs2, seq(from = as.Date("1994-01-01"), to
as.Date("2017-08-03"), by = 1))*
# import your Third sheet here, (2 columns)
ncolumns<-ncol(EMs3)
for(i in 1:ncolumns)
plot(EMs3[,i],type="l",col = "Red", xlab="Time",
ylab="APEn", ylim=c(0.1,2), main=names(EMs3)[i])
*APEn=zoo(EMs3, seq(from = as.Date("1996-01-01"), to
as.Date("2017-08-03"), by = 1)) *
# finish plotting
dev.off()
3. I want the corresponding date column (which is the daily date) on X-axis
of each plot. Thus, I added 1 line after the plot in the above (i.e. the
bold line). Please suggest me Is it the correct way that I am doing?
Sir, I am new in R and doing by learning.
Kindly suggest me regarding my previous queries for which I shall be always
grateful to you.
Thank you very much for educating a new R learner.
On Wed, Nov 21, 2018 at 3:20 PM Subhamitra Patra <subhamitra.patra at
gmail.com>
wrote:
> Thank you very much for your suggestions and help.
>
> [image: Mailtrack]
>
<https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&>
Sender
> notified by
> Mailtrack
>
<https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&>
11/21/18,
> 3:19:55 PM
>
> On Wed, Nov 21, 2018 at 3:09 PM Subhamitra Patra <
> subhamitra.patra at gmail.com> wrote:
>
>> OK, Sir. I will try as per your suggestions.
>>
>> Thank you very much for your kind help.
>>
>> [image: Mailtrack]
>>
<https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&>
Sender
>> notified by
>> Mailtrack
>>
<https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&>
11/21/18,
>> 3:07:47 PM
>>
>> On Wed, Nov 21, 2018 at 2:41 PM Jim Lemon <drjimlemon at
gmail.com> wrote:
>>
>>> 1. xaxt="n" means "Don't display the X
axis". See the help for "par" in
>>> the graphics package
>>>
>>> 2. axis(1,at=1:nrows,labels=names(MPG3))
>>> This means, "Display the bottom axis (1) with ticks at 1 to
the number
>>> of rows in the data frame"
>>> "Use the values of MPG$Year as labels for the ticks". see
the help for
>>> "axis" in the graphics package
>>> Note that this should be in the same loop as "plot"
>>>
>>> Now I can see that my guess at the structure of the data was wrong.
What
>>> you could do is to collapse the daily records into the means for
the years.
>>> As I don't know what your spreadsheet looks like, I could only
guess a
>>> method for this.
>>>
>>> You seem to be saying that you plot all 5655 values, but you want
the
>>> axis to show just the years.Rather than tell you to convert your
data to a
>>> time series, I'll suggest a quick hack.
>>>
>>> axis(1,at=seq(1,5655,by=365),labels=1994:2014)
>>>
>>> This _may_ work for you. I offer it because I can see that you do
not
>>> have a lot of experience in R and you want to get the job done. If
you
>>> can't get it to work, I apologize and you can blamelessly move
to something
>>> else.
>>>
>>> Jim
>>>
>>> PS - If you don't know how to start HTML help - help.start()
>>>
>>> On Wed, Nov 21, 2018 at 7:26 PM Subhamitra Patra <
>>> subhamitra.patra at gmail.com> wrote:
>>>
>>>> Sir, in the bold portion of the below code, I have some
confusion
>>>> which I am mentioning below that
>>>>
>>>>
"ylab="MPG",main=names(MPG3)[i],*xaxt="n"*)
>>>> axis(*1*,at=1:nrows,*labels=MPG3$Year*)"
>>>>
>>>> 1. Here, what *xaxt="n"* indicates? I think it
indicates the no. of
>>>> rows, right?
>>>> 2. 1 in the 2nd line represents the no. of graphs. Let suppose,
38
>>>> plots are having the same row, I need to mention them as
*axis(38,
>>>> at=1:nrows)*, right?
>>>> 3. *labels=**MPG3$Year *will give the name of all years in the
X-axis,
>>>> right?
>>>>
>>>> Kindly correct me if I am wrong.
>>>>
>>>> Sir, here one thing I would like to ask, my data frequency is
not
>>>> yearly. I obtained results from the daily data of the period
from
>>>> 1994-2017 (that means the no. of rows will be 5655). But, as
the daily
>>>> period is very unclear to mention in the X-axis, I wanted to
give year name
>>>> as the name of the X-axis (that means, 1995, 1997, 1999 with
the increment
>>>> of 2 years up to 2017).
>>>>
>>>> Sir, please suggest me how to proceed with this?
>>>>
>>>>
>>
>> --
>> *Best Regards,*
>> *Subhamitra Patra*
>> *Phd. Research Scholar*
>> *Department of Humanities and Social Sciences*
>> *Indian Institute of Technology, Kharagpur*
>> *INDIA*
>>
>
>
> --
> *Best Regards,*
> *Subhamitra Patra*
> *Phd. Research Scholar*
> *Department of Humanities and Social Sciences*
> *Indian Institute of Technology, Kharagpur*
> *INDIA*
>
--
*Best Regards,*
*Subhamitra Patra*
*Phd. Research Scholar*
*Department of Humanities and Social Sciences*
*Indian Institute of Technology, Kharagpur*
*INDIA*
[[alternative HTML version deleted]]
Jim Lemon
2018-Dec-14 09:18 UTC
[R] [R studio] Plotting of line chart for each columns at 1 page
Hi Subhamitra, As before, I don't have your data, so I cannot run your code. Similarly, when you say the plot is looking unclear, I have almost no idea what that means in terms of a plot that I could see and possibly correct. Let's start at the top anyway. You set up an array of 20 plots, then plot 38 series. This is going to cycle through your array almost twice, as each time you plot, you step forward one plot in the array. At the end of the first Excel data sheet, you will be at plot 18 out of the 20. You then display another 10 plots, leaving you at plot 8 in the array. Each time you plot into the same section of the array, you will wipe out the previous plot. Maybe this is why you are not getting what you want. Finally, you display a further two plots, leaving you at plot 10. If I am correct, you will have plots 31 to 38 from sheet 1 in the bottom two rows, with plots 1 and 2 from sheet two in positions 19 and 20, then 3 to 10 from sheet 2 in the top rows, finishing off with the two plots from sheet 3 in the 9th and 10th positions in the second row of the plot array. Of course I can't see what you actually have plotted, so this is but a desperate guess. I apologize for the complicated answer which is probably no use whatever, but without data and hopefully the output of your code, I am unable to read your mind. Jim On Fri, Dec 14, 2018 at 4:26 PM Subhamitra Patra <subhamitra.patra at gmail.com> wrote:> Sorry not previous queries, the 3 queries which I mentioned in my last > email. > > On Fri, Dec 14, 2018 at 10:52 AM Subhamitra Patra < > subhamitra.patra at gmail.com> wrote: > >> Dear Sir, >> >> The method you suggested for arranging multiple plots in 1 pdf page has >> finally worked. >> >> Thank you very much. >> >> But, I have 3 more queries as follows. >> >> 1. Is there any way that I can merge the respective plots from the >> different excel files into 1? For instance, I have 3 excel files (i.e. EMs >> 1, EMs 2 and EMs 3) having 4 plots each. I want to merge 1st plots from 3 >> excel files into 1, 2nd plots from 3 excel files into 1, similarly 3rd and >> 4th plots from each respective files into 1? >> 2. Is there any way to range the scale of Y-axis for all plots because I >> think if the range of the Y-axis for each plot is same, it can be easy to >> interpret and compare the results. I used Ylim function. But, after using >> the Ylim function, the plot is looking unclear than before. For your >> convenience, I am providing my code. >> >> pdf("EMs.pdf",width=20,height=20) >> par(mfrow=c(5,4)) >> # import your first sheet here (38 columns) >> ncolumns<-ncol(EMs1) >> for(i in 1:ncolumns) >> plot(EMs1[,i],type="l",col = "Red", xlab="Time", >> ylab="APEn", ylim=c(0.1,2), main=names(EMs1)[i]) >> library(zoo) >> *APEn=zoo(EMs1, seq(from = as.Date("1994-01-01"), to >> as.Date("2017-08-03"), by = 1))* >> #import your second sheet here, (10 columns) >> ncolumns<-ncol(EMs2) >> for(i in 1:ncolumns) >> plot(EMs2[,i],type="l",col = "Red", xlab="Time", >> ylab="APEn",ylim=c(0.1,2), main=names(EMs2)[i]) >> *APEn=zoo(EMs2, seq(from = as.Date("1994-01-01"), to >> as.Date("2017-08-03"), by = 1))* >> # import your Third sheet here, (2 columns) >> ncolumns<-ncol(EMs3) >> for(i in 1:ncolumns) >> plot(EMs3[,i],type="l",col = "Red", xlab="Time", >> ylab="APEn", ylim=c(0.1,2), main=names(EMs3)[i]) >> *APEn=zoo(EMs3, seq(from = as.Date("1996-01-01"), to >> as.Date("2017-08-03"), by = 1)) * >> # finish plotting >> dev.off() >> >> 3. I want the corresponding date column (which is the daily date) on >> X-axis of each plot. Thus, I added 1 line after the plot in the above (i.e. >> the bold line). Please suggest me Is it the correct way that I am doing? >> >> >> Sir, I am new in R and doing by learning. >> >> Kindly suggest me regarding my previous queries for which I shall be >> always grateful to you. >> >> Thank you very much for educating a new R learner. >> >> >> >> >> On Wed, Nov 21, 2018 at 3:20 PM Subhamitra Patra < >> subhamitra.patra at gmail.com> wrote: >> >>> Thank you very much for your suggestions and help. >>> >>> [image: Mailtrack] >>> <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> Sender >>> notified by >>> Mailtrack >>> <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> 11/21/18, >>> 3:19:55 PM >>> >>> On Wed, Nov 21, 2018 at 3:09 PM Subhamitra Patra < >>> subhamitra.patra at gmail.com> wrote: >>> >>>> OK, Sir. I will try as per your suggestions. >>>> >>>> Thank you very much for your kind help. >>>> >>>> [image: Mailtrack] >>>> <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> Sender >>>> notified by >>>> Mailtrack >>>> <https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&> 11/21/18, >>>> 3:07:47 PM >>>> >>>> On Wed, Nov 21, 2018 at 2:41 PM Jim Lemon <drjimlemon at gmail.com> wrote: >>>> >>>>> 1. xaxt="n" means "Don't display the X axis". See the help for "par" >>>>> in the graphics package >>>>> >>>>> 2. axis(1,at=1:nrows,labels=names(MPG3)) >>>>> This means, "Display the bottom axis (1) with ticks at 1 to the number >>>>> of rows in the data frame" >>>>> "Use the values of MPG$Year as labels for the ticks". see the help for >>>>> "axis" in the graphics package >>>>> Note that this should be in the same loop as "plot" >>>>> >>>>> Now I can see that my guess at the structure of the data was wrong. >>>>> What you could do is to collapse the daily records into the means for the >>>>> years. As I don't know what your spreadsheet looks like, I could only guess >>>>> a method for this. >>>>> >>>>> You seem to be saying that you plot all 5655 values, but you want the >>>>> axis to show just the years.Rather than tell you to convert your data to a >>>>> time series, I'll suggest a quick hack. >>>>> >>>>> axis(1,at=seq(1,5655,by=365),labels=1994:2014) >>>>> >>>>> This _may_ work for you. I offer it because I can see that you do not >>>>> have a lot of experience in R and you want to get the job done. If you >>>>> can't get it to work, I apologize and you can blamelessly move to something >>>>> else. >>>>> >>>>> Jim >>>>> >>>>> PS - If you don't know how to start HTML help - help.start() >>>>> >>>>> On Wed, Nov 21, 2018 at 7:26 PM Subhamitra Patra < >>>>> subhamitra.patra at gmail.com> wrote: >>>>> >>>>>> Sir, in the bold portion of the below code, I have some confusion >>>>>> which I am mentioning below that >>>>>> >>>>>> "ylab="MPG",main=names(MPG3)[i],*xaxt="n"*) >>>>>> axis(*1*,at=1:nrows,*labels=MPG3$Year*)" >>>>>> >>>>>> 1. Here, what *xaxt="n"* indicates? I think it indicates the no. of >>>>>> rows, right? >>>>>> 2. 1 in the 2nd line represents the no. of graphs. Let suppose, 38 >>>>>> plots are having the same row, I need to mention them as *axis(38, >>>>>> at=1:nrows)*, right? >>>>>> 3. *labels=**MPG3$Year *will give the name of all years in the >>>>>> X-axis, right? >>>>>> >>>>>> Kindly correct me if I am wrong. >>>>>> >>>>>> Sir, here one thing I would like to ask, my data frequency is not >>>>>> yearly. I obtained results from the daily data of the period from >>>>>> 1994-2017 (that means the no. of rows will be 5655). But, as the daily >>>>>> period is very unclear to mention in the X-axis, I wanted to give year name >>>>>> as the name of the X-axis (that means, 1995, 1997, 1999 with the increment >>>>>> of 2 years up to 2017). >>>>>> >>>>>> Sir, please suggest me how to proceed with this? >>>>>> >>>>>> >>>> >>>> -- >>>> *Best Regards,* >>>> *Subhamitra Patra* >>>> *Phd. Research Scholar* >>>> *Department of Humanities and Social Sciences* >>>> *Indian Institute of Technology, Kharagpur* >>>> *INDIA* >>>> >>> >>> >>> -- >>> *Best Regards,* >>> *Subhamitra Patra* >>> *Phd. Research Scholar* >>> *Department of Humanities and Social Sciences* >>> *Indian Institute of Technology, Kharagpur* >>> *INDIA* >>> >> >> >> -- >> *Best Regards,* >> *Subhamitra Patra* >> *Phd. Research Scholar* >> *Department of Humanities and Social Sciences* >> *Indian Institute of Technology, Kharagpur* >> *INDIA* >> > > > -- > *Best Regards,* > *Subhamitra Patra* > *Phd. Research Scholar* > *Department of Humanities and Social Sciences* > *Indian Institute of Technology, Kharagpur* > *INDIA* >[[alternative HTML version deleted]]
Subhamitra Patra
2018-Dec-15 05:15 UTC
[R] [R studio] Plotting of line chart for each columns at 1 page
Hello Sir,
I am extremely Sorry for the late reply.
Ok now, I am sending my data and output, and would like to discuss my
queries one by one.
This is my final code.
pdf("EMs.pdf",width=20,height=20)
par(mfrow=c(5,4))
# import your first sheet here (16 columns)
ncolumns<-ncol(EMs1.1)
for(i in 1:ncolumns)
plot(EMs1.1[,i],type="l",col = "Red",
xlab="Time",
ylab="APEn", main=names(EMs1.1)[i])
#import your second sheet here, (1 column)
ncolumns<-ncol(EMs2.1)
for(i in 1:ncolumns)
plot(EMs2.1[,i],type="l",col = "Red",
xlab="Time",
ylab="APEn", main=names(EMs2.1)[i])
# import your Third sheet here, (1 column)
ncolumns<-ncol(EMs3.1)
for(i in 1:ncolumns)
plot(EMs3.1[,i],type="l",col = "Red",
xlab="Time",
ylab="APEn", main=names(EMs3.1)[i])
# import your fourth sheet here, (1 column)
ncolumns<-ncol(EMs4.1)
for(i in 1:ncolumns)
plot(EMs4.1[,i],type="l",col = "Red",
xlab="Time",
ylab="APEn", main=names(EMs4.1)[i])
# finish plotting
dev.off()
With this code, I found the following results. I attached The data files
(in rar file containing 4 excel files) and the output of my result.
*My First query is :*
I am having daily data, and without defining the date column, I obtained
the results. Therefore, I found the no. of observation in my X-axis of the
plots (in the attached result Pdf file). Now, I need the date column in my
X-axis with the corresponding data. I considered 03-01-1994 to 03-08-2017
(Date-Month-Year) by excluding 2 non-trading days per week.
I know that the frequency for defining yearly data is 1. So, I tried with
the following code being attached to the plot code, but not sure that
whether It is giving the appropriate plot or not?
*library(zoo)*
*y=zoo(EMs1, seq(from = as.Date("1994-01-01"), to =
as.Date("2017-08-03"),
by = 1))*
*Therefore, kindly suggest me instead of getting the no. of observations in
the X-axis, how to get the date column in X-axis? *
[image: Mailtrack]
<https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&>
Sender
notified by
Mailtrack
<https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&>
12/15/18,
10:39:06 AM
On Fri, Dec 14, 2018 at 2:48 PM Jim Lemon <drjimlemon at gmail.com> wrote:
> Hi Subhamitra,
> As before, I don't have your data, so I cannot run your code.
Similarly,
> when you say the plot is looking unclear, I have almost no idea what that
> means in terms of a plot that I could see and possibly correct. Let's
start
> at the top anyway. You set up an array of 20 plots, then plot 38 series.
> This is going to cycle through your array almost twice, as each time you
> plot, you step forward one plot in the array. At the end of the first Excel
> data sheet, you will be at plot 18 out of the 20. You then display another
> 10 plots, leaving you at plot 8 in the array. Each time you plot into the
> same section of the array, you will wipe out the previous plot. Maybe this
> is why you are not getting what you want. Finally, you display a further
> two plots, leaving you at plot 10. If I am correct, you will have plots 31
> to 38 from sheet 1 in the bottom two rows, with plots 1 and 2 from sheet
> two in positions 19 and 20, then 3 to 10 from sheet 2 in the top rows,
> finishing off with the two plots from sheet 3 in the 9th and 10th positions
> in the second row of the plot array. Of course I can't see what you
> actually have plotted, so this is but a desperate guess. I apologize for
> the complicated answer which is probably no use whatever, but without data
> and hopefully the output of your code, I am unable to read your mind.
>
> Jim
>
>
> On Fri, Dec 14, 2018 at 4:26 PM Subhamitra Patra <
> subhamitra.patra at gmail.com> wrote:
>
>> Sorry not previous queries, the 3 queries which I mentioned in my last
>> email.
>>
>> On Fri, Dec 14, 2018 at 10:52 AM Subhamitra Patra <
>> subhamitra.patra at gmail.com> wrote:
>>
>>> Dear Sir,
>>>
>>> The method you suggested for arranging multiple plots in 1 pdf page
has
>>> finally worked.
>>>
>>> Thank you very much.
>>>
>>> But, I have 3 more queries as follows.
>>>
>>> 1. Is there any way that I can merge the respective plots from the
>>> different excel files into 1? For instance, I have 3 excel files
(i.e. EMs
>>> 1, EMs 2 and EMs 3) having 4 plots each. I want to merge 1st plots
from 3
>>> excel files into 1, 2nd plots from 3 excel files into 1, similarly
3rd and
>>> 4th plots from each respective files into 1?
>>> 2. Is there any way to range the scale of Y-axis for all plots
because I
>>> think if the range of the Y-axis for each plot is same, it can be
easy to
>>> interpret and compare the results. I used Ylim function. But, after
using
>>> the Ylim function, the plot is looking unclear than before. For
your
>>> convenience, I am providing my code.
>>>
>>> pdf("EMs.pdf",width=20,height=20)
>>> par(mfrow=c(5,4))
>>> # import your first sheet here (38 columns)
>>> ncolumns<-ncol(EMs1)
>>> for(i in 1:ncolumns)
>>> plot(EMs1[,i],type="l",col = "Red",
xlab="Time",
>>> ylab="APEn", ylim=c(0.1,2), main=names(EMs1)[i])
>>> library(zoo)
>>> *APEn=zoo(EMs1, seq(from = as.Date("1994-01-01"), to
>>> as.Date("2017-08-03"), by = 1))*
>>> #import your second sheet here, (10 columns)
>>> ncolumns<-ncol(EMs2)
>>> for(i in 1:ncolumns)
>>> plot(EMs2[,i],type="l",col = "Red",
xlab="Time",
>>> ylab="APEn",ylim=c(0.1,2), main=names(EMs2)[i])
>>> *APEn=zoo(EMs2, seq(from = as.Date("1994-01-01"), to
>>> as.Date("2017-08-03"), by = 1))*
>>> # import your Third sheet here, (2 columns)
>>> ncolumns<-ncol(EMs3)
>>> for(i in 1:ncolumns)
>>> plot(EMs3[,i],type="l",col = "Red",
xlab="Time",
>>> ylab="APEn", ylim=c(0.1,2), main=names(EMs3)[i])
>>> *APEn=zoo(EMs3, seq(from = as.Date("1996-01-01"), to
>>> as.Date("2017-08-03"), by = 1)) *
>>> # finish plotting
>>> dev.off()
>>>
>>> 3. I want the corresponding date column (which is the daily date)
on
>>> X-axis of each plot. Thus, I added 1 line after the plot in the
above (i.e.
>>> the bold line). Please suggest me Is it the correct way that I am
doing?
>>>
>>>
>>> Sir, I am new in R and doing by learning.
>>>
>>> Kindly suggest me regarding my previous queries for which I shall
be
>>> always grateful to you.
>>>
>>> Thank you very much for educating a new R learner.
>>>
>>>
>>>
>>>
>>> On Wed, Nov 21, 2018 at 3:20 PM Subhamitra Patra <
>>> subhamitra.patra at gmail.com> wrote:
>>>
>>>> Thank you very much for your suggestions and help.
>>>>
>>>> [image: Mailtrack]
>>>>
<https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&>
Sender
>>>> notified by
>>>> Mailtrack
>>>>
<https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&>
11/21/18,
>>>> 3:19:55 PM
>>>>
>>>> On Wed, Nov 21, 2018 at 3:09 PM Subhamitra Patra <
>>>> subhamitra.patra at gmail.com> wrote:
>>>>
>>>>> OK, Sir. I will try as per your suggestions.
>>>>>
>>>>> Thank you very much for your kind help.
>>>>>
>>>>> [image: Mailtrack]
>>>>>
<https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&>
Sender
>>>>> notified by
>>>>> Mailtrack
>>>>>
<https://mailtrack.io?utm_source=gmail&utm_medium=signature&utm_campaign=signaturevirality5&>
11/21/18,
>>>>> 3:07:47 PM
>>>>>
>>>>> On Wed, Nov 21, 2018 at 2:41 PM Jim Lemon <drjimlemon at
gmail.com>
>>>>> wrote:
>>>>>
>>>>>> 1. xaxt="n" means "Don't display the
X axis". See the help for "par"
>>>>>> in the graphics package
>>>>>>
>>>>>> 2. axis(1,at=1:nrows,labels=names(MPG3))
>>>>>> This means, "Display the bottom axis (1) with
ticks at 1 to the
>>>>>> number of rows in the data frame"
>>>>>> "Use the values of MPG$Year as labels for the
ticks". see the help
>>>>>> for "axis" in the graphics package
>>>>>> Note that this should be in the same loop as
"plot"
>>>>>>
>>>>>> Now I can see that my guess at the structure of the
data was wrong.
>>>>>> What you could do is to collapse the daily records into
the means for the
>>>>>> years. As I don't know what your spreadsheet looks
like, I could only guess
>>>>>> a method for this.
>>>>>>
>>>>>> You seem to be saying that you plot all 5655 values,
but you want the
>>>>>> axis to show just the years.Rather than tell you to
convert your data to a
>>>>>> time series, I'll suggest a quick hack.
>>>>>>
>>>>>> axis(1,at=seq(1,5655,by=365),labels=1994:2014)
>>>>>>
>>>>>> This _may_ work for you. I offer it because I can see
that you do not
>>>>>> have a lot of experience in R and you want to get the
job done. If you
>>>>>> can't get it to work, I apologize and you can
blamelessly move to something
>>>>>> else.
>>>>>>
>>>>>> Jim
>>>>>>
>>>>>> PS - If you don't know how to start HTML help -
help.start()
>>>>>>
>>>>>> On Wed, Nov 21, 2018 at 7:26 PM Subhamitra Patra <
>>>>>> subhamitra.patra at gmail.com> wrote:
>>>>>>
>>>>>>> Sir, in the bold portion of the below code, I have
some confusion
>>>>>>> which I am mentioning below that
>>>>>>>
>>>>>>>
"ylab="MPG",main=names(MPG3)[i],*xaxt="n"*)
>>>>>>> axis(*1*,at=1:nrows,*labels=MPG3$Year*)"
>>>>>>>
>>>>>>> 1. Here, what *xaxt="n"* indicates? I
think it indicates the no. of
>>>>>>> rows, right?
>>>>>>> 2. 1 in the 2nd line represents the no. of graphs.
Let suppose, 38
>>>>>>> plots are having the same row, I need to mention
them as *axis(38,
>>>>>>> at=1:nrows)*, right?
>>>>>>> 3. *labels=**MPG3$Year *will give the name of all
years in the
>>>>>>> X-axis, right?
>>>>>>>
>>>>>>> Kindly correct me if I am wrong.
>>>>>>>
>>>>>>> Sir, here one thing I would like to ask, my data
frequency is not
>>>>>>> yearly. I obtained results from the daily data of
the period from
>>>>>>> 1994-2017 (that means the no. of rows will be
5655). But, as the daily
>>>>>>> period is very unclear to mention in the X-axis, I
wanted to give year name
>>>>>>> as the name of the X-axis (that means, 1995, 1997,
1999 with the increment
>>>>>>> of 2 years up to 2017).
>>>>>>>
>>>>>>> Sir, please suggest me how to proceed with this?
>>>>>>>
>>>>>>>
>>>>>
>>>>> --
>>>>> *Best Regards,*
>>>>> *Subhamitra Patra*
>>>>> *Phd. Research Scholar*
>>>>> *Department of Humanities and Social Sciences*
>>>>> *Indian Institute of Technology, Kharagpur*
>>>>> *INDIA*
>>>>>
>>>>
>>>>
>>>> --
>>>> *Best Regards,*
>>>> *Subhamitra Patra*
>>>> *Phd. Research Scholar*
>>>> *Department of Humanities and Social Sciences*
>>>> *Indian Institute of Technology, Kharagpur*
>>>> *INDIA*
>>>>
>>>
>>>
>>> --
>>> *Best Regards,*
>>> *Subhamitra Patra*
>>> *Phd. Research Scholar*
>>> *Department of Humanities and Social Sciences*
>>> *Indian Institute of Technology, Kharagpur*
>>> *INDIA*
>>>
>>
>>
>> --
>> *Best Regards,*
>> *Subhamitra Patra*
>> *Phd. Research Scholar*
>> *Department of Humanities and Social Sciences*
>> *Indian Institute of Technology, Kharagpur*
>> *INDIA*
>>
>
--
*Best Regards,*
*Subhamitra Patra*
*Phd. Research Scholar*
*Department of Humanities and Social Sciences*
*Indian Institute of Technology, Kharagpur*
*INDIA*
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