David L Carlson
2017-May-11 21:17 UTC
[R] Error: invalid type (closure) for the variable 'time' - object specific trend
What Rui said, but as important, you have four columns in your data called "town", "year", "revenue", and "supply". You do not have a column called "time". ------------------------------------- David L Carlson Department of Anthropology Texas A&M University College Station, TX 77840-4352 -----Original Message----- From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Rui Barradas Sent: Thursday, May 11, 2017 3:36 PM To: Tobias Christoph <s3tochri at uni-bayreuth.de>; Duncan Murdoch <murdoch.duncan at gmail.com>; r-help at r-project.org Subject: Re: [R] Error: invalid type (closure) for the variable 'time' - object specific trend Hello, A closure is, like you say, a function. At an R prompt try: > typeof(time) [1] "closure" So like Duncan suggested rename 'time', for instance capitalize it 'Time'. That should do it. Hope this helps, Rui Barradas Em 11-05-2017 21:20, Tobias Christoph escreveu:> Hey Duncan, > > thank you very much for your quick reply. > > _My data used:_ > > 1st column(town):1,1,1,1,1,1,1,1,1,1,1,1,2,2,2,...........,11 > > 2nd column(year):1,2,3,4,5,6,7,8,9,10,11,12,1,2,3.......,12 > > 3rd column (revenue): > > 4th colum (supply): > > I have now renamed my colums and did the regression again. Now there is > a problem with R-squared, as it is the sum of 1 now with no given std. > error and t-value. This is probably due to the fact, that I try to > estimate more parameters than data. > > To add a linear trend I found the following formular:*lm(y ~ x1 + > factor(ccode)*time, data=df)* > > I try to I decode it for and use it for my regression: *plm(log(revenue) > ~ log(supply) + factor(town)*time, data=R_Test_log_Neu)* > > When I do this regression I will get the original error: "invalid type > (closure) for the variable 'time' - object specific trend" > > With the notation"time" not my colum is meant, but probably the command > "time" in R. > > Can you follow my thoughts? > > Tobi > > > > > > > Am 11.05.2017 um 17:23 schrieb Duncan Murdoch: >> Duncan Murdoch > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Tobias Christoph
2017-May-12 14:40 UTC
[R] Error: invalid type (closure) for the variable 'time' - object specific trend
Hey guys,
thanks a lot for your tips. The regression is finally running. As you
said, I had to integrate the column "year" in the function
"time" in R.
So I used the following formula: *plm(log(revenue) ~ log(supply) +
factor(town)*time(year), data=R_Test_log_Neu)*
So I have now sucessfully added a linear trend to my regression model?
Another question that concernes me is how to add a quadratic trend
instead of a linear trend. Can I just square the column "year"?
Enjoy your weekend,
Toby
_My results see below:_
Balanced Panel: n=11, T=12, N=132
Residuals :
Min. 1st Qu. Median 3rd Qu. Max.
-0.09610 -0.02370 -0.00152 0.01980 0.14000
Coefficients :
Estimate Std. Error t-value Pr(>|t|)
log(supply) -0.0080702 0.0133675 -0.6037 0.547411
factor(town)2:time(year) -0.0063245 0.0053744 -1.1768 0.242100
factor(town)3:time(year) 0.0295522 0.0056776 5.2050 1.053e-06 ***
factor(town)4:time(year) 0.0062191 0.0054152 1.1485 0.253549
factor(town)5:time(year) 0.0159028 0.0054954 2.8939 0.004681 **
factor(town)6:time(year) 0.0237112 0.0055395 4.2804 4.316e-05 ***
factor(town)7:time(year) 0.0410007 0.0055734 7.3565 5.576e-11 ***
factor(town)8:time(year) 0.0239085 0.0053751 4.4480 2.271e-05 ***
factor(town)9:time(year) 0.0242342 0.0056855 4.2625 4.619e-05 ***
factor(town)10:time(year) 0.0105890 0.0053302 1.9866 0.049733 *
factor(town)11:time(year) 0.0095270 0.0056354 1.6906 0.094065 .
---
Signif. codes: 0 ?***? 0.001 ?**? 0.01 ?*? 0.05 ?.? 0.1 ? ? 1
Total Sum of Squares: 0.46388
Residual Sum of Squares: 0.2001
R-Squared: 0.56863
Adj. R-Squared: 0.4292
F-statistic: 11.8637 on 11 and 99 DF, p-value: 7.3065e-14
Am 11.05.2017 um 23:17 schrieb David L Carlson:> What Rui said, but as important, you have four columns in your data called
"town", "year", "revenue", and "supply".
You do not have a column called "time".
>
> -------------------------------------
> David L Carlson
> Department of Anthropology
> Texas A&M University
> College Station, TX 77840-4352
>
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Rui
Barradas
> Sent: Thursday, May 11, 2017 3:36 PM
> To: Tobias Christoph <s3tochri at uni-bayreuth.de>; Duncan Murdoch
<murdoch.duncan at gmail.com>; r-help at r-project.org
> Subject: Re: [R] Error: invalid type (closure) for the variable
'time' - object specific trend
>
> Hello,
>
> A closure is, like you say, a function.
> At an R prompt try:
>
> > typeof(time)
> [1] "closure"
>
> So like Duncan suggested rename 'time', for instance capitalize it
> 'Time'. That should do it.
>
> Hope this helps,
>
> Rui Barradas
>
>
>
> Em 11-05-2017 21:20, Tobias Christoph escreveu:
>> Hey Duncan,
>>
>> thank you very much for your quick reply.
>>
>> _My data used:_
>>
>> 1st column(town):1,1,1,1,1,1,1,1,1,1,1,1,2,2,2,...........,11
>>
>> 2nd column(year):1,2,3,4,5,6,7,8,9,10,11,12,1,2,3.......,12
>>
>> 3rd column (revenue):
>>
>> 4th colum (supply):
>>
>> I have now renamed my colums and did the regression again. Now there is
>> a problem with R-squared, as it is the sum of 1 now with no given std.
>> error and t-value. This is probably due to the fact, that I try to
>> estimate more parameters than data.
>>
>> To add a linear trend I found the following formular:*lm(y ~ x1 +
>> factor(ccode)*time, data=df)*
>>
>> I try to I decode it for and use it for my regression:
*plm(log(revenue)
>> ~ log(supply) + factor(town)*time, data=R_Test_log_Neu)*
>>
>> When I do this regression I will get the original error: "invalid
type
>> (closure) for the variable 'time' - object specific trend"
>>
>> With the notation"time" not my colum is meant, but probably
the command
>> "time" in R.
>>
>> Can you follow my thoughts?
>>
>> Tobi
>>
>>
>>
>>
>>
>>
>> Am 11.05.2017 um 17:23 schrieb Duncan Murdoch:
>>> Duncan Murdoch
>> ______________________________________________
>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
[[alternative HTML version deleted]]
Rui Barradas
2017-May-12 17:15 UTC
[R] Error: invalid type (closure) for the variable 'time' - object specific trend
Hello, I have never used plm but the standard way of adding a quadratic term is I(time(year)^2) Hope this helps, Rui Barradas Em 12-05-2017 15:40, Tobias Christoph escreveu:> Hey guys, > > thanks a lot for your tips. The regression is finally running. As you > said, I had to integrate the column "year" in the function "time" in R. > > So I used the following formula: *plm(log(revenue) ~ log(supply) + > factor(town)*time(year), data=R_Test_log_Neu)* > > So I have now sucessfully added a linear trend to my regression model? > Another question that concernes me is how to add a quadratic trend > instead of a linear trend. Can I just square the column "year"? > > Enjoy your weekend, > > Toby > > _My results see below:_ > > Balanced Panel: n=11, T=12, N=132 > > Residuals : > Min. 1st Qu. Median 3rd Qu. Max. > -0.09610 -0.02370 -0.00152 0.01980 0.14000 > > Coefficients : > Estimate Std. Error t-value Pr(>|t|) > log(supply) -0.0080702 0.0133675 -0.6037 0.547411 > factor(town)2:time(year) -0.0063245 0.0053744 -1.1768 0.242100 > factor(town)3:time(year) 0.0295522 0.0056776 5.2050 1.053e-06 *** > factor(town)4:time(year) 0.0062191 0.0054152 1.1485 0.253549 > factor(town)5:time(year) 0.0159028 0.0054954 2.8939 0.004681 ** > factor(town)6:time(year) 0.0237112 0.0055395 4.2804 4.316e-05 *** > factor(town)7:time(year) 0.0410007 0.0055734 7.3565 5.576e-11 *** > factor(town)8:time(year) 0.0239085 0.0053751 4.4480 2.271e-05 *** > factor(town)9:time(year) 0.0242342 0.0056855 4.2625 4.619e-05 *** > factor(town)10:time(year) 0.0105890 0.0053302 1.9866 0.049733 * > factor(town)11:time(year) 0.0095270 0.0056354 1.6906 0.094065 . > --- > Signif. codes: 0 ?***? 0.001 ?**? 0.01 ?*? 0.05 ?.? 0.1 ? ? 1 > > Total Sum of Squares: 0.46388 > Residual Sum of Squares: 0.2001 > R-Squared: 0.56863 > Adj. R-Squared: 0.4292 > F-statistic: 11.8637 on 11 and 99 DF, p-value: 7.3065e-14 > > > > Am 11.05.2017 um 23:17 schrieb David L Carlson: >> What Rui said, but as important, you have four columns in your data called "town", "year", "revenue", and "supply". You do not have a column called "time". >> >> ------------------------------------- >> David L Carlson >> Department of Anthropology >> Texas A&M University >> College Station, TX 77840-4352 >> >> -----Original Message----- >> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Rui Barradas >> Sent: Thursday, May 11, 2017 3:36 PM >> To: Tobias Christoph<s3tochri at uni-bayreuth.de>; Duncan Murdoch<murdoch.duncan at gmail.com>;r-help at r-project.org >> Subject: Re: [R] Error: invalid type (closure) for the variable 'time' - object specific trend >> >> Hello, >> >> A closure is, like you say, a function. >> At an R prompt try: >> >> > typeof(time) >> [1] "closure" >> >> So like Duncan suggested rename 'time', for instance capitalize it >> 'Time'. That should do it. >> >> Hope this helps, >> >> Rui Barradas >> >> >> >> Em 11-05-2017 21:20, Tobias Christoph escreveu: >>> Hey Duncan, >>> >>> thank you very much for your quick reply. >>> >>> _My data used:_ >>> >>> 1st column(town):1,1,1,1,1,1,1,1,1,1,1,1,2,2,2,...........,11 >>> >>> 2nd column(year):1,2,3,4,5,6,7,8,9,10,11,12,1,2,3.......,12 >>> >>> 3rd column (revenue): >>> >>> 4th colum (supply): >>> >>> I have now renamed my colums and did the regression again. Now there is >>> a problem with R-squared, as it is the sum of 1 now with no given std. >>> error and t-value. This is probably due to the fact, that I try to >>> estimate more parameters than data. >>> >>> To add a linear trend I found the following formular:*lm(y ~ x1 + >>> factor(ccode)*time, data=df)* >>> >>> I try to I decode it for and use it for my regression: *plm(log(revenue) >>> ~ log(supply) + factor(town)*time, data=R_Test_log_Neu)* >>> >>> When I do this regression I will get the original error: "invalid type >>> (closure) for the variable 'time' - object specific trend" >>> >>> With the notation"time" not my colum is meant, but probably the command >>> "time" in R. >>> >>> Can you follow my thoughts? >>> >>> Tobi >>> >>> >>> >>> >>> >>> >>> Am 11.05.2017 um 17:23 schrieb Duncan Murdoch: >>>> Duncan Murdoch >>> ______________________________________________ >>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >>> https://stat.ethz.ch/mailman/listinfo/r-help >>> PLEASE do read the posting guide >>> http://www.R-project.org/posting-guide.html >>> and provide commented, minimal, self-contained, reproducible code. >> ______________________________________________ >> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guidehttp://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> >
David Winsemius
2017-May-12 20:12 UTC
[R] Error: invalid type (closure) for the variable 'time' - object specific trend
> On May 12, 2017, at 7:40 AM, Tobias Christoph <s3tochri at uni-bayreuth.de> wrote: > > Hey guys, > > thanks a lot for your tips. The regression is finally running. As you > said, I had to integrate the column "year" in the function "time" in R. > > So I used the following formula: *plm(log(revenue) ~ log(supply) + > factor(town)*time(year), data=R_Test_log_Neu)* > > So I have now sucessfully added a linear trend to my regression model? > Another question that concernes me is how to add a quadratic trend > instead of a linear trend. Can I just square the column "year"?It's difficult to respond to these questions. It appears you have either created a function named `time` or loaded a package that contains such a named function. Several of the origianl responders thought it might be a misspelling of an existing column name. One might guess from the output that `time` represents a linear value from a factor-variable across the values of the "year" column. You should probably NOT "just square column 'year'". That will probably construct non-orthogonal dependencies between "time" and "time"^2. The usual method in ordinary linear regression is to use the "poly" function. In your case however the puzzle about what that `time` function looks like prevents much further comment. To support informed discussion on this matter you MUST provide: --- code that includes all the needed library() calls to load packages or to build a time function. --- str(R_Test_log_Neu) -- David> > Enjoy your weekend, > > Toby > > _My results see below:_ > > Balanced Panel: n=11, T=12, N=132 > > Residuals : > Min. 1st Qu. Median 3rd Qu. Max. > -0.09610 -0.02370 -0.00152 0.01980 0.14000 > > Coefficients : > Estimate Std. Error t-value Pr(>|t|) > log(supply) -0.0080702 0.0133675 -0.6037 0.547411 > factor(town)2:time(year) -0.0063245 0.0053744 -1.1768 0.242100 > factor(town)3:time(year) 0.0295522 0.0056776 5.2050 1.053e-06 *** > factor(town)4:time(year) 0.0062191 0.0054152 1.1485 0.253549 > factor(town)5:time(year) 0.0159028 0.0054954 2.8939 0.004681 ** > factor(town)6:time(year) 0.0237112 0.0055395 4.2804 4.316e-05 *** > factor(town)7:time(year) 0.0410007 0.0055734 7.3565 5.576e-11 *** > factor(town)8:time(year) 0.0239085 0.0053751 4.4480 2.271e-05 *** > factor(town)9:time(year) 0.0242342 0.0056855 4.2625 4.619e-05 *** > factor(town)10:time(year) 0.0105890 0.0053302 1.9866 0.049733 * > factor(town)11:time(year) 0.0095270 0.0056354 1.6906 0.094065 . > --- > Signif. codes: 0 ?***? 0.001 ?**? 0.01 ?*? 0.05 ?.? 0.1 ? ? 1 > > Total Sum of Squares: 0.46388 > Residual Sum of Squares: 0.2001 > R-Squared: 0.56863 > Adj. R-Squared: 0.4292 > F-statistic: 11.8637 on 11 and 99 DF, p-value: 7.3065e-14 > > > > Am 11.05.2017 um 23:17 schrieb David L Carlson: >> What Rui said, but as important, you have four columns in your data called "town", "year", "revenue", and "supply". You do not have a column called "time". >> >> ------------------------------------- >> David L Carlson >> Department of Anthropology >> Texas A&M University >> College Station, TX 77840-4352 >> >> -----Original Message----- >> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Rui Barradas >> Sent: Thursday, May 11, 2017 3:36 PM >> To: Tobias Christoph <s3tochri at uni-bayreuth.de>; Duncan Murdoch <murdoch.duncan at gmail.com>; r-help at r-project.org >> Subject: Re: [R] Error: invalid type (closure) for the variable 'time' - object specific trend >> >> Hello, >> >> A closure is, like you say, a function. >> At an R prompt try: >> >>> typeof(time) >> [1] "closure" >> >> So like Duncan suggested rename 'time', for instance capitalize it >> 'Time'. That should do it. >> >> Hope this helps, >> >> Rui Barradas >> >> >> >> Em 11-05-2017 21:20, Tobias Christoph escreveu: >>> Hey Duncan, >>> >>> thank you very much for your quick reply. >>> >>> _My data used:_ >>> >>> 1st column(town):1,1,1,1,1,1,1,1,1,1,1,1,2,2,2,...........,11 >>> >>> 2nd column(year):1,2,3,4,5,6,7,8,9,10,11,12,1,2,3.......,12 >>> >>> 3rd column (revenue): >>> >>> 4th colum (supply): >>> >>> I have now renamed my colums and did the regression again. Now there is >>> a problem with R-squared, as it is the sum of 1 now with no given std. >>> error and t-value. This is probably due to the fact, that I try to >>> estimate more parameters than data. >>> >>> To add a linear trend I found the following formular:*lm(y ~ x1 + >>> factor(ccode)*time, data=df)* >>> >>> I try to I decode it for and use it for my regression: *plm(log(revenue) >>> ~ log(supply) + factor(town)*time, data=R_Test_log_Neu)* >>> >>> When I do this regression I will get the original error: "invalid type >>> (closure) for the variable 'time' - object specific trend" >>> >>> With the notation"time" not my colum is meant, but probably the command >>> "time" in R. >>> >>> Can you follow my thoughts? >>> >>> Tobi >>> >>> >>> >>> >>> >>> >>> Am 11.05.2017 um 17:23 schrieb Duncan Murdoch: >>>> Duncan Murdoch >>> ______________________________________________ >>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >>> https://stat.ethz.ch/mailman/listinfo/r-help >>> PLEASE do read the posting guide >>> http://www.R-project.org/posting-guide.html >>> and provide commented, minimal, self-contained, reproducible code. >> ______________________________________________ >> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.David Winsemius Alameda, CA, USA
peter dalgaard
2017-May-12 21:23 UTC
[R] Error: invalid type (closure) for the variable 'time' - object specific trend
> On 12 May 2017, at 16:40 , Tobias Christoph <s3tochri at uni-bayreuth.de> wrote: > > Hey guys, > > thanks a lot for your tips. The regression is finally running. As you > said, I had to integrate the column "year" in the function "time" in R. > > So I used the following formula: *plm(log(revenue) ~ log(supply) + > factor(town)*time(year), data=R_Test_log_Neu)*Um, that might not do what I think you think it does. time() gives you the "vector of times at which a time series was sampled". If you feed it any regular vector, it just gives the numbers 1:n, witness> time(rnorm(20))[1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 attr(,"tsp") [1] 1 20 1 I suspect you just want "year" in the formula.> > So I have now sucessfully added a linear trend to my regression model? > Another question that concernes me is how to add a quadratic trend > instead of a linear trend. Can I just square the column "year"?In principle, yes, but as others have pointed out, centering the variable may be a good idea, for numerical stability. -pd> > Enjoy your weekend, > > Toby > > _My results see below:_ > > Balanced Panel: n=11, T=12, N=132 > > Residuals : > Min. 1st Qu. Median 3rd Qu. Max. > -0.09610 -0.02370 -0.00152 0.01980 0.14000 > > Coefficients : > Estimate Std. Error t-value Pr(>|t|) > log(supply) -0.0080702 0.0133675 -0.6037 0.547411 > factor(town)2:time(year) -0.0063245 0.0053744 -1.1768 0.242100 > factor(town)3:time(year) 0.0295522 0.0056776 5.2050 1.053e-06 *** > factor(town)4:time(year) 0.0062191 0.0054152 1.1485 0.253549 > factor(town)5:time(year) 0.0159028 0.0054954 2.8939 0.004681 ** > factor(town)6:time(year) 0.0237112 0.0055395 4.2804 4.316e-05 *** > factor(town)7:time(year) 0.0410007 0.0055734 7.3565 5.576e-11 *** > factor(town)8:time(year) 0.0239085 0.0053751 4.4480 2.271e-05 *** > factor(town)9:time(year) 0.0242342 0.0056855 4.2625 4.619e-05 *** > factor(town)10:time(year) 0.0105890 0.0053302 1.9866 0.049733 * > factor(town)11:time(year) 0.0095270 0.0056354 1.6906 0.094065 . > --- > Signif. codes: 0 ?***? 0.001 ?**? 0.01 ?*? 0.05 ?.? 0.1 ? ? 1 > > Total Sum of Squares: 0.46388 > Residual Sum of Squares: 0.2001 > R-Squared: 0.56863 > Adj. R-Squared: 0.4292 > F-statistic: 11.8637 on 11 and 99 DF, p-value: 7.3065e-14 > > > > Am 11.05.2017 um 23:17 schrieb David L Carlson: >> What Rui said, but as important, you have four columns in your data called "town", "year", "revenue", and "supply". You do not have a column called "time". >> >> ------------------------------------- >> David L Carlson >> Department of Anthropology >> Texas A&M University >> College Station, TX 77840-4352 >> >> -----Original Message----- >> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Rui Barradas >> Sent: Thursday, May 11, 2017 3:36 PM >> To: Tobias Christoph <s3tochri at uni-bayreuth.de>; Duncan Murdoch <murdoch.duncan at gmail.com>; r-help at r-project.org >> Subject: Re: [R] Error: invalid type (closure) for the variable 'time' - object specific trend >> >> Hello, >> >> A closure is, like you say, a function. >> At an R prompt try: >> >>> typeof(time) >> [1] "closure" >> >> So like Duncan suggested rename 'time', for instance capitalize it >> 'Time'. That should do it. >> >> Hope this helps, >> >> Rui Barradas >> >> >> >> Em 11-05-2017 21:20, Tobias Christoph escreveu: >>> Hey Duncan, >>> >>> thank you very much for your quick reply. >>> >>> _My data used:_ >>> >>> 1st column(town):1,1,1,1,1,1,1,1,1,1,1,1,2,2,2,...........,11 >>> >>> 2nd column(year):1,2,3,4,5,6,7,8,9,10,11,12,1,2,3.......,12 >>> >>> 3rd column (revenue): >>> >>> 4th colum (supply): >>> >>> I have now renamed my colums and did the regression again. Now there is >>> a problem with R-squared, as it is the sum of 1 now with no given std. >>> error and t-value. This is probably due to the fact, that I try to >>> estimate more parameters than data. >>> >>> To add a linear trend I found the following formular:*lm(y ~ x1 + >>> factor(ccode)*time, data=df)* >>> >>> I try to I decode it for and use it for my regression: *plm(log(revenue) >>> ~ log(supply) + factor(town)*time, data=R_Test_log_Neu)* >>> >>> When I do this regression I will get the original error: "invalid type >>> (closure) for the variable 'time' - object specific trend" >>> >>> With the notation"time" not my colum is meant, but probably the command >>> "time" in R. >>> >>> Can you follow my thoughts? >>> >>> Tobi >>> >>> >>> >>> >>> >>> >>> Am 11.05.2017 um 17:23 schrieb Duncan Murdoch: >>>> Duncan Murdoch >>> ______________________________________________ >>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >>> https://stat.ethz.ch/mailman/listinfo/r-help >>> PLEASE do read the posting guide >>> http://www.R-project.org/posting-guide.html >>> and provide commented, minimal, self-contained, reproducible code. >> ______________________________________________ >> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.-- Peter Dalgaard, Professor, Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 2000 Frederiksberg, Denmark Phone: (+45)38153501 Office: A 4.23 Email: pd.mes at cbs.dk Priv: PDalgd at gmail.com