Hi
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Thomas
> Mailund
> Sent: Tuesday, April 25, 2017 11:20 AM
> To: r-help at r-project.org; Saifuddin, Miah Mohammad
> <miah.mohammadsaifudd at mavs.uta.edu>
> Subject: Re: [R] asking for help
>
> If you write something like
>
> indices <- rep(1:(163863/6069), each = 6069)
You can get similar result by
indices2 <- 0:163862%/%6069
but starting with zero.
or the same with
indices2 <- (0:163862%/%6069)+1
Cheers
Petr
>
> you can get the i?th block of rows with
>
> table[indices == i,]
>
> It looks like a little more work than a loop would be since you have to run
> through all rows for each block, but the implicit loop in this approach is
likely
> to be faster than an explicit for-loop.
>
> Cheers
> ?Thomas
>
> On 25 Apr 2017, 07.01 +0200, Saifuddin, Miah Mohammad
> <miah.mohammadsaifudd at mavs.uta.edu>, wrote:
> I have a data frame having 163863 values. I want to subset it so that each
set
> has 6069 values in it. for example 1:6069 as first, 6070: 6070+6068 as
second.
> how can I do that, preferably in a loop.
>
>
> TIA
>
> [[alternative HTML version deleted]]
>
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> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
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> and provide commented, minimal, self-contained, reproducible code.
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