Hi
I do not understand. My mind reading ambilities are limited.
Where do you get your vectors from?
Instead of
vec<-vec+3*(i-1)
you can use any computation to create any object.
d<-list()
n=2
for (i in 1:n) {
s<-sample(1:26, 10, replace=FALSE)
rn<-rnorm(10)
y<-rn*s*rnorm(1)+rnorm(1)
fit<-lm(y~s)
d[[i]]<-fit
names(d)[i] <- paste(letters[round(mean(s))],i, sep="")
}
So my opinion is that the code for populating list is pretty general.
Petr
From: carol white [mailto:wht_crl at yahoo.com]
Sent: Friday, June 05, 2015 11:18 AM
To: PIKAL Petr
Subject: Re: [R] building a list in a loop
vectors c(1,2,3) etc were an example. the general case should be considered if
it is a character vector with the unknown elements out of the loop. the same as
the name. your code can't be generalized.
On Friday, June 5, 2015 11:13 AM, PIKAL Petr <petr.pikal at
precheza.cz<mailto:petr.pikal at precheza.cz>> wrote:
Hi
It is not clear what exactly do you want.
d<-list()
vec<-1:3
for (i in 1:2) {
vec<-vec+3*(i-1)
d[[i]]<-vec
#names(d)[i] <- paste("name",i)
}
You can add names in second loop or you can use names command in first loop.
Cheers
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at
r-project.org<mailto:r-help-bounces at r-project.org>] On Behalf Of carol
> white via R-help
> Sent: Friday, June 05, 2015 10:40 AM
> To: R-help Help
> Subject: [R] building a list in a loop
>
> It might be an easy question but how to construct correctly a list in a
> loop?
>
> The following doesn't work
> before starting the loopd = NULL#in the loop, 1st iteration
> d = list(d,c(1,2,3)d[[1]]
> NULL
>
> [[2]]
> [1] 1 2 3#in the loop, 2nd iterationd=list(d,c(4,5,6)d
> [[1]]
> [[1]][[1]]
> NULL
>
> [[1]][[2]]
> [1] 1 2 3
>
>
> [[2]]
> [1] 4 5 6
> the goal is to have the result of d= list(c(1,2,3),c(4,5,6)) where the
> list components are not known out of the loop.
> d[[1]]
> [1] 1 2 3
>
> [[2]]
> [1] 4 5 6
> Moreover, how to name the components of the list in the loop while
> constructing as the names are not known out of the loop, either? note
> that the name of the component is stored in a variable in the loop
>
> d = NULL#name1 contains the name for c(1,2,3), how to give the name
> below?
> d = list(d,c(1,2,3)
> Thanks
>
> [[alternative HTML version deleted]]
>
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