Hie Alaiso,
try to simply apply lapply() to your data frame. It should work w/o any
further operation since data frames are lists (check with is.list()).
Hth -- Gerrit
On Wed, 25 Feb 2015, Alaios via R-help wrote:
> Hi all,I would like to use an expand.grid functionality that would give
> me at the end a listso far my code looks like:
> ?sigma_max_On_seq<-seq(0.05,100,length.out=10000)
> mean_max_On_seq<-seq(2,10000),length.out=10000)
>
expandMeanSigmaOn<-expand.grid(mean_max_On_seq,mean_max_On_seq,sigma_max_On_seq,sigma_max_On_seq)
> that gives me at the end all the possible combinations as a data
> frame.
> Browse[1]> str((expandMeanSigmaOn))
> 'data.frame':?? XXX obs. of? 4 variables:
> ?$ Var1: num? 1 11432 22864 34295 45727 ...
> ?$ Var2: num? 1 1 1 1 1 1 1 1 1 1 ...
> ?$ Var3: num? 0.05 0.05 0.05 0.05 0.05 0.05 0.05 0.05 0.05 0.05 ...
> ?$ Var4: num? 0.05 0.05 0.05 0.05 0.05 0.05 0.05 0.05 0.05 0.05 ...
> ?- attr(*, "out.attrs")=List of 2
> ? ..$ dim???? : int? 10 10 10 10
> ? ..$ dimnames:List of 4
> ? .. ..$ Var1: chr? "Var1=???? 1.00" "Var1= 11432.44"
"Var1= 22863.89" "Var1= 34295.33" ...
> ? .. ..$ Var2: chr? "Var2=???? 1.00" "Var2= 11432.44"
"Var2= 22863.89" "Var2= 34295.33" ...
> ? .. ..$ Var3: chr? "Var3=? 0.05000" "Var3= 31.48065"
"Var3= 62.91131" "Var3= 94.34196" ...
> ? .. ..$ Var4: chr? "Var4=? 0.05000" "Var4= 31.48065"
"Var4= 62.91131" "Var4= 94.34196" ...
>
> ?but I want to have a list that I would be able to use it as input into
> a lapply function. The lapply should use then each list entry
> independently giving as input variables only the current
> $Var1,$Var2,$Var3,$Var4
>
> How I can convert in R the data.frame into a list?
> I would like to thank you in advance for your replyRegardsAlex