R help - Feb 2017 - Change (merge) vector by row names.

Hello,

I have a vector of coefficients from backward selection model that looks
like:

             [,1]
(Intercept) -0.15
s1[, 1]      2.65
s1[, 2]      1.81
s1[, 5]      2.35


I'd like to get a new vector that contains zeroes for variables that were
not included in the final model. For example here it suppose to be:

             [,1]
(Intercept) -0.15
s1[, 1]      2.65
s1[, 2]      1.81
s1[, 3]      0
s1[, 4]      0
s1[, 5]      2.35

s1[, 6]      0

s1[, 7]      0

s1[, 8]      0


Is there simple function I can use to get such result?
Regards,
Ariel


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> On 03 Feb 2017, at 21:07 , Art U <art.tem.us at gmail.com> wrote:
> 
> Hello,
> 
> I have a vector of coefficients from backward selection model that looks
> like:
> 
>             [,1]
> (Intercept) -0.15
> s1[, 1]      2.65
> s1[, 2]      1.81
> s1[, 5]      2.35
> 
> 
> I'd like to get a new vector that contains zeroes for variables that
were
> not included in the final model. For example here it suppose to be:
> 
>             [,1]
> (Intercept) -0.15
> s1[, 1]      2.65
> s1[, 2]      1.81
> s1[, 3]      0
> s1[, 4]      0
> s1[, 5]      2.35
> 
> s1[, 6]      0
> 
> s1[, 7]      0
> 
> s1[, 8]      0
> 
> 
> Is there simple function I can use to get such result?
I wouldn't waste time looking for it... It goes something like

fullnames <- ...
extended <- matrix(0,length(fullnames),1)
rownames(extended) <- fullnames
extended[rownames(reduced),] <- reduced

where, presumably, you can find fullnames fromm the fit of a full model.

-pd

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