Oops, Bill's reply and mine crossed in the email. His is essentially
the same as mine except probably more efficient.
-- Bert
Bert Gunter
"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
-- Clifford Stoll
On Thu, Jul 23, 2015 at 2:44 PM, William Dunlap <wdunlap at tibco.com>
wrote:> You could do something like the following
> > rowsToShiftLeft <- c(2,4,5) # 4, not the 3 that was in the
original post
> > mat <- as.matrix(df_start)
> > mat[rowsToShiftLeft, 1:3] <- mat[rowsToShiftLeft, 2:4]
> > result <- data.frame(mat[, 1:3], stringsAsFactors=FALSE)
> > str(result)
> 'data.frame': 5 obs. of 3 variables:
> $ v0: chr "a" "b" "c" "d" ...
> $ v1: chr "1" "2" "3" "4" ...
> $ v2: chr "6" "7" "8" "9" ...
> You will then have to convert the columns which ought to be numeric
> to numeric. (All the columns in df_start were factors because of the
> extra xxx that offset some of them.)
>
>
> Bill Dunlap
> TIBCO Software
> wdunlap tibco.com
>
> On Thu, Jul 23, 2015 at 1:19 PM, maxbre <mbressan at arpa.veneto.it>
wrote:
>
>> sorry but honestly I do not get your point
>>
>> I need to shift to left by one position (i.e. one column) the entire
rows
>> 2,4,5 of "df_start" so that to obtain as final result the
structure
>> indicated in "df_end"
>>
>> I know in advance the rows that I need to shift
>>
>> hope it clears a bit, now
>>
>>
>>
>>
>> --
>> View this message in context:
>>
http://r.789695.n4.nabble.com/shift-by-one-column-given-rows-in-a-dataframe-tp4710256p4710276.html
>> Sent from the R help mailing list archive at Nabble.com.
>>
>> ______________________________________________
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>>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
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> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.