Hello!
The following (which is a toy example) works fine, but I wonder if there is
a better or more elegant way than to do the loop:
xz <- vector("list",length=4)
x <- 6:9
for(i in 1:4)xz[[i]] <- x[i]
xz
[[1]]
[1] 6
[[2]]
[1] 7
[[3]]
[1] 8
[[4]]
[1] 9
This does exactly what I want, but the "for" loop seems out of place.
Maybe not.
Thanks,
Sincerely
Erin
--
Erin Hodgess
Associate Professor
Department of Mathematical and Statistics
University of Houston - Downtown
mailto: erinm.hodgess at gmail.com
[[alternative HTML version deleted]]
Dear Erin, How about> x <- 6:9 > as.list(x)[[1]] [1] 6 [[2]] [1] 7 [[3]] [1] 8 [[4]] [1] 9 Best, John ----------------------------- John Fox, Professor McMaster University Hamilton, Ontario Canada L8S 4M4 Web: socserv.mcmaster.ca/jfox> -----Original Message----- > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Erin > Hodgess > Sent: October 26, 2015 9:32 PM > To: R help <r-help at stat.math.ethz.ch> > Subject: [R] Looking for a more elegant solution than a loop > > Hello! > > The following (which is a toy example) works fine, but I wonder if there is a > better or more elegant way than to do the loop: > > xz <- vector("list",length=4) > x <- 6:9 > for(i in 1:4)xz[[i]] <- x[i] > xz > [[1]] > [1] 6 > > [[2]] > [1] 7 > > [[3]] > [1] 8 > > [[4]] > [1] 9 > > This does exactly what I want, but the "for" loop seems out of place. > Maybe not. > > Thanks, > Sincerely > Erin > > > -- > Erin Hodgess > Associate Professor > Department of Mathematical and Statistics University of Houston - > Downtown > mailto: erinm.hodgess at gmail.com > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code.
Beautiful.... Thanks so much! Erin On Mon, Oct 26, 2015 at 8:47 PM, Fox, John <jfox at mcmaster.ca> wrote:> Dear Erin, > > How about > > > x <- 6:9 > > as.list(x) > [[1]] > [1] 6 > > [[2]] > [1] 7 > > [[3]] > [1] 8 > > [[4]] > [1] 9 > > Best, > John > > ----------------------------- > John Fox, Professor > McMaster University > Hamilton, Ontario > Canada L8S 4M4 > Web: socserv.mcmaster.ca/jfox > > > > > -----Original Message----- > > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Erin > > Hodgess > > Sent: October 26, 2015 9:32 PM > > To: R help <r-help at stat.math.ethz.ch> > > Subject: [R] Looking for a more elegant solution than a loop > > > > Hello! > > > > The following (which is a toy example) works fine, but I wonder if there > is a > > better or more elegant way than to do the loop: > > > > xz <- vector("list",length=4) > > x <- 6:9 > > for(i in 1:4)xz[[i]] <- x[i] > > xz > > [[1]] > > [1] 6 > > > > [[2]] > > [1] 7 > > > > [[3]] > > [1] 8 > > > > [[4]] > > [1] 9 > > > > This does exactly what I want, but the "for" loop seems out of place. > > Maybe not. > > > > Thanks, > > Sincerely > > Erin > > > > > > -- > > Erin Hodgess > > Associate Professor > > Department of Mathematical and Statistics University of Houston - > > Downtown > > mailto: erinm.hodgess at gmail.com > > > > [[alternative HTML version deleted]] > > > > ______________________________________________ > > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide http://www.R-project.org/posting- > > guide.html > > and provide commented, minimal, self-contained, reproducible code. >-- Erin Hodgess Associate Professor Department of Mathematical and Statistics University of Houston - Downtown mailto: erinm.hodgess at gmail.com [[alternative HTML version deleted]]
> identical(as.list(x), xz)[1] TRUE Bill Dunlap TIBCO Software wdunlap tibco.com On Mon, Oct 26, 2015 at 6:31 PM, Erin Hodgess <erinm.hodgess at gmail.com> wrote:> Hello! > > The following (which is a toy example) works fine, but I wonder if there is > a better or more elegant way than to do the loop: > > xz <- vector("list",length=4) > x <- 6:9 > for(i in 1:4)xz[[i]] <- x[i] > xz > [[1]] > [1] 6 > > [[2]] > [1] 7 > > [[3]] > [1] 8 > > [[4]] > [1] 9 > > This does exactly what I want, but the "for" loop seems out of place. > Maybe not. > > Thanks, > Sincerely > Erin > > > -- > Erin Hodgess > Associate Professor > Department of Mathematical and Statistics > University of Houston - Downtown > mailto: erinm.hodgess at gmail.com > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.