Dear all
I attached file whose basic structure is
Z:\\AAAAAAA\\BBBBB\\XXXXXX\\CCCCCC\\DDDDD\\....
I would like to select value from first column after let say third
"\\" (but sometimes it can be second or first) and find out all
permissions located in second column regarding this folder.
So far I found this way:
ctvrta<-sapply(strsplit(writelist[,1],"\\", fixed=T),"[",
4)
ctvrta <- addNA(as.factor(ctvrta))
aggregate(writelist[,2], list(ctvrta), function(x) unique(as.character(x)))
structure(list(Group.1 = structure(1:4, .Label = c("Kov??ov?",
"Laborato? stavebn?ch hmot - Vesel?", "Valenta-Vidl?kov?",
NA
), class = "factor"), x = structure(list(`1` =
c("Administrators",
" PRECHEZA\\FA-KU-GLB-RW", " PRECHEZA\\FA-KU-TEC-GLB-RW",
" PRECHEZA\\FA-KU-TEC-VedouciVyzkumu-RW"
), `2` = c("Administrators", " PRECHEZA\\FA-KU-GLB-RW",
" PRECHEZA\\FA-KU-TEC-GLB-RW",
" PRECHEZA\\FA-KU-TEC-VedouciVyzkumu-RW", "
PRECHEZA\\LabSTHM"
), `3` = c("Administrators", " PRECHEZA\\FA-KU-GLB-RW",
" PRECHEZA\\FA-KU-TEC-GLB-RW",
" PRECHEZA\\FA-KU-TEC-VedouciVyzkumu-RW"), `4` =
c("Administrators",
" PRECHEZA\\FA-KU-GLB-RW", " PRECHEZA\\FA-KU-TEC-GLB-RW",
" PRECHEZA\\FA-KU-TEC-VedouciVyzkumu-RW"
)), .Names = c("1", "2", "3", "4"))),
.Names = c("Group.1", "x"
), row.names = c(NA, -4L), class = "data.frame")
If there are same permissions for all folders I could melt resulting data.frame
using reshape2 but if there are different number of permissions, the second
column is list. I basically know how to separate items of those lists using rep,
length and unlist but maybe somebody more capable than myself can come with more
elegant solution.
Best regards
Petr
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