I have a list of data frames,
ownersList <- list(exp2004owners,exp2005owners,
exp2006owners,exp2007owners,
exp2008owners,exp2009owners,
exp2010owners,exp2011owners,
exp2012owners,exp2013owners,
exp2014owners)
I want to take the mean of the first column $grossIncome.
I can access the first column with
lapply(ownersList, "[[", 1) ##works
But I can't take the mean of that.
mean(lapply(ownersList, "[[", 1)) ##not working
There must be a more idiomatic way to write this with map or apply.
ownersIncome<- c(mean(ownersList[[1]]$grossIncome),
mean(ownersList[[2]]$grossIncome),
mean(ownersList[[3]]$grossIncome),
mean(ownersList[[4]]$grossIncome),
mean(ownersList[[5]]$grossIncome),
mean(ownersList[[6]]$grossIncome),
mean(ownersList[[7]]$grossIncome),
mean(ownersList[[8]]$grossIncome),
mean(ownersList[[9]]$grossIncome),
mean(ownersList[[10]]$grossIncome),
mean(ownersList[[11]]$grossIncome))
I tried a for loop, which also didn't work.
aList<-
for(i in 1:3){
mean(ownersList[[i]]$grossIncome)
}
aList
[[alternative HTML version deleted]]
On 05/02/2017 7:01 AM, Brandon Payne wrote:> I have a list of data frames, > > ownersList <- list(exp2004owners,exp2005owners, > exp2006owners,exp2007owners, > exp2008owners,exp2009owners, > exp2010owners,exp2011owners, > exp2012owners,exp2013owners, > exp2014owners) > > I want to take the mean of the first column $grossIncome. > I can access the first column with > > lapply(ownersList, "[[", 1) ##works > > But I can't take the mean of that. > mean(lapply(ownersList, "[[", 1)) ##not workinglapply returns a list of the first columns, and mean() doesn't know what to do with that.> > There must be a more idiomatic way to write this with map or apply.Yes, take the mean inside lapply: lapply(ownersList, function(x) mean(x[[1]])) Not tested. Duncan Murdoch> > ownersIncome<- c(mean(ownersList[[1]]$grossIncome), > mean(ownersList[[2]]$grossIncome), > mean(ownersList[[3]]$grossIncome), > mean(ownersList[[4]]$grossIncome), > mean(ownersList[[5]]$grossIncome), > mean(ownersList[[6]]$grossIncome), > mean(ownersList[[7]]$grossIncome), > mean(ownersList[[8]]$grossIncome), > mean(ownersList[[9]]$grossIncome), > mean(ownersList[[10]]$grossIncome), > mean(ownersList[[11]]$grossIncome)) > > I tried a for loop, which also didn't work. > > aList<- > for(i in 1:3){ > mean(ownersList[[i]]$grossIncome) > }for loops don't have a useful value: it's always NULL. This would have worked as aList <- list() for(i in 1:3){ aList[[i]] <- mean(ownersList[[i]]$grossIncome) } Duncan Murdoch
Hello,
Try instead the following.
aList<- numeric(3)
for(i in 1:3){
aList[i] <- mean(ownersList[[i]]$grossIncome)
}
aList
Hope this helps,
Rui Barradas
Em 05-02-2017 12:01, Brandon Payne escreveu:> I have a list of data frames,
>
> ownersList <- list(exp2004owners,exp2005owners,
> exp2006owners,exp2007owners,
> exp2008owners,exp2009owners,
> exp2010owners,exp2011owners,
> exp2012owners,exp2013owners,
> exp2014owners)
>
> I want to take the mean of the first column $grossIncome.
> I can access the first column with
>
> lapply(ownersList, "[[", 1) ##works
>
> But I can't take the mean of that.
> mean(lapply(ownersList, "[[", 1)) ##not working
>
> There must be a more idiomatic way to write this with map or apply.
>
> ownersIncome<- c(mean(ownersList[[1]]$grossIncome),
> mean(ownersList[[2]]$grossIncome),
> mean(ownersList[[3]]$grossIncome),
> mean(ownersList[[4]]$grossIncome),
> mean(ownersList[[5]]$grossIncome),
> mean(ownersList[[6]]$grossIncome),
> mean(ownersList[[7]]$grossIncome),
> mean(ownersList[[8]]$grossIncome),
> mean(ownersList[[9]]$grossIncome),
> mean(ownersList[[10]]$grossIncome),
> mean(ownersList[[11]]$grossIncome))
>
> I tried a for loop, which also didn't work.
>
> aList<-
> for(i in 1:3){
> mean(ownersList[[i]]$grossIncome)
> }
> aList
>
> [[alternative HTML version deleted]]
>
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