R help - Jan 2016 - logical vector of the indices of a string in a vector

Hi,?it might be trivial but is there any way to get the logical vector of the
indices of a string in a vector? I thought that %in% would do but it
doesn't. I also want to filter the empty fields.
Here I want to extract the non-empty elements containing "Yes":x
=c("Yes, fsd", "", "No","","Yes,
fjsdlf", "")
x[c("Yes") %in% x & x != ""]character(0)

Above, I wanted to do the 2 following operations in 1. Here with grep,? it works
but %in% in above doesn't:y = x[grep("Yes",
x)]
> y = y[y != ""]
> y
[1] "Yes, fsd"??? "Yes, fjsdlf"
Thanks
Carol

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Hello,

Try

x[grepl("Yes", x) & x != ""]

Hope this helps,

Rui Barradas

?

Citando carol white via R-help <r-help at r-project.org>:
> Hi,?it might be trivial but is there any way to get the logical  
> vector of the indices of a string in a vector? I thought that %in%  
> would do but it doesn't. I also want to filter the empty fields.
> Here I want to extract the non-empty elements containing "Yes":x
> =c("Yes, fsd", "",
"No","","Yes, fjsdlf", "")
> x[c("Yes") %in% x & x != ""]character(0)
>
> Above, I wanted to do the 2 following operations in 1. Here with  
> grep,? it works but %in% in above doesn't:y = x[grep("Yes",
x)]
>> y = y[y != ""]
>> y
>
> [1] "Yes, fsd"??? "Yes, fjsdlf"
> Thanks
> Carol
>
> ? ? ? ? [[alternative HTML version deleted]]
>
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?

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