Dear R Fellows, I Have a dataset( data1) with 2 columns of date showing a class of factor. How to convert them to date? Then compare them, keep the greater date only in a new column. Using as.Date to change the class to Date but the data becomes NA. Much Thanks COL1 COL2 Apr-16 1-Nov-16 May-16 1-Nov-16 Jun-16 1-Nov-16 Jul-16 1-Nov-16 Aug-16 1-Nov-16 Sep-16 1-Nov-16 Oct-16 1-Nov-16 Nov-16 1-Nov-16 Dec-16 1-Nov-16 Jan-17 1-Nov-16 Feb-17 1-Nov-16 Mar-17 1-Nov-16 Apr-17 1-Nov-16 May-17 1-Nov-16 Jun-17 1-Nov-16 Jul-17 1-Nov-16 Aug-17 1-Nov-16 Sep-17 1-Nov-16 [[alternative HTML version deleted]]
On 2017-08-22 1:30 PM, Patrick Casimir wrote:> Dear R Fellows, > > > I Have a dataset( data1) with 2 columns of date showing a class of factor. How to convert them to date? Then compare them, keep the greater date only in a new column. Using as.Date to change the class to Date but the data becomes NA.????? When I specified a format with the second date, I got the desired behavior: > as.Date(factor('1-Nov-16'), '%d-%b-%y') [1] "2016-11-01" > as.Date('Nov-16', '%b-%y') [1] NA > as.Date(factor('Nov-16'), '%b-%y') [1] NA > as.Date('Nov-16', '%b-%y') [1] NA ????? To convert the first column, I pasted "1-" in front: as.Date(paste0('1-', factor('Nov-16')), '%d-%b-%y') ????? Hope this helps.? Spencer> Much Thanks > > > COL1 COL2 > Apr-16 1-Nov-16 > May-16 1-Nov-16 > Jun-16 1-Nov-16 > Jul-16 1-Nov-16 > Aug-16 1-Nov-16 > Sep-16 1-Nov-16 > Oct-16 1-Nov-16 > Nov-16 1-Nov-16 > Dec-16 1-Nov-16 > Jan-17 1-Nov-16 > Feb-17 1-Nov-16 > Mar-17 1-Nov-16 > Apr-17 1-Nov-16 > May-17 1-Nov-16 > Jun-17 1-Nov-16 > Jul-17 1-Nov-16 > Aug-17 1-Nov-16 > Sep-17 1-Nov-16 > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.
This is large data set Spencer. What about when the dates change as below: COL1 COL2 Jan-14 1-Aug-16 Feb-14 1-Aug-16 Mar-14 1-Aug-16 Apr-14 1-Aug-16 May-14 1-Aug-16 Jun-14 1-Aug-16 Jul-14 1-Aug-16 Aug-14 1-Aug-16 Sep-14 1-Aug-16 Oct-14 1-Aug-16 Nov-14 1-Aug-16 Dec-14 1-Aug-16 Jan-15 1-Aug-16 Feb-15 1-Aug-16 Mar-15 1-Aug-16 Apr-15 1-Aug-16 May-15 1-Aug-16 Jun-15 1-Aug-16 Jul-15 1-Aug-16 Aug-15 1-Aug-16 Sep-15 1-Aug-16 Oct-15 1-Aug-16 Nov-15 1-Aug-16 Dec-15 1-Aug-16 Jan-16 1-Aug-16 Feb-16 1-Aug-16 Mar-16 1-Aug-16 Apr-16 1-Aug-16 May-16 1-Aug-16 Jun-16 1-Aug-16 Jul-16 1-Aug-16 Aug-16 1-Aug-16 Sep-16 1-Aug-16 Oct-16 1-Aug-16 ________________________________ From: R-help <r-help-bounces at r-project.org> on behalf of Spencer Graves <spencer.graves at effectivedefense.org> Sent: Tuesday, August 22, 2017 2:49 PM To: r-help at r-project.org Subject: Re: [R] Convert Factor to Date On 2017-08-22 1:30 PM, Patrick Casimir wrote:> Dear R Fellows, > > > I Have a dataset( data1) with 2 columns of date showing a class of factor. How to convert them to date? Then compare them, keep the greater date only in a new column. Using as.Date to change the class to Date but the data becomes NA.When I specified a format with the second date, I got the desired behavior: > as.Date(factor('1-Nov-16'), '%d-%b-%y') [1] "2016-11-01" > as.Date('Nov-16', '%b-%y') [1] NA > as.Date(factor('Nov-16'), '%b-%y') [1] NA > as.Date('Nov-16', '%b-%y') [1] NA To convert the first column, I pasted "1-" in front: as.Date(paste0('1-', factor('Nov-16')), '%d-%b-%y') Hope this helps. Spencer> Much Thanks > > > COL1 COL2 > Apr-16 1-Nov-16 > May-16 1-Nov-16 > Jun-16 1-Nov-16 > Jul-16 1-Nov-16 > Aug-16 1-Nov-16 > Sep-16 1-Nov-16 > Oct-16 1-Nov-16 > Nov-16 1-Nov-16 > Dec-16 1-Nov-16 > Jan-17 1-Nov-16 > Feb-17 1-Nov-16 > Mar-17 1-Nov-16 > Apr-17 1-Nov-16 > May-17 1-Nov-16 > Jun-17 1-Nov-16 > Jul-17 1-Nov-16 > Aug-17 1-Nov-16 > Sep-17 1-Nov-16 > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://na01.safelinks.protection.outlook.com/?url=https%3A%2F%2Fstat.ethz.ch%2Fmailman%2Flistinfo%2Fr-help&data=02%7C01%7Cpatrcasi%40nova.edu%7C6abf3517ab5f407427d308d4e98e9efd%7C2c2b2d312e3e4df1b571fb37c042ff1b%7C0%7C0%7C636390246143633480&sdata=jwTeb%2BvH0bbkXdckgzE6PJZ3gDl9d1%2F3t9K%2BxDtjyls%3D&reserved=0 > PLEASE do read the posting guide https://na01.safelinks.protection.outlook.com/?url=http%3A%2F%2Fwww.R-project.org%2Fposting-guide.html&data=02%7C01%7Cpatrcasi%40nova.edu%7C6abf3517ab5f407427d308d4e98e9efd%7C2c2b2d312e3e4df1b571fb37c042ff1b%7C0%7C0%7C636390246143633480&sdata=GUAR582xxtA88KLkQC1oPnvyNecfUyXjV9MrIziJicU%3D&reserved=0 > and provide commented, minimal, self-contained, reproducible code.______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://na01.safelinks.protection.outlook.com/?url=https%3A%2F%2Fstat.ethz.ch%2Fmailman%2Flistinfo%2Fr-help&data=02%7C01%7Cpatrcasi%40nova.edu%7C6abf3517ab5f407427d308d4e98e9efd%7C2c2b2d312e3e4df1b571fb37c042ff1b%7C0%7C0%7C636390246143633480&sdata=jwTeb%2BvH0bbkXdckgzE6PJZ3gDl9d1%2F3t9K%2BxDtjyls%3D&reserved=0 PLEASE do read the posting guide https://na01.safelinks.protection.outlook.com/?url=http%3A%2F%2Fwww.R-project.org%2Fposting-guide.html&data=02%7C01%7Cpatrcasi%40nova.edu%7C6abf3517ab5f407427d308d4e98e9efd%7C2c2b2d312e3e4df1b571fb37c042ff1b%7C0%7C0%7C636390246143633480&sdata=GUAR582xxtA88KLkQC1oPnvyNecfUyXjV9MrIziJicU%3D&reserved=0 and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]]
Dear R fellows, I created a new column Date_flag to compare the dates of COL1 and COL2 using the code below. But it showed that 5/1/15 is greater than 6/1/2014 and 5/1/2015 greater than 7/1/2014 despite the year is greater. How do I fix that? I did try to format as %y/%m/%d but it does not fix that. data$Date_Flag <- ifelse(data$COL2 > data$COL1, 0,1) COL1 COL2 6/1/14 5/1/15 7/1/14 5/1/15 data$COL2<- as.Date(as.character(data$COL2, format="%y/%m/%d")) data$COL1<- as.Date(as.character(data$COL1, format="%y/%m/%d")) [[alternative HTML version deleted]]
Hi your code is wrong. I get> test<-read.table("clipboard", header=T) > str(test)'data.frame': 2 obs. of 2 variables: $ COL1: Factor w/ 2 levels "6/1/14","7/1/14": 1 2 $ COL2: Factor w/ 1 level "5/1/15": 1 1> test$COL2<- as.Date(as.character(test$COL2, format="%y/%m/%d")) > test$COL1<- as.Date(as.character(test$COL1, format="%y/%m/%d"))^^^^^^^^^^^^^^^^^^^^^^^ incorrect parentheses position, wrong y,m,d Using correct syntax I get correct result.> test$COL2<- as.Date(test$COL2, format="%d/%m/%y") > test$COL1<- as.Date(test$COL1, format="%d/%m/%y") > > test$COL2 > test$COL1[1] TRUE TRUE> testCOL1 COL2 1 2014-01-06 2015-01-05 2 2014-01-07 2015-01-05>Cheers Petr> -----Original Message----- > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Patrick > Casimir > Sent: Wednesday, August 23, 2017 4:54 PM > To: r-help at r-project.org > Subject: [R] Comparing 2 dale columns > > Dear R fellows, > > > I created a new column Date_flag to compare the dates of COL1 and COL2 > using the code below. But it showed that 5/1/15 is greater than 6/1/2014 and > 5/1/2015 greater than > 7/1/2014 despite the year is greater. How do I fix that? I did try to format as > %y/%m/%d > > but it does not fix that. > > > data$Date_Flag <- ifelse(data$COL2 > data$COL1, 0,1) > > > COL1 COL2 > 6/1/14 5/1/15 > 7/1/14 5/1/15 > > > data$COL2<- as.Date(as.character(data$COL2, format="%y/%m/%d")) > data$COL1<- as.Date(as.character(data$COL1, format="%y/%m/%d")) > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.________________________________ Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou ur?eny pouze jeho adres?t?m. Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? neprodlen? jeho odes?latele. Obsah tohoto emailu i s p??lohami a jeho kopie vyma?te ze sv?ho syst?mu. Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat. Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi ?i zpo?d?n?m p?enosu e-mailu. V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?: - vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? smlouvy, a to z jak?hokoliv d?vodu i bez uveden? d?vodu. - a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout; Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce s dodatkem ?i odchylkou. - trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m dosa?en?m shody na v?ech jej?ch n?le?itostech. - odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost ??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn? pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn? osob?, kterou adres?t zastupuje, p?edlo?eny nebo jejich existence je adres?tovi ?i osob? j?m zastoupen? zn?m?. This e-mail and any documents attached to it may be confidential and are intended only for its intended recipients. If you received this e-mail by mistake, please immediately inform its sender. Delete the contents of this e-mail with all attachments and its copies from your system. If you are not the intended recipient of this e-mail, you are not authorized to use, disseminate, copy or disclose this e-mail in any manner. The sender of this e-mail shall not be liable for any possible damage caused by modifications of the e-mail or by delay with transfer of the email. In case that this e-mail forms part of business dealings: - the sender reserves the right to end negotiations about entering into a contract in any time, for any reason, and without stating any reasoning. - if the e-mail contains an offer, the recipient is entitled to immediately accept such offer; The sender of this e-mail (offer) excludes any acceptance of the offer on the part of the recipient containing any amendment or variation. - the sender insists on that the respective contract is concluded only upon an express mutual agreement on all its aspects. - the sender of this e-mail informs that he/she is not authorized to enter into any contracts on behalf of the company except for cases in which he/she is expressly authorized to do so in writing, and such authorization or power of attorney is submitted to the recipient or the person represented by the recipient, or the existence of such authorization is known to the recipient of the person represented by the recipient.
Patrick, ## Run the following script an notice the different values of the dataframe "data" in each instance. # I understand you have done something like the following: data <- data.frame(COL1 = c("6/1/14", "7/1/14"), COL2 = c("5/1/15", "5/1/15"), stringsAsFactors = FALSE) data$Date_Flag <- ifelse(data$COL2 > data$COL1, 0,1) data data$COL2 <- as.Date(as.character(data$COL2, format = "%y/%m/%d")) data$COL1 <- as.Date(as.character(data$COL1, format = "%y/%m/%d")) data$Date_Flag <- ifelse(data$COL2 > data$COL1, 0,1) data # What you may want instead is the following: data <- data.frame(COL1 = c("6/1/14", "7/1/14"), COL2 = c("5/1/15", "5/1/15"), stringsAsFactors = FALSE) data ## strptime() converts the character vector to POSIXct so you do not necessarily ## need the as.Date. However, they are not the same and you may need the Date ## class. data$COL2 <- as.Date(strptime(data$COL2, format = "%m/%d/%y")) data$COL1 <- as.Date(strptime(data$COL1, format = "%m/%d/%y")) data data$Date_Flag <- ifelse(data$COL2 > data$COL1, 0,1) data R. Mark Sharp, Ph.D. msharp at TxBiomed.org> On Aug 23, 2017, at 9:53 AM, Patrick Casimir <patrcasi at nova.edu> wrote: > > data$Date_Flag <- ifelse(data$COL2 > data$COL1, 0,1) > > > COL1 COL2 > 6/1/14 5/1/15 > 7/1/14 5/1/15 > > > data$COL2<- as.Date(as.character(data$COL2, format="%y/%m/%d")) > data$COL1<- as.Date(as.character(data$COL1, format="%y/%m/%d")) >CONFIDENTIALITY NOTICE: This e-mail and any files and/or...{{dropped:10}}