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PIKAL Petr

2016-Jun-27 09:04 UTC

[R] Antwort: Fw: Re: Subscripting problem with is.na()

Hi

see in line
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of
> G.Maubach at weinwolf.de
> Sent: Monday, June 27, 2016 10:45 AM
> To: David L Carlson <dcarlson at tamu.edu>; Bert Gunter
> <bgunter.4567 at gmail.com>
> Cc: r-help at r-project.org
> Subject: [R] Antwort: Fw: Re: Subscripting problem with is.na()
>
> Hi David,
> Hi Bert,
>
> many thanks for the valuable discussion on NA in R (please see extract
> below). I follow your arguments leaving NA as they are for most of the
> time. In special occasions however I want to replace the NA with another
> value. To preserve the newly acquired knowledge for me I wrote this
> function:
>
> -- cut --
> t_replace_na <- function(dataset, variable, value) {
>  if(inherits(dataset[[variable]], "factor") == TRUE) {
>    dataset[variable] <- as.character(dataset[variable])
>    print(class(dataset[variable]))
>    dataset[, variable][is.na(dataset[, variable])] <- value
>    dataset[variable] <- as.factor(dataset[variable])
>    print(class(dataset[variable]))
>  } else {
>    dataset[, variable][is.na(dataset[, variable])] <- value
>  }
>  return(dataset)
> }
>
<snip>
> class(ds_test[, "c"])
> test_class(ds_test, "c")
> warning("'c' should be factor NOT data.frame.
> In addition data.frame != factor")
> -- cut --
>
> Why do I get different results for the same function if it is inside or
> outside my own function definition?
Because you still are missing the way how to subscript data frames.

test_class <- function(dataset, variable) {
  if(inherits(dataset[, variable], "factor") == TRUE) {
    return(c(class(dataset[,variable]), TRUE))
####                                 ^^^^
} else {
    return(c(class(dataset[,variable]), FALSE))
######                            ^^^^
  }
}
> test_class(ds_test, "a")
[1] "numeric" "FALSE"> test_class(ds_test, "c")
[1] "factor" "TRUE">
If you properly arrange commas in your function you get desired result

p_replace_na <- function(dataset, variable, value) {
 if(inherits(dataset[,variable], "factor") == TRUE) {
   dataset[,variable] <- as.character(dataset[,variable])
   print(class(dataset[,variable]))
   dataset[, variable][is.na(dataset[, variable])] <- value
   dataset[, variable] <- as.factor(dataset[, variable])
   print(class(dataset[, variable]))
 } else {
   dataset[, variable][is.na(dataset[, variable])] <- value
 }
 return(dataset)
}
> p_replace_na(ds_test, "c", value = -3)[1] "character"
[1] "factor"
   a  b  c
1  1 NA  A
2 NA NA  b
3  2 NA -3
> t_replace_na(ds_test, "c", value = -3)[1] "data.frame"
Error in sort.list(y) : 'x' must be atomic for 'sort.list'
Have you called 'sort' on a list?>
Cheers
Petr


>
> Kind regards
>
> Georg
>
> --------------------------------
>
> > Gesendet: Donnerstag, 23. Juni 2016 um 21:14 Uhr
> > Von: "David L Carlson" <dcarlson at tamu.edu>
> > An: "Bert Gunter" <bgunter.4567 at gmail.com>
> > Cc: "R Help" <r-help at r-project.org>
> > Betreff: Re: [R] Subscripting problem with is.na()
> >
> > Good point. I did not think about factors. Also your example raises
> another issue since column c is logical, but gets silently converted to
> numeric. This would seem to get the job done assuming the conversion is
> intended for numeric columns only:
> >
> > > test <- data.frame(a=c(1,NA,2), b =
c("A","b",NA), c= rep(NA,3))
> > > sapply(test, class)
> >         a         b         c
> > "numeric"  "factor" "logical"
> > > num <- sapply(test, is.numeric)
> > > test[, num][is.na(test[, num])] <- 0
> > > test
> >   a    b  c
> > 1 1    A NA
> > 2 0    b NA
> > 3 2 <NA> NA
> >
> > David C
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
________________________________
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- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m
dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost
??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn?
pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn?
osob?, kterou adres?t zastupuje, p?edlo?eny nebo jejich existence je adres?tovi
?i osob? j?m zastoupen? zn?m?.

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G.Maubach at weinwolf.de

2016-Jun-27 11:43 UTC

head link

[R] Antwort: RE: Antwort: Fw: Re: Subscripting problem with is.na()

Hi Petr,

many thanks for your reply and the examples.

My subscripting problems drive me nuts.

I have understood that dataset[variable] is semantically identical to 
dataset[, variable] cause dataset[variable] takes all cases because no 
other subscripts are given.

Where can I lookup the rules when to use the comma and when not?

Kind regards

Georg





Von:    PIKAL Petr <petr.pikal at precheza.cz>
An:     "G.Maubach at weinwolf.de" <G.Maubach at weinwolf.de>, 
Kopie:  "r-help at r-project.org" <r-help at r-project.org>
Datum:  27.06.2016 11:03
Betreff:        RE: [R] Antwort: Fw: Re:  Subscripting problem with 
is.na()



Hi

see in line
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of
> G.Maubach at weinwolf.de
> Sent: Monday, June 27, 2016 10:45 AM
> To: David L Carlson <dcarlson at tamu.edu>; Bert Gunter
> <bgunter.4567 at gmail.com>
> Cc: r-help at r-project.org
> Subject: [R] Antwort: Fw: Re: Subscripting problem with is.na()
>
> Hi David,
> Hi Bert,
>
> many thanks for the valuable discussion on NA in R (please see extract
> below). I follow your arguments leaving NA as they are for most of the
> time. In special occasions however I want to replace the NA with another
> value. To preserve the newly acquired knowledge for me I wrote this
> function:
>
> -- cut --
> t_replace_na <- function(dataset, variable, value) {
>  if(inherits(dataset[[variable]], "factor") == TRUE) {
>    dataset[variable] <- as.character(dataset[variable])
>    print(class(dataset[variable]))
>    dataset[, variable][is.na(dataset[, variable])] <- value
>    dataset[variable] <- as.factor(dataset[variable])
>    print(class(dataset[variable]))
>  } else {
>    dataset[, variable][is.na(dataset[, variable])] <- value
>  }
>  return(dataset)
> }
>
<snip>
> class(ds_test[, "c"])
> test_class(ds_test, "c")
> warning("'c' should be factor NOT data.frame.
> In addition data.frame != factor")
> -- cut --
>
> Why do I get different results for the same function if it is inside or
> outside my own function definition?
Because you still are missing the way how to subscript data frames.

test_class <- function(dataset, variable) {
  if(inherits(dataset[, variable], "factor") == TRUE) {
    return(c(class(dataset[,variable]), TRUE))
####                                 ^^^^
} else {
    return(c(class(dataset[,variable]), FALSE))
######                            ^^^^
  }
}
> test_class(ds_test, "a")
[1] "numeric" "FALSE"> test_class(ds_test, "c")
[1] "factor" "TRUE">
If you properly arrange commas in your function you get desired result

p_replace_na <- function(dataset, variable, value) {
 if(inherits(dataset[,variable], "factor") == TRUE) {
   dataset[,variable] <- as.character(dataset[,variable])
   print(class(dataset[,variable]))
   dataset[, variable][is.na(dataset[, variable])] <- value
   dataset[, variable] <- as.factor(dataset[, variable])
   print(class(dataset[, variable]))
 } else {
   dataset[, variable][is.na(dataset[, variable])] <- value
 }
 return(dataset)
}
> p_replace_na(ds_test, "c", value = -3)[1] "character"
[1] "factor"
   a  b  c
1  1 NA  A
2 NA NA  b
3  2 NA -3
> t_replace_na(ds_test, "c", value = -3)[1] "data.frame"
Error in sort.list(y) : 'x' must be atomic for 'sort.list'
Have you called 'sort' on a list?>
Cheers
Petr


>
> Kind regards
>
> Georg
>
> --------------------------------
>
> > Gesendet: Donnerstag, 23. Juni 2016 um 21:14 Uhr
> > Von: "David L Carlson" <dcarlson at tamu.edu>
> > An: "Bert Gunter" <bgunter.4567 at gmail.com>
> > Cc: "R Help" <r-help at r-project.org>
> > Betreff: Re: [R] Subscripting problem with is.na()
> >
> > Good point. I did not think about factors. Also your example raises
> another issue since column c is logical, but gets silently converted to
> numeric. This would seem to get the job done assuming the conversion is
> intended for numeric columns only:
> >
> > > test <- data.frame(a=c(1,NA,2), b =
c("A","b",NA), c= rep(NA,3))
> > > sapply(test, class)
> >         a         b         c
> > "numeric"  "factor" "logical"
> > > num <- sapply(test, is.numeric)
> > > test[, num][is.na(test[, num])] <- 0
> > > test
> >   a    b  c
> > 1 1    A NA
> > 2 0    b NA
> > 3 2 <NA> NA
> >
> > David C
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
________________________________
Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou 
ur?eny pouze jeho adres?t?m.
Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? 
neprodlen? jeho odes?latele. Obsah tohoto emailu i s p??lohami a jeho 
kopie vyma?te ze sv?ho syst?mu.
Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email 
jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat.
Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi 
?i zpo?d?n?m p?enosu e-mailu.

V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? 
smlouvy, a to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout; 
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany 
p??jemce s dodatkem ?i odchylkou.
- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve 
v?slovn?m dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za 
spole?nost ??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? 
zmocn?n nebo p?semn? pov??en a takov? pov??en? nebo pln? moc byly 
adres?tovi tohoto emailu p??padn? osob?, kterou adres?t zastupuje, 
p?edlo?eny nebo jejich existence je adres?tovi ?i osob? j?m zastoupen? 
zn?m?.

This e-mail and any documents attached to it may be confidential and are 
intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its 
sender. Delete the contents of this e-mail with all attachments and its 
copies from your system.
If you are not the intended recipient of this e-mail, you are not 
authorized to use, disseminate, copy or disclose this e-mail in any 
manner.
The sender of this e-mail shall not be liable for any possible damage 
caused by modifications of the e-mail or by delay with transfer of the 
email.

In case that this e-mail forms part of business dealings:
- the sender reserves the right to end negotiations about entering into a 
contract in any time, for any reason, and without stating any reasoning.
- if the e-mail contains an offer, the recipient is entitled to 
immediately accept such offer; The sender of this e-mail (offer) excludes 
any acceptance of the offer on the part of the recipient containing any 
amendment or variation.
- the sender insists on that the respective contract is concluded only 
upon an express mutual agreement on all its aspects.
- the sender of this e-mail informs that he/she is not authorized to enter
into any contracts on behalf of the company except for cases in which 
he/she is expressly authorized to do so in writing, and such authorization
or power of attorney is submitted to the recipient or the person 
represented by the recipient, or the existence of such authorization is 
known to the recipient of the person represented by the recipient.


	[[alternative HTML version deleted]]

Duncan Murdoch

2016-Jun-27 11:57 UTC

head link

[R] Antwort: RE: Antwort: Fw: Re: Subscripting problem with is.na()

On 27/06/2016 7:43 AM, G.Maubach at weinwolf.de wrote:> Hi Petr,
>
> many thanks for your reply and the examples.
>
> My subscripting problems drive me nuts.
>
> I have understood that dataset[variable] is semantically identical to
> dataset[, variable] cause dataset[variable] takes all cases because no
> other subscripts are given.
>
> Where can I lookup the rules when to use the comma and when not?
I don't think you'll find an explicit list of rules in the R 
documentation.  It does imply the rules, however, by saying that a data 
frame is a list which can be indexed as a matrix.

So if you want to treat your dataset as a list of columns, use single 
component list indexing:  dataset[columnname] to give another list, 
dataset[[columnname]] to extract the column as a vector.

If you want to treat it as a matrix of values, use two indices:

dataset[row, column]

to extract the entry (or entries, if row or column contains more than 
one value).

Duncan Murdoch
>
> Kind regards
>
> Georg
>
>
>
>
>
> Von:    PIKAL Petr <petr.pikal at precheza.cz>
> An:     "G.Maubach at weinwolf.de" <G.Maubach at
weinwolf.de>,
> Kopie:  "r-help at r-project.org" <r-help at r-project.org>
> Datum:  27.06.2016 11:03
> Betreff:        RE: [R] Antwort: Fw: Re:  Subscripting problem with
> is.na()
>
>
>
> Hi
>
> see in line
>
>> -----Original Message-----
>> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of
>> G.Maubach at weinwolf.de
>> Sent: Monday, June 27, 2016 10:45 AM
>> To: David L Carlson <dcarlson at tamu.edu>; Bert Gunter
>> <bgunter.4567 at gmail.com>
>> Cc: r-help at r-project.org
>> Subject: [R] Antwort: Fw: Re: Subscripting problem with is.na()
>>
>> Hi David,
>> Hi Bert,
>>
>> many thanks for the valuable discussion on NA in R (please see extract
>> below). I follow your arguments leaving NA as they are for most of the
>> time. In special occasions however I want to replace the NA with
another
>> value. To preserve the newly acquired knowledge for me I wrote this
>> function:
>>
>> -- cut --
>> t_replace_na <- function(dataset, variable, value) {
>>  if(inherits(dataset[[variable]], "factor") == TRUE) {
>>    dataset[variable] <- as.character(dataset[variable])
>>    print(class(dataset[variable]))
>>    dataset[, variable][is.na(dataset[, variable])] <- value
>>    dataset[variable] <- as.factor(dataset[variable])
>>    print(class(dataset[variable]))
>>  } else {
>>    dataset[, variable][is.na(dataset[, variable])] <- value
>>  }
>>  return(dataset)
>> }
>>
>
> <snip>
>
>> class(ds_test[, "c"])
>> test_class(ds_test, "c")
>> warning("'c' should be factor NOT data.frame.
>> In addition data.frame != factor")
>> -- cut --
>>
>> Why do I get different results for the same function if it is inside or
>> outside my own function definition?
>
> Because you still are missing the way how to subscript data frames.
>
> test_class <- function(dataset, variable) {
>   if(inherits(dataset[, variable], "factor") == TRUE) {
>     return(c(class(dataset[,variable]), TRUE))
> ####                                 ^^^^
> } else {
>     return(c(class(dataset[,variable]), FALSE))
> ######                            ^^^^
>   }
> }
>
>> test_class(ds_test, "a")
> [1] "numeric" "FALSE"
>> test_class(ds_test, "c")
> [1] "factor" "TRUE"
>>
>
> If you properly arrange commas in your function you get desired result
>
> p_replace_na <- function(dataset, variable, value) {
>  if(inherits(dataset[,variable], "factor") == TRUE) {
>    dataset[,variable] <- as.character(dataset[,variable])
>    print(class(dataset[,variable]))
>    dataset[, variable][is.na(dataset[, variable])] <- value
>    dataset[, variable] <- as.factor(dataset[, variable])
>    print(class(dataset[, variable]))
>  } else {
>    dataset[, variable][is.na(dataset[, variable])] <- value
>  }
>  return(dataset)
> }
>
>> p_replace_na(ds_test, "c", value = -3)
> [1] "character"
> [1] "factor"
>    a  b  c
> 1  1 NA  A
> 2 NA NA  b
> 3  2 NA -3
>
>> t_replace_na(ds_test, "c", value = -3)
> [1] "data.frame"
> Error in sort.list(y) : 'x' must be atomic for 'sort.list'
> Have you called 'sort' on a list?
>>
>
> Cheers
> Petr
>
>
>
>>
>> Kind regards
>>
>> Georg
>>
>> --------------------------------
>>
>>> Gesendet: Donnerstag, 23. Juni 2016 um 21:14 Uhr
>>> Von: "David L Carlson" <dcarlson at tamu.edu>
>>> An: "Bert Gunter" <bgunter.4567 at gmail.com>
>>> Cc: "R Help" <r-help at r-project.org>
>>> Betreff: Re: [R] Subscripting problem with is.na()
>>>
>>> Good point. I did not think about factors. Also your example raises
>> another issue since column c is logical, but gets silently converted to
>> numeric. This would seem to get the job done assuming the conversion is
>> intended for numeric columns only:
>>>
>>>> test <- data.frame(a=c(1,NA,2), b =
c("A","b",NA), c= rep(NA,3))
>>>> sapply(test, class)
>>>         a         b         c
>>> "numeric"  "factor" "logical"
>>>> num <- sapply(test, is.numeric)
>>>> test[, num][is.na(test[, num])] <- 0
>>>> test
>>>   a    b  c
>>> 1 1    A NA
>>> 2 0    b NA
>>> 3 2 <NA> NA
>>>
>>> David C
>>
>> ______________________________________________
>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-
>> guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>
> ________________________________
> Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou
> ur?eny pouze jeho adres?t?m.
> Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav?
> neprodlen? jeho odes?latele. Obsah tohoto emailu i s p??lohami a jeho
> kopie vyma?te ze sv?ho syst?mu.
> Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email
> jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat.
> Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi
> ?i zpo?d?n?m p?enosu e-mailu.
>
> V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
> - vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en?
> smlouvy, a to z jak?hokoliv d?vodu i bez uveden? d?vodu.
> - a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
> Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany
> p??jemce s dodatkem ?i odchylkou.
> - trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve
> v?slovn?m dosa?en?m shody na v?ech jej?ch n?le?itostech.
> - odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za
> spole?nost ??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn?
> zmocn?n nebo p?semn? pov??en a takov? pov??en? nebo pln? moc byly
> adres?tovi tohoto emailu p??padn? osob?, kterou adres?t zastupuje,
> p?edlo?eny nebo jejich existence je adres?tovi ?i osob? j?m zastoupen?
> zn?m?.
>
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> ______________________________________________
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> and provide commented, minimal, self-contained, reproducible code.
>

G.Maubach at weinwolf.de

2016-Jun-27 12:52 UTC

head link

[R] Antwort: RE: Antwort: Fw: Re: Subscripting problem with is.na()

Hi All,

Petr, Bert, David, Ivan, Duncan and Rui helped me to develop a function 
able to replace NA's in variables IF NEEDED:

#-------------------------------------------------------------------------------
# Module        : t_replace_na.R
# Author        : Georg Maubach
# Date          : 2016-06-27
# Update        : 2016-06-27
# Description   : Replace NA with another value
# Source System : R 3.3.0 (64 Bit)
# Target System : R 3.3.0 (64 Bit)
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
#--------1---------2---------3---------4---------5---------6---------7---------8

t_version = "2016-06-27"
t_module_name = "t_replace_na.R"

cat(
  paste0("\n",
         t_module_name, " (Version: ", t_version, ")",
"\n", "\n",
         "This software comes with ABSOLUTELY NO WARRANTY.",
         "\n", "\n"))

# If do_test is not defined globally define it here locally by 
un-commenting it
t_do_test <- FALSE

# [ Function Defintion 
]--------------------------------------------------------
t_replace_na <- function(dataset, variables, value) {
  # Replace NA with another given value
  #
  # Args:
  #   dataset (data frame, data table):
  #     Object with dimnames, e.g. data frame, data table.
  #   variables (character vector):
  #     List of variable names.
  #
  # Operation:
  #   NA is replaced by the value given with the parameter "value".
  #
  #   A factor is converted explicitly with as.character(), the missing 
value
  #   replacement is done and then the character vector is converted back 
with
  #   as.factor(). Thus NA becomes a category of the new factor variable.
  #
  # Caution:
  #   Please check your data in case you replace NA within factors due to
  #   explicit type conversion. Tests were done only for the below given
  #   dataset.
  #
  # Returns:
  #   Original dataset.
  #
  # Error handling:
  #   None.
  #
  # Credits: 
https://www.mail-archive.com/r-help at r-project.org/msg236537.html

  for (variable in variables) {
    if (inherits(dataset[, variable], "factor") == TRUE) {
      dataset[, variable] <- as.character(dataset[, variable])
      print(class(dataset[, variable]))
      dataset[, variable][is.na(dataset[, variable])] <- value
      dataset[, variable] <- as.factor(dataset[, variable])
      print(class(dataset[, variable]))
    } else {
      dataset[, variable][is.na(dataset[, variable])] <- value
    }
  }
  return(dataset)
}

# [ Test Defintion 
]------------------------------------------------------------
t_test <- function(do_test = FALSE) {
  if (do_test == TRUE) {
    cat("\n", "\n", "Test function t_count_na()",
"\n", "\n")
 
    # Example dataset
    ds_example <- data.frame(a=c(1,NA,2), b = rep(NA,3), c = 
c("A","b",NA))
 
    cat("\n", "\n", "Example dataset before function
call", "\n", "\n")
    cat("Variables and their classes:\n")
    print(sapply(ds_example, class))
    cat("Dataset:\n")
    print(ds_example)
 
    cat("\n", "\n", "Function call",
"\n", "\n")
    ds_result <- t_replace_na(ds_example, "a", value = -1)
    cat("\n", "\n", "Dataset after function call",
"\n", "\n")
    print(ds_result)
 
    cat("\n", "\n", "Function call",
"\n", "\n")
    ds_result <- t_replace_na(ds_example, "b", value = -2)
    cat("\n", "\n", "Example dataset after function
call", "\n", "\n")
    print(ds_result)

    cat("\n", "\n", "Function call",
"\n", "\n")
    ds_result <- t_replace_na(ds_example, "c", value = -3)
    cat("\n", "\n", "Example dataset after function
call", "\n", "\n")
    print(ds_result) 
  }
}

# [ Test Run 
]------------------------------------------------------------------
t_test(do_test = t_do_test)

# [ Clean up 
]------------------------------------------------------------------
rm("t_module_name", "t_version", "t_do_test",
"t_test")

# EOF .

Please note: R has capabilities to handle NA correctly. There is often no 
need to recode NA. Also NA might or might not have meaning. You have to 
decide with regard to the meaning of the original data and the business 
problem.

Kind regards

Georg




Von:    PIKAL Petr <petr.pikal at precheza.cz>
An:     "G.Maubach at weinwolf.de" <G.Maubach at weinwolf.de>, 
Kopie:  "r-help at r-project.org" <r-help at r-project.org>
Datum:  27.06.2016 11:03
Betreff:        RE: [R] Antwort: Fw: Re:  Subscripting problem with 
is.na()



Hi

see in line
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of
> G.Maubach at weinwolf.de
> Sent: Monday, June 27, 2016 10:45 AM
> To: David L Carlson <dcarlson at tamu.edu>; Bert Gunter
> <bgunter.4567 at gmail.com>
> Cc: r-help at r-project.org
> Subject: [R] Antwort: Fw: Re: Subscripting problem with is.na()
>
> Hi David,
> Hi Bert,
>
> many thanks for the valuable discussion on NA in R (please see extract
> below). I follow your arguments leaving NA as they are for most of the
> time. In special occasions however I want to replace the NA with another
> value. To preserve the newly acquired knowledge for me I wrote this
> function:
>
> -- cut --
> t_replace_na <- function(dataset, variable, value) {
>  if(inherits(dataset[[variable]], "factor") == TRUE) {
>    dataset[variable] <- as.character(dataset[variable])
>    print(class(dataset[variable]))
>    dataset[, variable][is.na(dataset[, variable])] <- value
>    dataset[variable] <- as.factor(dataset[variable])
>    print(class(dataset[variable]))
>  } else {
>    dataset[, variable][is.na(dataset[, variable])] <- value
>  }
>  return(dataset)
> }
>
<snip>
> class(ds_test[, "c"])
> test_class(ds_test, "c")
> warning("'c' should be factor NOT data.frame.
> In addition data.frame != factor")
> -- cut --
>
> Why do I get different results for the same function if it is inside or
> outside my own function definition?
Because you still are missing the way how to subscript data frames.

test_class <- function(dataset, variable) {
  if(inherits(dataset[, variable], "factor") == TRUE) {
    return(c(class(dataset[,variable]), TRUE))
####                                 ^^^^
} else {
    return(c(class(dataset[,variable]), FALSE))
######                            ^^^^
  }
}
> test_class(ds_test, "a")
[1] "numeric" "FALSE"> test_class(ds_test, "c")
[1] "factor" "TRUE">
If you properly arrange commas in your function you get desired result

p_replace_na <- function(dataset, variable, value) {
 if(inherits(dataset[,variable], "factor") == TRUE) {
   dataset[,variable] <- as.character(dataset[,variable])
   print(class(dataset[,variable]))
   dataset[, variable][is.na(dataset[, variable])] <- value
   dataset[, variable] <- as.factor(dataset[, variable])
   print(class(dataset[, variable]))
 } else {
   dataset[, variable][is.na(dataset[, variable])] <- value
 }
 return(dataset)
}
> p_replace_na(ds_test, "c", value = -3)[1] "character"
[1] "factor"
   a  b  c
1  1 NA  A
2 NA NA  b
3  2 NA -3
> t_replace_na(ds_test, "c", value = -3)[1] "data.frame"
Error in sort.list(y) : 'x' must be atomic for 'sort.list'
Have you called 'sort' on a list?>
Cheers
Petr


>
> Kind regards
>
> Georg
>
> --------------------------------
>
> > Gesendet: Donnerstag, 23. Juni 2016 um 21:14 Uhr
> > Von: "David L Carlson" <dcarlson at tamu.edu>
> > An: "Bert Gunter" <bgunter.4567 at gmail.com>
> > Cc: "R Help" <r-help at r-project.org>
> > Betreff: Re: [R] Subscripting problem with is.na()
> >
> > Good point. I did not think about factors. Also your example raises
> another issue since column c is logical, but gets silently converted to
> numeric. This would seem to get the job done assuming the conversion is
> intended for numeric columns only:
> >
> > > test <- data.frame(a=c(1,NA,2), b =
c("A","b",NA), c= rep(NA,3))
> > > sapply(test, class)
> >         a         b         c
> > "numeric"  "factor" "logical"
> > > num <- sapply(test, is.numeric)
> > > test[, num][is.na(test[, num])] <- 0
> > > test
> >   a    b  c
> > 1 1    A NA
> > 2 0    b NA
> > 3 2 <NA> NA
> >
> > David C
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
________________________________
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- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout; 
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany 
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- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za 
spole?nost ??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? 
zmocn?n nebo p?semn? pov??en a takov? pov??en? nebo pln? moc byly 
adres?tovi tohoto emailu p??padn? osob?, kterou adres?t zastupuje, 
p?edlo?eny nebo jejich existence je adres?tovi ?i osob? j?m zastoupen? 
zn?m?.

This e-mail and any documents attached to it may be confidential and are 
intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its 
sender. Delete the contents of this e-mail with all attachments and its 
copies from your system.
If you are not the intended recipient of this e-mail, you are not 
authorized to use, disseminate, copy or disclose this e-mail in any 
manner.
The sender of this e-mail shall not be liable for any possible damage 
caused by modifications of the e-mail or by delay with transfer of the 
email.

In case that this e-mail forms part of business dealings:
- the sender reserves the right to end negotiations about entering into a 
contract in any time, for any reason, and without stating any reasoning.
- if the e-mail contains an offer, the recipient is entitled to 
immediately accept such offer; The sender of this e-mail (offer) excludes 
any acceptance of the offer on the part of the recipient containing any 
amendment or variation.
- the sender insists on that the respective contract is concluded only 
upon an express mutual agreement on all its aspects.
- the sender of this e-mail informs that he/she is not authorized to enter 
into any contracts on behalf of the company except for cases in which 
he/she is expressly authorized to do so in writing, and such authorization 
or power of attorney is submitted to the recipient or the person 
represented by the recipient, or the existence of such authorization is 
known to the recipient of the person represented by the recipient.

PIKAL Petr

2016-Jun-27 14:14 UTC

head link

[R] Antwort: RE: Antwort: Fw: Re: Subscripting problem with is.na()

Hi

On top of what Duncan wrote you can check results yourself
> str(iris[,"Sepal.Length"])num [1:150] 5.1 4.9 4.7 4.6 5 5.4 4.6 5 4.4 4.9 ...

here you get vector and data.frame class is lost. The result is same
as> str(iris$Sepal.Length)num [1:150] 5.1 4.9 4.7 4.6 5 5.4 4.6 5 4.4 4.9 ...

However
> str(iris["Sepal.Length"])'data.frame':   150 obs. of  1 variable:
$ Sepal.Length: num  5.1 4.9 4.7 4.6 5 5.4 4.6 5 4.4 4.9 ...

here the data frame class is preserved.

I subscript rectangular objects (arrays, matricex, data, frames) exclusively by

object[ , , something, ] or in case of data frame object.df[sub, ]

and lists with

object.l[sub] or object.l[[sub]]

so I never had problems with it.

Cheers
Petr


From: G.Maubach at weinwolf.de [mailto:G.Maubach at weinwolf.de]
Sent: Monday, June 27, 2016 1:43 PM
To: PIKAL Petr <petr.pikal at precheza.cz>
Cc: r-help at r-project.org
Subject: Antwort: RE: [R] Antwort: Fw: Re: Subscripting problem with is.na()

Hi Petr,

many thanks for your reply and the examples.

My subscripting problems drive me nuts.

I have understood that dataset[variable] is semantically identical to dataset[,
variable] cause dataset[variable] takes all cases because no other subscripts
are given.

Where can I lookup the rules when to use the comma and when not?

Kind regards

Georg





Von:        PIKAL Petr <petr.pikal at precheza.cz<mailto:petr.pikal at
precheza.cz>>
An:        "G.Maubach at weinwolf.de<mailto:G.Maubach at
weinwolf.de>" <G.Maubach at weinwolf.de<mailto:G.Maubach at
weinwolf.de>>,
Kopie:        "r-help at r-project.org<mailto:r-help at
r-project.org>" <r-help at r-project.org<mailto:r-help at
r-project.org>>
Datum:        27.06.2016 11:03
Betreff:        RE: [R] Antwort: Fw: Re:  Subscripting problem with is.na()
________________________________



Hi

see in line
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of
> G.Maubach at weinwolf.de<mailto:G.Maubach at weinwolf.de>
> Sent: Monday, June 27, 2016 10:45 AM
> To: David L Carlson <dcarlson at tamu.edu<mailto:dcarlson at
tamu.edu>>; Bert Gunter
> <bgunter.4567 at gmail.com<mailto:bgunter.4567 at gmail.com>>
> Cc: r-help at r-project.org<mailto:r-help at r-project.org>
> Subject: [R] Antwort: Fw: Re: Subscripting problem with is.na()
>
> Hi David,
> Hi Bert,
>
> many thanks for the valuable discussion on NA in R (please see extract
> below). I follow your arguments leaving NA as they are for most of the
> time. In special occasions however I want to replace the NA with another
> value. To preserve the newly acquired knowledge for me I wrote this
> function:
>
> -- cut --
> t_replace_na <- function(dataset, variable, value) {
>  if(inherits(dataset[[variable]], "factor") == TRUE) {
>    dataset[variable] <- as.character(dataset[variable])
>    print(class(dataset[variable]))
>    dataset[, variable][is.na(dataset[, variable])] <- value
>    dataset[variable] <- as.factor(dataset[variable])
>    print(class(dataset[variable]))
>  } else {
>    dataset[, variable][is.na(dataset[, variable])] <- value
>  }
>  return(dataset)
> }
>
<snip>
> class(ds_test[, "c"])
> test_class(ds_test, "c")
> warning("'c' should be factor NOT data.frame.
> In addition data.frame != factor")
> -- cut --
>
> Why do I get different results for the same function if it is inside or
> outside my own function definition?
Because you still are missing the way how to subscript data frames.

test_class <- function(dataset, variable) {
 if(inherits(dataset[, variable], "factor") == TRUE) {
   return(c(class(dataset[,variable]), TRUE))
####                                 ^^^^
} else {
   return(c(class(dataset[,variable]), FALSE))
######                            ^^^^
 }
}
> test_class(ds_test, "a")
[1] "numeric" "FALSE"> test_class(ds_test, "c")
[1] "factor" "TRUE">
If you properly arrange commas in your function you get desired result

p_replace_na <- function(dataset, variable, value) {
if(inherits(dataset[,variable], "factor") == TRUE) {
  dataset[,variable] <- as.character(dataset[,variable])
  print(class(dataset[,variable]))
  dataset[, variable][is.na(dataset[, variable])] <- value
  dataset[, variable] <- as.factor(dataset[, variable])
  print(class(dataset[, variable]))
} else {
  dataset[, variable][is.na(dataset[, variable])] <- value
}
return(dataset)
}
> p_replace_na(ds_test, "c", value = -3)[1] "character"
[1] "factor"
  a  b  c
1  1 NA  A
2 NA NA  b
3  2 NA -3
> t_replace_na(ds_test, "c", value = -3)[1] "data.frame"
Error in sort.list(y) : 'x' must be atomic for 'sort.list'
Have you called 'sort' on a list?>
Cheers
Petr


>
> Kind regards
>
> Georg
>
> --------------------------------
>
> > Gesendet: Donnerstag, 23. Juni 2016 um 21:14 Uhr
> > Von: "David L Carlson" <dcarlson at
tamu.edu<mailto:dcarlson at tamu.edu>>
> > An: "Bert Gunter" <bgunter.4567 at
gmail.com<mailto:bgunter.4567 at gmail.com>>
> > Cc: "R Help" <r-help at r-project.org<mailto:r-help at
r-project.org>>
> > Betreff: Re: [R] Subscripting problem with is.na()
> >
> > Good point. I did not think about factors. Also your example raises
> another issue since column c is logical, but gets silently converted to
> numeric. This would seem to get the job done assuming the conversion is
> intended for numeric columns only:
> >
> > > test <- data.frame(a=c(1,NA,2), b =
c("A","b",NA), c= rep(NA,3))
> > > sapply(test, class)
> >         a         b         c
> > "numeric"  "factor" "logical"
> > > num <- sapply(test, is.numeric)
> > > test[, num][is.na(test[, num])] <- 0
> > > test
> >   a    b  c
> > 1 1    A NA
> > 2 0    b NA
> > 3 2 <NA> NA
> >
> > David C
>
> ______________________________________________
> R-help at r-project.org<mailto:R-help at r-project.org> mailing list
-- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-<http://www.r-project.org/posting->
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
________________________________
Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou ur?eny
pouze jeho adres?t?m.
Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? neprodlen? jeho
odes?latele. Obsah tohoto emailu i s p??lohami a jeho kopie vyma?te ze sv?ho
syst?mu.
Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email
jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat.
Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi ?i
zpo?d?n?m p?enosu e-mailu.

V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? smlouvy, a
to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce
s dodatkem ?i odchylkou.
- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m
dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost
??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn?
pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn?
osob?, kterou adres?t zastupuje, p?edlo?eny nebo jejich existence je adres?tovi
?i osob? j?m zastoupen? zn?m?.

This e-mail and any documents attached to it may be confidential and are
intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its sender.
Delete the contents of this e-mail with all attachments and its copies from your
system.
If you are not the intended recipient of this e-mail, you are not authorized to
use, disseminate, copy or disclose this e-mail in any manner.
The sender of this e-mail shall not be liable for any possible damage caused by
modifications of the e-mail or by delay with transfer of the email.

In case that this e-mail forms part of business dealings:
- the sender reserves the right to end negotiations about entering into a
contract in any time, for any reason, and without stating any reasoning.
- if the e-mail contains an offer, the recipient is entitled to immediately
accept such offer; The sender of this e-mail (offer) excludes any acceptance of
the offer on the part of the recipient containing any amendment or variation.
- the sender insists on that the respective contract is concluded only upon an
express mutual agreement on all its aspects.
- the sender of this e-mail informs that he/she is not authorized to enter into
any contracts on behalf of the company except for cases in which he/she is
expressly authorized to do so in writing, and such authorization or power of
attorney is submitted to the recipient or the person represented by the
recipient, or the existence of such authorization is known to the recipient of
the person represented by the recipient.

________________________________
Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou ur?eny
pouze jeho adres?t?m.
Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? neprodlen? jeho
odes?latele. Obsah tohoto emailu i s p??lohami a jeho kopie vyma?te ze sv?ho
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R help - Jun 2016 - Antwort: RE: Antwort: Fw: Re: Subscripting problem with is.na()

[R] Antwort: Fw: Re: Subscripting problem with is.na()

[R] Antwort: RE: Antwort: Fw: Re: Subscripting problem with is.na()

[R] Antwort: RE: Antwort: Fw: Re: Subscripting problem with is.na()

[R] Antwort: RE: Antwort: Fw: Re: Subscripting problem with is.na()

[R] Antwort: RE: Antwort: Fw: Re: Subscripting problem with is.na()