Dear R list users,
sorry for this simple question, but I already spent many efforts to solve it.
I create an empty data frame called df_year like
df_year <- data.frame(day=as.Date(character()), hs_MteBove=integer(),
hs_MtePrata=integer(), hs_Pintura=integer(), hs_Pizzo=integer(),
hs_Sassotetto=integer(), hs_Sibilla=integer(), stringsAsFactors=FALSE)
and then I start to fill in it with
df_year$day <-
seq(as.Date("2004-11-01-00-00","%Y-%m-%d"),
as.Date("2005-05-01-00-00","%Y-%m-%d"), by="day")
but I get the following error:
"replacement has 182 rows, data has 0"
Where is my silly mistake?
Thank you for your help
Stefano
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On 09/06/2016 6:22 AM, Stefano Sofia wrote:> Dear R list users, > sorry for this simple question, but I already spent many efforts to solve it. > > I create an empty data frame called df_year like > > df_year <- data.frame(day=as.Date(character()), hs_MteBove=integer(), hs_MtePrata=integer(), hs_Pintura=integer(), hs_Pizzo=integer(), hs_Sassotetto=integer(), hs_Sibilla=integer(), stringsAsFactors=FALSE) > > and then I start to fill in it with > > df_year$day <- seq(as.Date("2004-11-01-00-00","%Y-%m-%d"), as.Date("2005-05-01-00-00","%Y-%m-%d"), by="day") > > but I get the following error: > "replacement has 182 rows, data has 0" > > Where is my silly mistake?Your dataframe has 0 rows, so you can't put a 182 row vector into the first column. Unlike vectors, dataframes won't grow if you make assignments beyond the end of the rows. There are at least a couple of solutions: 1. Don't create columns until you have data ready for them. You can wait to create the dataframe until your "day" column is ready: df_year <- data.frame(day = seq(...)) As you compute other columns of the same length, you can add them, e.g. df_year$hs_MteBove <- ... 2. Create your columns with the right length from the beginning: df_year <- data.frame(day = rep(as.Date(NA), 182), ...) I don't like this solution as much. Duncan Murdoch
On 09/06/2016 6:22 AM, Stefano Sofia wrote:> Dear R list users, > sorry for this simple question, but I already spent many efforts to solve it. > > I create an empty data frame called df_year like > > df_year <- data.frame(day=as.Date(character()), hs_MteBove=integer(), hs_MtePrata=integer(), hs_Pintura=integer(), hs_Pizzo=integer(), hs_Sassotetto=integer(), hs_Sibilla=integer(), stringsAsFactors=FALSE) > > and then I start to fill in it with > > df_year$day <- seq(as.Date("2004-11-01-00-00","%Y-%m-%d"), as.Date("2005-05-01-00-00","%Y-%m-%d"), by="day") > > but I get the following error: > "replacement has 182 rows, data has 0" > > Where is my silly mistake?Your dataframe has 0 rows, so you can't put a 182 row vector into the first column. Unlike vectors, dataframes won't grow if you make assignments beyond the end of the rows. There are at least a couple of solutions: 1. Don't create columns until you have data ready for them. You can wait to create the dataframe until your "day" column is ready: df_year <- data.frame(day = seq(...)) As you compute other columns of the same length, you can add them, e.g. df_year$hs_MteBove <- ... 2. Create your columns with the right length from the beginning: df_year <- data.frame(day = rep(as.Date(NA), 182), ...) I don't like this solution as much. Duncan Murdoch