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Joachim Audenaert

2015-Apr-16 11:12 UTC

[R] melt function chooses wrong id variable with large datasets

Hello,

This is a part of my dataset:

structure(list(januari = c(38.1, 32.4, 34.5, 20.7, 21.5, 23.1, 
29.7, 36.6, 36.1, 20.6, 20.4, 30.1, 38.7, 41.4, 37, 36, 37, 38, 
23, 26.7), februari = c(31.5, 36.2, 38.2, 26.4, 20.9, 21.5, 30.2, 
33.4, 32.6, 22.2, 21.7, 30, 35.7, 32.8, 39.3, 25.5, 23, 19.9, 
21.3, 20.8), maart = c(34.2, 27, 24.2, 19.9, 19.7, 21.5, 30.6, 
30, 19, 19.6, 20.6, 23.6, 17.9, 17.3, 21.4, 24.1, 20.9, 30.1, 
32.6, 21.3), april = c(26.3, 29.6, 30.3, 23.6, 28.4, 20.7, 24.1, 
27.3, 23.2, 18.3, 24.6, 27.4, 20.4, 18.1, 25.2, 19.8, 21, 23.7, 
19.6, 18.1), mei = c(23.7, 24, 17.2, 23.2, 25.2, 17.2, 16, 15.6, 
13.4, 16, 16.8, 14.6, 19.4, 21, 19.5, 18.5, 13.3, 13.7, 14.3, 
14.1), juni = c(17.7, 14.2, 16.6, 15.7, 13.7, 14.7, 13.1, 12.9, 
15.4, 11.9, 15.2, 15.3, 16.5, 16.1, 11.7, 11.2, 11.5, 10.8, 16.1, 
14.8), juli = c(15.7, 14.5, 10.8, 10.5, 13.4, 12.2, 13.2, 13, 
12.4, 13.1, 9.8, 10.5, 13.4, 11, 13.1, 15, 16.7, 16.1, 18.2, 
15.7), augustus = c(12.9, 12.8, 15.2, 14.5, 17.2, 14.5, 14.4, 
11, 13.1, 13.6, 14.6, 12.7, 13.6, 12.7, 15.5, 17.4, 15.2, 14.2, 
17.7, 19.2), september = c(15.6, 15.5, 15.9, 15.1, 16, 19.4, 
21.5, 23.7, 18.7, 23.8, 18, 16.2, 18.5, 20.6, 18.3, 22.5, 26.9, 
19.4, 15.9, 20.5), oktober = c(21.4, 20.8, 14, 17, 23, 26.4, 
19.6, 22.7, 26.9, 14.7, 15.2, 19.8, 26.9, 20.2, 14.3, 14.8, 18.5, 
21.7, 21.4, 21.8), november = c(24.7, 26.2, 29, 21.6, 17.1, 16.9, 
19.1, 24.7, 25.4, 19.8, 18.2, 16.3, 17, 17.7, 15.5, 14.7, 15.8, 
19.9, 20.4, 23.3), december = c(19.8, 27, 21, 33, 22.6, 28.3, 
21.1, 19, 17.3, 27, 30.2, 24.8, 17.9, 17.9, 20.7, 30.9, 36.2, 
21, 20.2, 21.3), norm = c("45.8713463281901",
"24.047250681782984",
"3.7533684144746324", "38.594241119279324",
"26.391897460120358",
"61.746470001194638", "6.8321020448487992",
"11.933109250115226",
"51.951891096493924", "37.424611852237945",
"5.1587836676942374",
"36.552835044409434", "31.781209673851027",
"29.09146215582853",
"4.856812959269508", "5.3982910143166514",
"46.553976273304215",
"17.566272518985429", "20.552451905814117",
"61.894775704479279"
)), .Names = c("januari", "februari", "maart",
"april", "mei",
"juni", "juli", "augustus", "september",
"oktober", "november",
"december", "norm"), row.names = c(NA, 20L), class =
"data.frame")

I transform my dataset with the following script:

y <- melt(dataset,na.rm=TRUE)
variable <- y[,1] 
value <- y[,2]

and can then perform a levene test as follows:

LEVENE <- leveneTest(value~variable,y)

When the dataset is small, lets say less than 100 values per column 
everything works great. I get the message: 

No id variables; using all as measure variables

When the dataset is much bigger I get the following message

Using norm as id variables, why does this function pick norm as id 
variable? and how can I tell R that each column title is my variable

 
Met vriendelijke groeten - With kind regards,

Joachim Audenaert 
onderzoeker gewasbescherming - crop protection researcher

PCS | proefcentrum voor sierteelt - ornamental plant research

Schaessestraat 18, 9070 Destelbergen, Belgi?
T: +32 (0)9 353 94 71 | F: +32 (0)9 353 94 95
E: joachim.audenaert at pcsierteelt.be | W: www.pcsierteelt.be 



From:   PIKAL Petr <petr.pikal at precheza.cz>
To:     Joachim Audenaert <Joachim.Audenaert at pcsierteelt.be>, 
"r-help at r-project.org" <r-help at r-project.org>
Date:   16/04/2015 12:13
Subject:        RE: [R]  melt function chooses wrong id variable with 
large datasets



Hi

There is something weird with your data and melt function.

AFAIK melt does not use first row as id.variables.

What is result of

str(dataset)

Instead of

melt(dataset,id.vars=dataset[1,], na.rm=TRUE)

melt expects something like

melt(dataset, id.vars=c("norm, "jaar"), na.rm=TRUE)

If you want more specific answer you shall show us part of your data, 
preferably copy output of

dput(dataset[1:20,])

into your mail.

Cheers
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Joachim
> Audenaert
> Sent: Thursday, April 16, 2015 11:37 AM
> To: r-help at r-project.org
> Subject: [R] melt function chooses wrong id variable with large
> datasets
>
> Hello all,
>
> I'm using a large dataset consisting of 2 groups of data, 2 columns in
> excel with a header (group name) and 15 000 rows of data. I would like
> like to compare this data, so I transform my dataset with the melt
> function to get 1 column of data and 1 column of ID variables, then I
> can apply different statistical tests. With small datasets this works
> great, the melt function automatically chooses the name in row 1 as ID
> variable and melts the data, thus giving me a matrix with all ID
> variables in column one and the data accordingly in column 2.
> With this big dataset however it chooses the whole first column as ID
> variables in stead of the first row. Is there a reason why this happens
> and how can I make sure the first row is chosen as ID variabele and the
> lower rows as data?
>
> If I specify that I want the first row to be the id variable I also get
> error.
>
> melt(dataset,id.vars=dataset[1,], na.rm=TRUE)
>
> Error: id variables not found in data: norm, jaar
>
> Are there alternative ways to create a good reshaped dataset?
>
> Met vriendelijke groeten - With kind regards,
>
> Joachim Audenaert
> onderzoeker gewasbescherming - crop protection researcher
>
> PCS | proefcentrum voor sierteelt - ornamental plant research
>
> Schaessestraat 18, 9070 Destelbergen, Belgi
> T: +32 (0)9 353 94 71 | F: +32 (0)9 353 94 95
> E: joachim.audenaert at pcsierteelt.be | W: www.pcsierteelt.be
>
> Heb je je individuele begeleiding bemesting (CVBB) al aangevraagd? |
> Het PCS op LinkedIn Disclaimer | Please consider the environment before
> printing. Think green, keep it on the screen!
>       [[alternative HTML version deleted]]

________________________________
Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou 
ur?eny pouze jeho adres?t?m.
Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? 
neprodlen? jeho odes?latele. Obsah tohoto emailu i s p??lohami a jeho 
kopie vyma?te ze sv?ho syst?mu.
Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email 
jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat.
Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi 
?i zpo?d?n?m p?enosu e-mailu.

V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? 
smlouvy, a to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout; 
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany 
p??jemce s dodatkem ?i odchylkou.
- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve 
v?slovn?m dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za 
spole?nost ??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? 
zmocn?n nebo p?semn? pov??en a takov? pov??en? nebo pln? moc byly 
adres?tovi tohoto emailu p??padn? osob?, kterou adres?t zastupuje, 
p?edlo?eny nebo jejich existence je adres?tovi ?i osob? j?m zastoupen? 
zn?m?.

This e-mail and any documents attached to it may be confidential and are 
intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its 
sender. Delete the contents of this e-mail with all attachments and its 
copies from your system.
If you are not the intended recipient of this e-mail, you are not 
authorized to use, disseminate, copy or disclose this e-mail in any 
manner.
The sender of this e-mail shall not be liable for any possible damage 
caused by modifications of the e-mail or by delay with transfer of the 
email.

In case that this e-mail forms part of business dealings:
- the sender reserves the right to end negotiations about entering into a 
contract in any time, for any reason, and without stating any reasoning.
- if the e-mail contains an offer, the recipient is entitled to 
immediately accept such offer; The sender of this e-mail (offer) excludes 
any acceptance of the offer on the part of the recipient containing any 
amendment or variation.
- the sender insists on that the respective contract is concluded only 
upon an express mutual agreement on all its aspects.
- the sender of this e-mail informs that he/she is not authorized to enter
into any contracts on behalf of the company except for cases in which 
he/she is expressly authorized to do so in writing, and such authorization
or power of attorney is submitted to the recipient or the person 
represented by the recipient, or the existence of such authorization is 
known to the recipient of the person represented by the recipient.



Heb je je individuele begeleiding bemesting (CVBB) al aangevraagd? | Het 
PCS op LinkedIn
Disclaimer | Please consider the environment before printing. Think green,
keep it on the screen!
	[[alternative HTML version deleted]]

PIKAL Petr

2015-Apr-16 11:41 UTC

head link

[R] melt function chooses wrong id variable with large datasets

Hi

With this dataset I get
> dd.m0<-melt(dataset, na.rm=T)
Using norm as id variables> head(dd.m0)                norm variable value
1   45.8713463281901  januari  38.1
2 24.047250681782984  januari  32.4
3 3.7533684144746324  januari  34.5
4 38.594241119279324  januari  20.7
5 26.391897460120358  januari  21.5
6 61.746470001194638  januari  23.1>or

dd.m<-melt(dataset, id.vars=NULL, na.rm=T)
> head(dd.m)  variable value
1  januari  38.1
2  januari  32.4
3  januari  34.5
4  januari  20.7
5  januari  21.5
6  januari  23.1> tail(dd.m)    variable              value
255     norm  4.856812959269508
256     norm 5.3982910143166514
257     norm 46.553976273304215
258     norm 17.566272518985429
259     norm 20.552451905814117
260     norm 61.894775704479279

The latter will put norm to the same column as months. Is it intended?

Maybe you want
> dd.m1<-melt(dataset[,-13], na.rm=T)
No id variables; using all as measure variables> head(dd.m1)  variable value
1  januari  38.1
2  januari  32.4
3  januari  34.5
4  januari  20.7
5  januari  21.5
6  januari  23.1> tail(dd.m1)    variable value
235 december  20.7
236 december  30.9
237 december  36.2
238 december  21.0
239 december  20.2
240 december  21.3

Cheers
Petr

From: Joachim Audenaert [mailto:Joachim.Audenaert at pcsierteelt.be]
Sent: Thursday, April 16, 2015 1:13 PM
To: PIKAL Petr
Cc: r-help at r-project.org
Subject: RE: [R] melt function chooses wrong id variable with large datasets

Hello,

This is a part of my dataset:

structure(list(januari = c(38.1, 32.4, 34.5, 20.7, 21.5, 23.1,
29.7, 36.6, 36.1, 20.6, 20.4, 30.1, 38.7, 41.4, 37, 36, 37, 38,
23, 26.7), februari = c(31.5, 36.2, 38.2, 26.4, 20.9, 21.5, 30.2,
33.4, 32.6, 22.2, 21.7, 30, 35.7, 32.8, 39.3, 25.5, 23, 19.9,
21.3, 20.8), maart = c(34.2, 27, 24.2, 19.9, 19.7, 21.5, 30.6,
30, 19, 19.6, 20.6, 23.6, 17.9, 17.3, 21.4, 24.1, 20.9, 30.1,
32.6, 21.3), april = c(26.3, 29.6, 30.3, 23.6, 28.4, 20.7, 24.1,
27.3, 23.2, 18.3, 24.6, 27.4, 20.4, 18.1, 25.2, 19.8, 21, 23.7,
19.6, 18.1), mei = c(23.7, 24, 17.2, 23.2, 25.2, 17.2, 16, 15.6,
13.4, 16, 16.8, 14.6, 19.4, 21, 19.5, 18.5, 13.3, 13.7, 14.3,
14.1), juni = c(17.7, 14.2, 16.6, 15.7, 13.7, 14.7, 13.1, 12.9,
15.4, 11.9, 15.2, 15.3, 16.5, 16.1, 11.7, 11.2, 11.5, 10.8, 16.1,
14.8), juli = c(15.7, 14.5, 10.8, 10.5, 13.4, 12.2, 13.2, 13,
12.4, 13.1, 9.8, 10.5, 13.4, 11, 13.1, 15, 16.7, 16.1, 18.2,
15.7), augustus = c(12.9, 12.8, 15.2, 14.5, 17.2, 14.5, 14.4,
11, 13.1, 13.6, 14.6, 12.7, 13.6, 12.7, 15.5, 17.4, 15.2, 14.2,
17.7, 19.2), september = c(15.6, 15.5, 15.9, 15.1, 16, 19.4,
21.5, 23.7, 18.7, 23.8, 18, 16.2, 18.5, 20.6, 18.3, 22.5, 26.9,
19.4, 15.9, 20.5), oktober = c(21.4, 20.8, 14, 17, 23, 26.4,
19.6, 22.7, 26.9, 14.7, 15.2, 19.8, 26.9, 20.2, 14.3, 14.8, 18.5,
21.7, 21.4, 21.8), november = c(24.7, 26.2, 29, 21.6, 17.1, 16.9,
19.1, 24.7, 25.4, 19.8, 18.2, 16.3, 17, 17.7, 15.5, 14.7, 15.8,
19.9, 20.4, 23.3), december = c(19.8, 27, 21, 33, 22.6, 28.3,
21.1, 19, 17.3, 27, 30.2, 24.8, 17.9, 17.9, 20.7, 30.9, 36.2,
21, 20.2, 21.3), norm = c("45.8713463281901",
"24.047250681782984",
"3.7533684144746324", "38.594241119279324",
"26.391897460120358",
"61.746470001194638", "6.8321020448487992",
"11.933109250115226",
"51.951891096493924", "37.424611852237945",
"5.1587836676942374",
"36.552835044409434", "31.781209673851027",
"29.09146215582853",
"4.856812959269508", "5.3982910143166514",
"46.553976273304215",
"17.566272518985429", "20.552451905814117",
"61.894775704479279"
)), .Names = c("januari", "februari", "maart",
"april", "mei",
"juni", "juli", "augustus", "september",
"oktober", "november",
"december", "norm"), row.names = c(NA, 20L), class =
"data.frame")

I transform my dataset with the following script:

y <- melt(dataset,na.rm=TRUE)
variable <- y[,1]
value <- y[,2]

and can then perform a levene test as follows:

LEVENE <- leveneTest(value~variable,y)

When the dataset is small, lets say less than 100 values per column everything
works great. I get the message:

No id variables; using all as measure variables

When the dataset is much bigger I get the following message

Using norm as id variables, why does this function pick norm as id variable? and
how can I tell R that each column title is my variable


Met vriendelijke groeten - With kind regards,

Joachim Audenaert
onderzoeker gewasbescherming - crop protection researcher

PCS | proefcentrum voor sierteelt - ornamental plant research
________________________________

Schaessestraat 18, 9070 Destelbergen, Belgi?
T: +32 (0)9 353 94 71 | F: +32 (0)9 353 94 95
E: joachim.audenaert at pcsierteelt.be<mailto:joachim.audenaert at
pcsierteelt.be> | W: www.pcsierteelt.be<http://www.pcsierteelt.be/>



From:        PIKAL Petr <petr.pikal at precheza.cz<mailto:petr.pikal at
precheza.cz>>
To:        Joachim Audenaert <Joachim.Audenaert at
pcsierteelt.be<mailto:Joachim.Audenaert at pcsierteelt.be>>,
"r-help at r-project.org<mailto:r-help at r-project.org>"
<r-help at r-project.org<mailto:r-help at r-project.org>>
Date:        16/04/2015 12:13
Subject:        RE: [R]  melt function chooses wrong id variable with large
datasets
________________________________



Hi

There is something weird with your data and melt function.

AFAIK melt does not use first row as id.variables.

What is result of

str(dataset)

Instead of

melt(dataset,id.vars=dataset[1,], na.rm=TRUE)

melt expects something like

melt(dataset, id.vars=c("norm, "jaar"), na.rm=TRUE)

If you want more specific answer you shall show us part of your data, preferably
copy output of

dput(dataset[1:20,])

into your mail.

Cheers
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Joachim
> Audenaert
> Sent: Thursday, April 16, 2015 11:37 AM
> To: r-help at r-project.org<mailto:r-help at r-project.org>
> Subject: [R] melt function chooses wrong id variable with large
> datasets
>
> Hello all,
>
> I'm using a large dataset consisting of 2 groups of data, 2 columns in
> excel with a header (group name) and 15 000 rows of data. I would like
> like to compare this data, so I transform my dataset with the melt
> function to get 1 column of data and 1 column of ID variables, then I
> can apply different statistical tests. With small datasets this works
> great, the melt function automatically chooses the name in row 1 as ID
> variable and melts the data, thus giving me a matrix with all ID
> variables in column one and the data accordingly in column 2.
> With this big dataset however it chooses the whole first column as ID
> variables in stead of the first row. Is there a reason why this happens
> and how can I make sure the first row is chosen as ID variabele and the
> lower rows as data?
>
> If I specify that I want the first row to be the id variable I also get
> error.
>
> melt(dataset,id.vars=dataset[1,], na.rm=TRUE)
>
> Error: id variables not found in data: norm, jaar
>
> Are there alternative ways to create a good reshaped dataset?
>
> Met vriendelijke groeten - With kind regards,
>
> Joachim Audenaert
> onderzoeker gewasbescherming - crop protection researcher
>
> PCS | proefcentrum voor sierteelt - ornamental plant research
>
> Schaessestraat 18, 9070 Destelbergen, Belgi
> T: +32 (0)9 353 94 71 | F: +32 (0)9 353 94 95
> E: joachim.audenaert at pcsierteelt.be<mailto:joachim.audenaert at
pcsierteelt.be> | W: www.pcsierteelt.be
>
> Heb je je individuele begeleiding bemesting (CVBB) al aangevraagd? |
> Het PCS op LinkedIn Disclaimer | Please consider the environment before
> printing. Think green, keep it on the screen!
>       [[alternative HTML version deleted]]

________________________________
Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou ur?eny
pouze jeho adres?t?m.
Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? neprodlen? jeho
odes?latele. Obsah tohoto emailu i s p??lohami a jeho kopie vyma?te ze sv?ho
syst?mu.
Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email
jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat.
Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi ?i
zpo?d?n?m p?enosu e-mailu.

V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? smlouvy, a
to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce
s dodatkem ?i odchylkou.
- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m
dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost
??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn?
pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn?
osob?, kterou adres?t zastupuje, p?edlo?eny nebo jejich existence je adres?tovi
?i osob? j?m zastoupen? zn?m?.

This e-mail and any documents attached to it may be confidential and are
intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its sender.
Delete the contents of this e-mail with all attachments and its copies from your
system.
If you are not the intended recipient of this e-mail, you are not authorized to
use, disseminate, copy or disclose this e-mail in any manner.
The sender of this e-mail shall not be liable for any possible damage caused by
modifications of the e-mail or by delay with transfer of the email.

In case that this e-mail forms part of business dealings:
- the sender reserves the right to end negotiations about entering into a
contract in any time, for any reason, and without stating any reasoning.
- if the e-mail contains an offer, the recipient is entitled to immediately
accept such offer; The sender of this e-mail (offer) excludes any acceptance of
the offer on the part of the recipient containing any amendment or variation.
- the sender insists on that the respective contract is concluded only upon an
express mutual agreement on all its aspects.
- the sender of this e-mail informs that he/she is not authorized to enter into
any contracts on behalf of the company except for cases in which he/she is
expressly authorized to do so in writing, and such authorization or power of
attorney is submitted to the recipient or the person represented by the
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	[[alternative HTML version deleted]]

Joachim Audenaert

2015-Apr-16 11:59 UTC

head link

[R] melt function chooses wrong id variable with large datasets

Thanks,

indeed norm should be in the same group as as the months. everything works 
fine when the number of data is quite small, but with big datasets (15 000 
values) things seem to go wrong and I can't explain why. It puts norm as 
an individual column in stead of in the group of months as it does when 
the dataset is small.

Met vriendelijke groeten - With kind regards,

Joachim Audenaert 
onderzoeker gewasbescherming - crop protection researcher

PCS | proefcentrum voor sierteelt - ornamental plant research

Schaessestraat 18, 9070 Destelbergen, Belgi?
T: +32 (0)9 353 94 71 | F: +32 (0)9 353 94 95
E: joachim.audenaert at pcsierteelt.be | W: www.pcsierteelt.be 



From:   PIKAL Petr <petr.pikal at precheza.cz>
To:     Joachim Audenaert <Joachim.Audenaert at pcsierteelt.be>
Cc:     "r-help at r-project.org" <r-help at r-project.org>
Date:   16/04/2015 13:41
Subject:        RE: [R]  melt function chooses wrong id variable with 
large datasets



Hi
 
With this dataset I get
 > dd.m0<-melt(dataset, na.rm=T)
Using norm as id variables> head(dd.m0)                norm variable value
1   45.8713463281901  januari  38.1
2 24.047250681782984  januari  32.4
3 3.7533684144746324  januari  34.5
4 38.594241119279324  januari  20.7
5 26.391897460120358  januari  21.5
6 61.746470001194638  januari  23.1> or
 
dd.m<-melt(dataset, id.vars=NULL, na.rm=T)
 > head(dd.m)  variable value
1  januari  38.1
2  januari  32.4
3  januari  34.5
4  januari  20.7
5  januari  21.5
6  januari  23.1> tail(dd.m)    variable              value
255     norm  4.856812959269508
256     norm 5.3982910143166514
257     norm 46.553976273304215
258     norm 17.566272518985429
259     norm 20.552451905814117
260     norm 61.894775704479279
 
The latter will put norm to the same column as months. Is it intended?
 
Maybe you want
 > dd.m1<-melt(dataset[,-13], na.rm=T)
No id variables; using all as measure variables> head(dd.m1)  variable value
1  januari  38.1
2  januari  32.4
3  januari  34.5
4  januari  20.7
5  januari  21.5
6  januari  23.1> tail(dd.m1)    variable value
235 december  20.7
236 december  30.9
237 december  36.2
238 december  21.0
239 december  20.2
240 december  21.3
 
Cheers
Petr
 
From: Joachim Audenaert [mailto:Joachim.Audenaert at pcsierteelt.be] 
Sent: Thursday, April 16, 2015 1:13 PM
To: PIKAL Petr
Cc: r-help at r-project.org
Subject: RE: [R] melt function chooses wrong id variable with large 
datasets
 
Hello, 

This is a part of my dataset: 

structure(list(januari = c(38.1, 32.4, 34.5, 20.7, 21.5, 23.1, 
29.7, 36.6, 36.1, 20.6, 20.4, 30.1, 38.7, 41.4, 37, 36, 37, 38, 
23, 26.7), februari = c(31.5, 36.2, 38.2, 26.4, 20.9, 21.5, 30.2, 
33.4, 32.6, 22.2, 21.7, 30, 35.7, 32.8, 39.3, 25.5, 23, 19.9, 
21.3, 20.8), maart = c(34.2, 27, 24.2, 19.9, 19.7, 21.5, 30.6, 
30, 19, 19.6, 20.6, 23.6, 17.9, 17.3, 21.4, 24.1, 20.9, 30.1, 
32.6, 21.3), april = c(26.3, 29.6, 30.3, 23.6, 28.4, 20.7, 24.1, 
27.3, 23.2, 18.3, 24.6, 27.4, 20.4, 18.1, 25.2, 19.8, 21, 23.7, 
19.6, 18.1), mei = c(23.7, 24, 17.2, 23.2, 25.2, 17.2, 16, 15.6, 
13.4, 16, 16.8, 14.6, 19.4, 21, 19.5, 18.5, 13.3, 13.7, 14.3, 
14.1), juni = c(17.7, 14.2, 16.6, 15.7, 13.7, 14.7, 13.1, 12.9, 
15.4, 11.9, 15.2, 15.3, 16.5, 16.1, 11.7, 11.2, 11.5, 10.8, 16.1, 
14.8), juli = c(15.7, 14.5, 10.8, 10.5, 13.4, 12.2, 13.2, 13, 
12.4, 13.1, 9.8, 10.5, 13.4, 11, 13.1, 15, 16.7, 16.1, 18.2, 
15.7), augustus = c(12.9, 12.8, 15.2, 14.5, 17.2, 14.5, 14.4, 
11, 13.1, 13.6, 14.6, 12.7, 13.6, 12.7, 15.5, 17.4, 15.2, 14.2, 
17.7, 19.2), september = c(15.6, 15.5, 15.9, 15.1, 16, 19.4, 
21.5, 23.7, 18.7, 23.8, 18, 16.2, 18.5, 20.6, 18.3, 22.5, 26.9, 
19.4, 15.9, 20.5), oktober = c(21.4, 20.8, 14, 17, 23, 26.4, 
19.6, 22.7, 26.9, 14.7, 15.2, 19.8, 26.9, 20.2, 14.3, 14.8, 18.5, 
21.7, 21.4, 21.8), november = c(24.7, 26.2, 29, 21.6, 17.1, 16.9, 
19.1, 24.7, 25.4, 19.8, 18.2, 16.3, 17, 17.7, 15.5, 14.7, 15.8, 
19.9, 20.4, 23.3), december = c(19.8, 27, 21, 33, 22.6, 28.3, 
21.1, 19, 17.3, 27, 30.2, 24.8, 17.9, 17.9, 20.7, 30.9, 36.2, 
21, 20.2, 21.3), norm = c("45.8713463281901",
"24.047250681782984",
"3.7533684144746324", "38.594241119279324",
"26.391897460120358",
"61.746470001194638", "6.8321020448487992",
"11.933109250115226",
"51.951891096493924", "37.424611852237945",
"5.1587836676942374",
"36.552835044409434", "31.781209673851027",
"29.09146215582853",
"4.856812959269508", "5.3982910143166514",
"46.553976273304215",
"17.566272518985429", "20.552451905814117",
"61.894775704479279"
)), .Names = c("januari", "februari", "maart",
"april", "mei",
"juni", "juli", "augustus", "september",
"oktober", "november",
"december", "norm"), row.names = c(NA, 20L), class =
"data.frame")

I transform my dataset with the following script: 

y <- melt(dataset,na.rm=TRUE) 
variable <- y[,1] 
value <- y[,2] 

and can then perform a levene test as follows: 

LEVENE <- leveneTest(value~variable,y) 

When the dataset is small, lets say less than 100 values per column 
everything works great. I get the message: 

No id variables; using all as measure variables 

When the dataset is much bigger I get the following message 

Using norm as id variables, why does this function pick norm as id 
variable? and how can I tell R that each column title is my variable 

  
Met vriendelijke groeten - With kind regards, 

Joachim Audenaert 
onderzoeker gewasbescherming - crop protection researcher

PCS | proefcentrum voor sierteelt - ornamental plant research 


Schaessestraat 18, 9070 Destelbergen, Belgi?
T: +32 (0)9 353 94 71 | F: +32 (0)9 353 94 95
E: joachim.audenaert at pcsierteelt.be | W: www.pcsierteelt.be 



From:        PIKAL Petr <petr.pikal at precheza.cz> 
To:        Joachim Audenaert <Joachim.Audenaert at pcsierteelt.be>, "
r-help at r-project.org" <r-help at r-project.org> 
Date:        16/04/2015 12:13 
Subject:        RE: [R]  melt function chooses wrong id variable with 
large datasets 




Hi

There is something weird with your data and melt function.

AFAIK melt does not use first row as id.variables.

What is result of

str(dataset)

Instead of

melt(dataset,id.vars=dataset[1,], na.rm=TRUE)

melt expects something like

melt(dataset, id.vars=c("norm, "jaar"), na.rm=TRUE)

If you want more specific answer you shall show us part of your data, 
preferably copy output of

dput(dataset[1:20,])

into your mail.

Cheers
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Joachim
> Audenaert
> Sent: Thursday, April 16, 2015 11:37 AM
> To: r-help at r-project.org
> Subject: [R] melt function chooses wrong id variable with large
> datasets
>
> Hello all,
>
> I'm using a large dataset consisting of 2 groups of data, 2 columns in
> excel with a header (group name) and 15 000 rows of data. I would like
> like to compare this data, so I transform my dataset with the melt
> function to get 1 column of data and 1 column of ID variables, then I
> can apply different statistical tests. With small datasets this works
> great, the melt function automatically chooses the name in row 1 as ID
> variable and melts the data, thus giving me a matrix with all ID
> variables in column one and the data accordingly in column 2.
> With this big dataset however it chooses the whole first column as ID
> variables in stead of the first row. Is there a reason why this happens
> and how can I make sure the first row is chosen as ID variabele and the
> lower rows as data?
>
> If I specify that I want the first row to be the id variable I also get
> error.
>
> melt(dataset,id.vars=dataset[1,], na.rm=TRUE)
>
> Error: id variables not found in data: norm, jaar
>
> Are there alternative ways to create a good reshaped dataset?
>
> Met vriendelijke groeten - With kind regards,
>
> Joachim Audenaert
> onderzoeker gewasbescherming - crop protection researcher
>
> PCS | proefcentrum voor sierteelt - ornamental plant research
>
> Schaessestraat 18, 9070 Destelbergen, Belgi
> T: +32 (0)9 353 94 71 | F: +32 (0)9 353 94 95
> E: joachim.audenaert at pcsierteelt.be | W: www.pcsierteelt.be
>
> Heb je je individuele begeleiding bemesting (CVBB) al aangevraagd? |
> Het PCS op LinkedIn Disclaimer | Please consider the environment before
> printing. Think green, keep it on the screen!
>       [[alternative HTML version deleted]]

________________________________
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?i zpo?d?n?m p?enosu e-mailu.

V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? 
smlouvy, a to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout; 
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany 
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v?slovn?m dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za 
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zmocn?n nebo p?semn? pov??en a takov? pov??en? nebo pln? moc byly 
adres?tovi tohoto emailu p??padn? osob?, kterou adres?t zastupuje, 
p?edlo?eny nebo jejich existence je adres?tovi ?i osob? j?m zastoupen? 
zn?m?.

This e-mail and any documents attached to it may be confidential and are 
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If you received this e-mail by mistake, please immediately inform its 
sender. Delete the contents of this e-mail with all attachments and its 
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If you are not the intended recipient of this e-mail, you are not 
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The sender of this e-mail shall not be liable for any possible damage 
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known to the recipient of the person represented by the recipient.



Heb je je individuele begeleiding bemesting (CVBB) al aangevraagd? | Het 
PCS op LinkedIn
Disclaimer | Please consider the environment before printing. Think green,
keep it on the screen!

Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou 
ur?eny pouze jeho adres?t?m.
Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? 
neprodlen? jeho odes?latele. Obsah tohoto emailu i s p??lohami a jeho 
kopie vyma?te ze sv?ho syst?mu.
Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email 
jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat.
Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi 
?i zpo?d?n?m p?enosu e-mailu.

V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? 
smlouvy, a to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout; 
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany 
p??jemce s dodatkem ?i odchylkou.
- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve 
v?slovn?m dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za 
spole?nost ??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? 
zmocn?n nebo p?semn? pov??en a takov? pov??en? nebo pln? moc byly 
adres?tovi tohoto emailu p??padn? osob?, kterou adres?t zastupuje, 
p?edlo?eny nebo jejich existence je adres?tovi ?i osob? j?m zastoupen? 
zn?m?.

This e-mail and any documents attached to it may be confidential and are 
intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its 
sender. Delete the contents of this e-mail with all attachments and its 
copies from your system.
If you are not the intended recipient of this e-mail, you are not 
authorized to use, disseminate, copy or disclose this e-mail in any 
manner.
The sender of this e-mail shall not be liable for any possible damage 
caused by modifications of the e-mail or by delay with transfer of the 
email.

In case that this e-mail forms part of business dealings:
- the sender reserves the right to end negotiations about entering into a 
contract in any time, for any reason, and without stating any reasoning.
- if the e-mail contains an offer, the recipient is entitled to 
immediately accept such offer; The sender of this e-mail (offer) excludes 
any acceptance of the offer on the part of the recipient containing any 
amendment or variation.
- the sender insists on that the respective contract is concluded only 
upon an express mutual agreement on all its aspects.
- the sender of this e-mail informs that he/she is not authorized to enter
into any contracts on behalf of the company except for cases in which 
he/she is expressly authorized to do so in writing, and such authorization
or power of attorney is submitted to the recipient or the person 
represented by the recipient, or the existence of such authorization is 
known to the recipient of the person represented by the recipient.


Heb je je individuele begeleiding bemesting (CVBB) al aangevraagd? | Het 
PCS op LinkedIn
Disclaimer | Please consider the environment before printing. Think green,
keep it on the screen!
	[[alternative HTML version deleted]]

PIKAL Petr

2015-Apr-17 09:07 UTC

head link

[R] melt function chooses wrong id variable with large datasets

Yes

It could be. But anyway, if you wanted to melt your frame and be sure to have
norm column added to months column you shall use

melt(dataset, id.vars=NULL, na.rm=TRUE)

construction.

Without it and considering data you sent I get
> head(dd.m0)                norm variable value
1   45.8713463281901  januari  38.1
2 24.047250681782984  januari  32.4
3 3.7533684144746324  januari  34.5
4 38.594241119279324  januari  20.7
5 26.391897460120358  januari  21.5
6 61.746470001194638  januari  23.1
...
without this id.vars=NULL parameter.

Cheers
Petr

PS. Keep your post to Rhelp - others may learn from it and anothers can provide
you with more elaborated explanation.


From: Joachim Audenaert [mailto:Joachim.Audenaert at pcsierteelt.be]
Sent: Friday, April 17, 2015 8:23 AM
To: PIKAL Petr
Subject: RE: [R] melt function chooses wrong id variable with large datasets

Hello,

I upgraded R tot version 3.1.3 and now everything in the script works perfectly.
Could the troubles be due to the fact that I was running an older version?

Met vriendelijke groeten - With kind regards,

Joachim Audenaert
onderzoeker gewasbescherming - crop protection researcher

PCS | proefcentrum voor sierteelt - ornamental plant research
________________________________

Schaessestraat 18, 9070 Destelbergen, Belgi?
T: +32 (0)9 353 94 71 | F: +32 (0)9 353 94 95
E: joachim.audenaert at pcsierteelt.be<mailto:joachim.audenaert at
pcsierteelt.be> | W: www.pcsierteelt.be<http://www.pcsierteelt.be/>



From:        PIKAL Petr <petr.pikal at precheza.cz<mailto:petr.pikal at
precheza.cz>>
To:        Joachim Audenaert <Joachim.Audenaert at
pcsierteelt.be<mailto:Joachim.Audenaert at pcsierteelt.be>>
Cc:        "r-help at r-project.org<mailto:r-help at
r-project.org>" <r-help at r-project.org<mailto:r-help at
r-project.org>>
Date:        16/04/2015 13:41
Subject:        RE: [R]  melt function chooses wrong id variable with large
datasets
________________________________



Hi

With this dataset I get
> dd.m0<-melt(dataset, na.rm=T)
Using norm as id variables> head(dd.m0)                norm variable value
1   45.8713463281901  januari  38.1
2 24.047250681782984  januari  32.4
3 3.7533684144746324  januari  34.5
4 38.594241119279324  januari  20.7
5 26.391897460120358  januari  21.5
6 61.746470001194638  januari  23.1>or

dd.m<-melt(dataset, id.vars=NULL, na.rm=T)
> head(dd.m)  variable value
1  januari  38.1
2  januari  32.4
3  januari  34.5
4  januari  20.7
5  januari  21.5
6  januari  23.1> tail(dd.m)    variable              value
255     norm  4.856812959269508
256     norm 5.3982910143166514
257     norm 46.553976273304215
258     norm 17.566272518985429
259     norm 20.552451905814117
260     norm 61.894775704479279

The latter will put norm to the same column as months. Is it intended?

Maybe you want
> dd.m1<-melt(dataset[,-13], na.rm=T)
No id variables; using all as measure variables> head(dd.m1)  variable value
1  januari  38.1
2  januari  32.4
3  januari  34.5
4  januari  20.7
5  januari  21.5
6  januari  23.1> tail(dd.m1)    variable value
235 december  20.7
236 december  30.9
237 december  36.2
238 december  21.0
239 december  20.2
240 december  21.3

Cheers
Petr

From: Joachim Audenaert [mailto:Joachim.Audenaert at pcsierteelt.be]
Sent: Thursday, April 16, 2015 1:13 PM
To: PIKAL Petr
Cc: r-help at r-project.org<mailto:r-help at r-project.org>
Subject: RE: [R] melt function chooses wrong id variable with large datasets

Hello,

This is a part of my dataset:

structure(list(januari = c(38.1, 32.4, 34.5, 20.7, 21.5, 23.1,
29.7, 36.6, 36.1, 20.6, 20.4, 30.1, 38.7, 41.4, 37, 36, 37, 38,
23, 26.7), februari = c(31.5, 36.2, 38.2, 26.4, 20.9, 21.5, 30.2,
33.4, 32.6, 22.2, 21.7, 30, 35.7, 32.8, 39.3, 25.5, 23, 19.9,
21.3, 20.8), maart = c(34.2, 27, 24.2, 19.9, 19.7, 21.5, 30.6,
30, 19, 19.6, 20.6, 23.6, 17.9, 17.3, 21.4, 24.1, 20.9, 30.1,
32.6, 21.3), april = c(26.3, 29.6, 30.3, 23.6, 28.4, 20.7, 24.1,
27.3, 23.2, 18.3, 24.6, 27.4, 20.4, 18.1, 25.2, 19.8, 21, 23.7,
19.6, 18.1), mei = c(23.7, 24, 17.2, 23.2, 25.2, 17.2, 16, 15.6,
13.4, 16, 16.8, 14.6, 19.4, 21, 19.5, 18.5, 13.3, 13.7, 14.3,
14.1), juni = c(17.7, 14.2, 16.6, 15.7, 13.7, 14.7, 13.1, 12.9,
15.4, 11.9, 15.2, 15.3, 16.5, 16.1, 11.7, 11.2, 11.5, 10.8, 16.1,
14.8), juli = c(15.7, 14.5, 10.8, 10.5, 13.4, 12.2, 13.2, 13,
12.4, 13.1, 9.8, 10.5, 13.4, 11, 13.1, 15, 16.7, 16.1, 18.2,
15.7), augustus = c(12.9, 12.8, 15.2, 14.5, 17.2, 14.5, 14.4,
11, 13.1, 13.6, 14.6, 12.7, 13.6, 12.7, 15.5, 17.4, 15.2, 14.2,
17.7, 19.2), september = c(15.6, 15.5, 15.9, 15.1, 16, 19.4,
21.5, 23.7, 18.7, 23.8, 18, 16.2, 18.5, 20.6, 18.3, 22.5, 26.9,
19.4, 15.9, 20.5), oktober = c(21.4, 20.8, 14, 17, 23, 26.4,
19.6, 22.7, 26.9, 14.7, 15.2, 19.8, 26.9, 20.2, 14.3, 14.8, 18.5,
21.7, 21.4, 21.8), november = c(24.7, 26.2, 29, 21.6, 17.1, 16.9,
19.1, 24.7, 25.4, 19.8, 18.2, 16.3, 17, 17.7, 15.5, 14.7, 15.8,
19.9, 20.4, 23.3), december = c(19.8, 27, 21, 33, 22.6, 28.3,
21.1, 19, 17.3, 27, 30.2, 24.8, 17.9, 17.9, 20.7, 30.9, 36.2,
21, 20.2, 21.3), norm = c("45.8713463281901",
"24.047250681782984",
"3.7533684144746324", "38.594241119279324",
"26.391897460120358",
"61.746470001194638", "6.8321020448487992",
"11.933109250115226",
"51.951891096493924", "37.424611852237945",
"5.1587836676942374",
"36.552835044409434", "31.781209673851027",
"29.09146215582853",
"4.856812959269508", "5.3982910143166514",
"46.553976273304215",
"17.566272518985429", "20.552451905814117",
"61.894775704479279"
)), .Names = c("januari", "februari", "maart",
"april", "mei",
"juni", "juli", "augustus", "september",
"oktober", "november",
"december", "norm"), row.names = c(NA, 20L), class =
"data.frame")

I transform my dataset with the following script:

y <- melt(dataset,na.rm=TRUE)
variable <- y[,1]
value <- y[,2]

and can then perform a levene test as follows:

LEVENE <- leveneTest(value~variable,y)

When the dataset is small, lets say less than 100 values per column everything
works great. I get the message:

No id variables; using all as measure variables

When the dataset is much bigger I get the following message

Using norm as id variables, why does this function pick norm as id variable? and
how can I tell R that each column title is my variable


Met vriendelijke groeten - With kind regards,

Joachim Audenaert
onderzoeker gewasbescherming - crop protection researcher

PCS | proefcentrum voor sierteelt - ornamental plant research

________________________________


Schaessestraat 18, 9070 Destelbergen, Belgi?
T: +32 (0)9 353 94 71 | F: +32 (0)9 353 94 95
E: joachim.audenaert at pcsierteelt.be<mailto:joachim.audenaert at
pcsierteelt.be> | W: www.pcsierteelt.be<http://www.pcsierteelt.be/>



From:        PIKAL Petr <petr.pikal at precheza.cz<mailto:petr.pikal at
precheza.cz>>
To:        Joachim Audenaert <Joachim.Audenaert at
pcsierteelt.be<mailto:Joachim.Audenaert at pcsierteelt.be>>,
"r-help at r-project.org<mailto:r-help at r-project.org>"
<r-help at r-project.org<mailto:r-help at r-project.org>>
Date:        16/04/2015 12:13
Subject:        RE: [R]  melt function chooses wrong id variable with large
datasets

________________________________




Hi

There is something weird with your data and melt function.

AFAIK melt does not use first row as id.variables.

What is result of

str(dataset)

Instead of

melt(dataset,id.vars=dataset[1,], na.rm=TRUE)

melt expects something like

melt(dataset, id.vars=c("norm, "jaar"), na.rm=TRUE)

If you want more specific answer you shall show us part of your data, preferably
copy output of

dput(dataset[1:20,])

into your mail.

Cheers
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Joachim
> Audenaert
> Sent: Thursday, April 16, 2015 11:37 AM
> To: r-help at r-project.org<mailto:r-help at r-project.org>
> Subject: [R] melt function chooses wrong id variable with large
> datasets
>
> Hello all,
>
> I'm using a large dataset consisting of 2 groups of data, 2 columns in
> excel with a header (group name) and 15 000 rows of data. I would like
> like to compare this data, so I transform my dataset with the melt
> function to get 1 column of data and 1 column of ID variables, then I
> can apply different statistical tests. With small datasets this works
> great, the melt function automatically chooses the name in row 1 as ID
> variable and melts the data, thus giving me a matrix with all ID
> variables in column one and the data accordingly in column 2.
> With this big dataset however it chooses the whole first column as ID
> variables in stead of the first row. Is there a reason why this happens
> and how can I make sure the first row is chosen as ID variabele and the
> lower rows as data?
>
> If I specify that I want the first row to be the id variable I also get
> error.
>
> melt(dataset,id.vars=dataset[1,], na.rm=TRUE)
>
> Error: id variables not found in data: norm, jaar
>
> Are there alternative ways to create a good reshaped dataset?
>
> Met vriendelijke groeten - With kind regards,
>
> Joachim Audenaert
> onderzoeker gewasbescherming - crop protection researcher
>
> PCS | proefcentrum voor sierteelt - ornamental plant research
>
> Schaessestraat 18, 9070 Destelbergen, Belgi
> T: +32 (0)9 353 94 71 | F: +32 (0)9 353 94 95
> E: joachim.audenaert at pcsierteelt.be<mailto:joachim.audenaert at
pcsierteelt.be> | W: www.pcsierteelt.be
>
> Heb je je individuele begeleiding bemesting (CVBB) al aangevraagd? |
> Het PCS op LinkedIn Disclaimer | Please consider the environment before
> printing. Think green, keep it on the screen!
>       [[alternative HTML version deleted]]

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Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou ur?eny
pouze jeho adres?t?m.
Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? neprodlen? jeho
odes?latele. Obsah tohoto emailu i s p??lohami a jeho kopie vyma?te ze sv?ho
syst?mu.
Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email
jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat.
Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi ?i
zpo?d?n?m p?enosu e-mailu.

V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? smlouvy, a
to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce
s dodatkem ?i odchylkou.
- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m
dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost
??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn?
pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn?
osob?, kterou adres?t zastupuje, p?edlo?eny nebo jejich existence je adres?tovi
?i osob? j?m zastoupen? zn?m?.

This e-mail and any documents attached to it may be confidential and are
intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its sender.
Delete the contents of this e-mail with all attachments and its copies from your
system.
If you are not the intended recipient of this e-mail, you are not authorized to
use, disseminate, copy or disclose this e-mail in any manner.
The sender of this e-mail shall not be liable for any possible damage caused by
modifications of the e-mail or by delay with transfer of the email.

In case that this e-mail forms part of business dealings:
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- if the e-mail contains an offer, the recipient is entitled to immediately
accept such offer; The sender of this e-mail (offer) excludes any acceptance of
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- the sender insists on that the respective contract is concluded only upon an
express mutual agreement on all its aspects.
- the sender of this e-mail informs that he/she is not authorized to enter into
any contracts on behalf of the company except for cases in which he/she is
expressly authorized to do so in writing, and such authorization or power of
attorney is submitted to the recipient or the person represented by the
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Tento e-mail a jak?koliv k n?mu p?ipojen? dokumenty jsou d?v?rn? a jsou ur?eny
pouze jeho adres?t?m.
Jestli?e jste obdr?el(a) tento e-mail omylem, informujte laskav? neprodlen? jeho
odes?latele. Obsah tohoto emailu i s p??lohami a jeho kopie vyma?te ze sv?ho
syst?mu.
Nejste-li zam??len?m adres?tem tohoto emailu, nejste opr?vn?ni tento email
jakkoliv u??vat, roz?i?ovat, kop?rovat ?i zve?ej?ovat.
Odes?latel e-mailu neodpov?d? za eventu?ln? ?kodu zp?sobenou modifikacemi ?i
zpo?d?n?m p?enosu e-mailu.

V p??pad?, ?e je tento e-mail sou??st? obchodn?ho jedn?n?:
- vyhrazuje si odes?latel pr?vo ukon?it kdykoliv jedn?n? o uzav?en? smlouvy, a
to z jak?hokoliv d?vodu i bez uveden? d?vodu.
- a obsahuje-li nab?dku, je adres?t opr?vn?n nab?dku bezodkladn? p?ijmout;
Odes?latel tohoto e-mailu (nab?dky) vylu?uje p?ijet? nab?dky ze strany p??jemce
s dodatkem ?i odchylkou.
- trv? odes?latel na tom, ?e p??slu?n? smlouva je uzav?ena teprve v?slovn?m
dosa?en?m shody na v?ech jej?ch n?le?itostech.
- odes?latel tohoto emailu informuje, ?e nen? opr?vn?n uzav?rat za spole?nost
??dn? smlouvy s v?jimkou p??pad?, kdy k tomu byl p?semn? zmocn?n nebo p?semn?
pov??en a takov? pov??en? nebo pln? moc byly adres?tovi tohoto emailu p??padn?
osob?, kterou adres?t zastupuje, p?edlo?eny nebo jejich existence je adres?tovi
?i osob? j?m zastoupen? zn?m?.

This e-mail and any documents attached to it may be confidential and are
intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its sender.
Delete the contents of this e-mail with all attachments and its copies from your
system.
If you are not the intended recipient of this e-mail, you are not authorized to
use, disseminate, copy or disclose this e-mail in any manner.
The sender of this e-mail shall not be liable for any possible damage caused by
modifications of the e-mail or by delay with transfer of the email.

In case that this e-mail forms part of business dealings:
- the sender reserves the right to end negotiations about entering into a
contract in any time, for any reason, and without stating any reasoning.
- if the e-mail contains an offer, the recipient is entitled to immediately
accept such offer; The sender of this e-mail (offer) excludes any acceptance of
the offer on the part of the recipient containing any amendment or variation.
- the sender insists on that the respective contract is concluded only upon an
express mutual agreement on all its aspects.
- the sender of this e-mail informs that he/she is not authorized to enter into
any contracts on behalf of the company except for cases in which he/she is
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R help - Apr 2015 - melt function chooses wrong id variable with large datasets

[R] melt function chooses wrong id variable with large datasets

[R] melt function chooses wrong id variable with large datasets

[R] melt function chooses wrong id variable with large datasets

[R] melt function chooses wrong id variable with large datasets