Hi all, I am trying to list all the 4 by 2 tables with some fixed margins. For example, consider 4 by 2 tables with row margins 1,2,2,1 and column margins 3,3. I was able to do it using the code below. However, as seen below, I had to first count the total number of tables with the specific row margins and column margins in order to create space to store the tables. Is there a way to skip the step of counting the number of tables? Also, wanted to avoid for loops as much as possible since it can be extremely slow and inefficient. Thanks so much in advance for you insight and help. Hanna> library(gtools) > A <- permutations(n=4,r=2,v=0:3, repeats.allowed=TRUE) > B <- apply(A, 1, sum) > rmg <- c(1,2,2,1) > cmg <- c(3,3) > m1 <- t(A[which(B==1),]) > m2 <- t(A[which(B==2),]) > m3 <- t(A[which(B==2),]) > > ##count number of tables with row margins 1,2,2,1 and column margins 3,3. > num <- 0 > for (i in 1:ncol(m1)){+ for (j in 1:ncol(m2)){ + for (k in 1:ncol(m3)){ + M <- t(cbind(m1[,i], m2[,j], m3[,k])) + M1 <- rbind(M, cmg-apply(M,2,sum)) + num <- num+(sum(M1[4,] < 0) == 0) + }}}> > > #create space to store the tables > C <- array(NA, dim=c(4,2,num)) > > # list all the tables with fixed margins > num <- 0 > for (i in 1:ncol(m1)){+ for (j in 1:ncol(m2)){ + for (k in 1:ncol(m3)){ + M <- t(cbind(m1[,i], m2[,j], m3[,k])) + M1 <- rbind(M,cmg-apply(M,2,sum)) + if (sum(M1[4,] < 0) == 0) { + num <- num+1 + C[,,num] <- M1 + } + }}}> > C, , 1 [,1] [,2] [1,] 0 1 [2,] 0 2 [3,] 2 0 [4,] 1 0 , , 2 [,1] [,2] [1,] 0 1 [2,] 1 1 [3,] 1 1 [4,] 1 0 , , 3 [,1] [,2] [1,] 0 1 [2,] 1 1 [3,] 2 0 [4,] 0 1 , , 4 [,1] [,2] [1,] 0 1 [2,] 2 0 [3,] 0 2 [4,] 1 0 , , 5 [,1] [,2] [1,] 0 1 [2,] 2 0 [3,] 1 1 [4,] 0 1 , , 6 [,1] [,2] [1,] 1 0 [2,] 0 2 [3,] 1 1 [4,] 1 0 , , 7 [,1] [,2] [1,] 1 0 [2,] 0 2 [3,] 2 0 [4,] 0 1 , , 8 [,1] [,2] [1,] 1 0 [2,] 1 1 [3,] 0 2 [4,] 1 0 , , 9 [,1] [,2] [1,] 1 0 [2,] 1 1 [3,] 1 1 [4,] 0 1 , , 10 [,1] [,2] [1,] 1 0 [2,] 2 0 [3,] 0 2 [4,] 0 1
Don't give up on for loops entirely... some of the largest time savings in optimizing loops are achieved by managing memory effectively. [1] [1] https://www.r-bloggers.com/r-tip-use-vectormode-list-to-pre-allocate-lists On November 8, 2018 8:05:39 PM PST, li li <hannah.hlx at gmail.com> wrote:>Hi all, > I am trying to list all the 4 by 2 tables with some fixed margins. > For example, consider 4 by 2 tables with row margins 1,2,2,1 and >column margins 3,3. I was able to do it using the code below. However, >as seen below, I had to first count the total number of tables with >the specific row margins and column margins in order to create space >to store the tables. >Is there a way to skip the step of counting the number of tables? > Also, wanted to avoid for loops as much as possible since it can be >extremely slow and inefficient. > Thanks so much in advance for you insight and help. > Hanna > > > >> library(gtools) >> A <- permutations(n=4,r=2,v=0:3, repeats.allowed=TRUE) >> B <- apply(A, 1, sum) >> rmg <- c(1,2,2,1) >> cmg <- c(3,3) >> m1 <- t(A[which(B==1),]) >> m2 <- t(A[which(B==2),]) >> m3 <- t(A[which(B==2),]) >> >> ##count number of tables with row margins 1,2,2,1 and column margins >3,3. >> num <- 0 >> for (i in 1:ncol(m1)){ >+ for (j in 1:ncol(m2)){ >+ for (k in 1:ncol(m3)){ >+ M <- t(cbind(m1[,i], m2[,j], m3[,k])) >+ M1 <- rbind(M, cmg-apply(M,2,sum)) >+ num <- num+(sum(M1[4,] < 0) == 0) >+ }}} >> >> >> #create space to store the tables >> C <- array(NA, dim=c(4,2,num)) >> >> # list all the tables with fixed margins >> num <- 0 >> for (i in 1:ncol(m1)){ >+ for (j in 1:ncol(m2)){ >+ for (k in 1:ncol(m3)){ >+ M <- t(cbind(m1[,i], m2[,j], m3[,k])) >+ M1 <- rbind(M,cmg-apply(M,2,sum)) >+ if (sum(M1[4,] < 0) == 0) { >+ num <- num+1 >+ C[,,num] <- M1 >+ } >+ }}} >> >> C >, , 1 > > [,1] [,2] >[1,] 0 1 >[2,] 0 2 >[3,] 2 0 >[4,] 1 0 > >, , 2 > > [,1] [,2] >[1,] 0 1 >[2,] 1 1 >[3,] 1 1 >[4,] 1 0 > >, , 3 > > [,1] [,2] >[1,] 0 1 >[2,] 1 1 >[3,] 2 0 >[4,] 0 1 > >, , 4 > > [,1] [,2] >[1,] 0 1 >[2,] 2 0 >[3,] 0 2 >[4,] 1 0 > >, , 5 > > [,1] [,2] >[1,] 0 1 >[2,] 2 0 >[3,] 1 1 >[4,] 0 1 > >, , 6 > > [,1] [,2] >[1,] 1 0 >[2,] 0 2 >[3,] 1 1 >[4,] 1 0 > >, , 7 > > [,1] [,2] >[1,] 1 0 >[2,] 0 2 >[3,] 2 0 >[4,] 0 1 > >, , 8 > > [,1] [,2] >[1,] 1 0 >[2,] 1 1 >[3,] 0 2 >[4,] 1 0 > >, , 9 > > [,1] [,2] >[1,] 1 0 >[2,] 1 1 >[3,] 1 1 >[4,] 0 1 > >, , 10 > > [,1] [,2] >[1,] 1 0 >[2,] 2 0 >[3,] 0 2 >[4,] 0 1 > >______________________________________________ >R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code.-- Sent from my phone. Please excuse my brevity.
Seems like you are trying to recreate the calculations needed to perform an exact test. Why not look at the code for that or even easier, just use the function. -- David. On 11/8/18 8:05 PM, li li wrote:> Hi all, > I am trying to list all the 4 by 2 tables with some fixed margins. > For example, consider 4 by 2 tables with row margins 1,2,2,1 and > column margins 3,3. I was able to do it using the code below. However, > as seen below, I had to first count the total number of tables with > the specific row margins and column margins in order to create space > to store the tables. > Is there a way to skip the step of counting the number of tables? > Also, wanted to avoid for loops as much as possible since it can be > extremely slow and inefficient. > Thanks so much in advance for you insight and help. > Hanna > > > >> library(gtools) >> A <- permutations(n=4,r=2,v=0:3, repeats.allowed=TRUE) >> B <- apply(A, 1, sum) >> rmg <- c(1,2,2,1) >> cmg <- c(3,3) >> m1 <- t(A[which(B==1),]) >> m2 <- t(A[which(B==2),]) >> m3 <- t(A[which(B==2),]) >> >> ##count number of tables with row margins 1,2,2,1 and column margins 3,3. >> num <- 0 >> for (i in 1:ncol(m1)){ > + for (j in 1:ncol(m2)){ > + for (k in 1:ncol(m3)){ > + M <- t(cbind(m1[,i], m2[,j], m3[,k])) > + M1 <- rbind(M, cmg-apply(M,2,sum)) > + num <- num+(sum(M1[4,] < 0) == 0) > + }}} >> >> #create space to store the tables >> C <- array(NA, dim=c(4,2,num)) >> >> # list all the tables with fixed margins >> num <- 0 >> for (i in 1:ncol(m1)){ > + for (j in 1:ncol(m2)){ > + for (k in 1:ncol(m3)){ > + M <- t(cbind(m1[,i], m2[,j], m3[,k])) > + M1 <- rbind(M,cmg-apply(M,2,sum)) > + if (sum(M1[4,] < 0) == 0) { > + num <- num+1 > + C[,,num] <- M1 > + } > + }}} >> C > , , 1 > > [,1] [,2] > [1,] 0 1 > [2,] 0 2 > [3,] 2 0 > [4,] 1 0 > > , , 2 > > [,1] [,2] > [1,] 0 1 > [2,] 1 1 > [3,] 1 1 > [4,] 1 0 > > , , 3 > > [,1] [,2] > [1,] 0 1 > [2,] 1 1 > [3,] 2 0 > [4,] 0 1 > > , , 4 > > [,1] [,2] > [1,] 0 1 > [2,] 2 0 > [3,] 0 2 > [4,] 1 0 > > , , 5 > > [,1] [,2] > [1,] 0 1 > [2,] 2 0 > [3,] 1 1 > [4,] 0 1 > > , , 6 > > [,1] [,2] > [1,] 1 0 > [2,] 0 2 > [3,] 1 1 > [4,] 1 0 > > , , 7 > > [,1] [,2] > [1,] 1 0 > [2,] 0 2 > [3,] 2 0 > [4,] 0 1 > > , , 8 > > [,1] [,2] > [1,] 1 0 > [2,] 1 1 > [3,] 0 2 > [4,] 1 0 > > , , 9 > > [,1] [,2] > [1,] 1 0 > [2,] 1 1 > [3,] 1 1 > [4,] 0 1 > > , , 10 > > [,1] [,2] > [1,] 1 0 > [2,] 2 0 > [3,] 0 2 > [4,] 0 1 > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.
Yes, exactly (heh, heh). ?fisher.test is probably what is wanted. For arbitrary rxc tables with fixed marginals, this is a difficult problem. Mehta's efficient network algorithm to solve it can be found by a web search on "algorithm for Fisher exact test." -- Bert On Fri, Nov 9, 2018 at 12:36 PM David Winsemius <dwinsemius at comcast.net> wrote:> Seems like you are trying to recreate the calculations needed to perform > an exact test. Why not look at the code for that or even easier, just > use the function. > > -- > > David. > > On 11/8/18 8:05 PM, li li wrote: > > Hi all, > > I am trying to list all the 4 by 2 tables with some fixed margins. > > For example, consider 4 by 2 tables with row margins 1,2,2,1 and > > column margins 3,3. I was able to do it using the code below. However, > > as seen below, I had to first count the total number of tables with > > the specific row margins and column margins in order to create space > > to store the tables. > > Is there a way to skip the step of counting the number of tables? > > Also, wanted to avoid for loops as much as possible since it can be > > extremely slow and inefficient. > > Thanks so much in advance for you insight and help. > > Hanna > > > > > > > >> library(gtools) > >> A <- permutations(n=4,r=2,v=0:3, repeats.allowed=TRUE) > >> B <- apply(A, 1, sum) > >> rmg <- c(1,2,2,1) > >> cmg <- c(3,3) > >> m1 <- t(A[which(B==1),]) > >> m2 <- t(A[which(B==2),]) > >> m3 <- t(A[which(B==2),]) > >> > >> ##count number of tables with row margins 1,2,2,1 and column margins > 3,3. > >> num <- 0 > >> for (i in 1:ncol(m1)){ > > + for (j in 1:ncol(m2)){ > > + for (k in 1:ncol(m3)){ > > + M <- t(cbind(m1[,i], m2[,j], m3[,k])) > > + M1 <- rbind(M, cmg-apply(M,2,sum)) > > + num <- num+(sum(M1[4,] < 0) == 0) > > + }}} > >> > >> #create space to store the tables > >> C <- array(NA, dim=c(4,2,num)) > >> > >> # list all the tables with fixed margins > >> num <- 0 > >> for (i in 1:ncol(m1)){ > > + for (j in 1:ncol(m2)){ > > + for (k in 1:ncol(m3)){ > > + M <- t(cbind(m1[,i], m2[,j], m3[,k])) > > + M1 <- rbind(M,cmg-apply(M,2,sum)) > > + if (sum(M1[4,] < 0) == 0) { > > + num <- num+1 > > + C[,,num] <- M1 > > + } > > + }}} > >> C > > , , 1 > > > > [,1] [,2] > > [1,] 0 1 > > [2,] 0 2 > > [3,] 2 0 > > [4,] 1 0 > > > > , , 2 > > > > [,1] [,2] > > [1,] 0 1 > > [2,] 1 1 > > [3,] 1 1 > > [4,] 1 0 > > > > , , 3 > > > > [,1] [,2] > > [1,] 0 1 > > [2,] 1 1 > > [3,] 2 0 > > [4,] 0 1 > > > > , , 4 > > > > [,1] [,2] > > [1,] 0 1 > > [2,] 2 0 > > [3,] 0 2 > > [4,] 1 0 > > > > , , 5 > > > > [,1] [,2] > > [1,] 0 1 > > [2,] 2 0 > > [3,] 1 1 > > [4,] 0 1 > > > > , , 6 > > > > [,1] [,2] > > [1,] 1 0 > > [2,] 0 2 > > [3,] 1 1 > > [4,] 1 0 > > > > , , 7 > > > > [,1] [,2] > > [1,] 1 0 > > [2,] 0 2 > > [3,] 2 0 > > [4,] 0 1 > > > > , , 8 > > > > [,1] [,2] > > [1,] 1 0 > > [2,] 1 1 > > [3,] 0 2 > > [4,] 1 0 > > > > , , 9 > > > > [,1] [,2] > > [1,] 1 0 > > [2,] 1 1 > > [3,] 1 1 > > [4,] 0 1 > > > > , , 10 > > > > [,1] [,2] > > [1,] 1 0 > > [2,] 2 0 > > [3,] 0 2 > > [4,] 0 1 > > > > ______________________________________________ > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >[[alternative HTML version deleted]]