That's exactly what I was thinking. Thanks tons.
Sent from Yahoo Mail on Android
From:"arun" <smartpink111 at yahoo.com>
Date:Sun, Feb 15, 2015 at 2:47 AM
Subject:Re: Difference in dates for unique ID
HI Farnoosh,
Not sure I understand the expected output.? The difference between the first 2
days is "136 days"
May be this helps
? library(data.table)
? ? ? dcast.data.table(setDT(df)[, list(Visit=.N, Diff=
as.numeric(abs(diff(as.Date(Date, format='%d-%b-%y'))))) ,
? ? ? ? by = ID], ID+Visit~ Diff, value.var='Diff', length)
? ? ID Visit 136 255 857
? ? 1:? 1? ? 2? 1? 0? 0
? ? 2:? 2? ? 3? 0? 1? 1
On Wednesday, February 11, 2015 5:47 PM, farnoosh sheikhi <farnoosh_81 at
yahoo.com> wrote:
Hi Arun,
I have a data set that look s like below. I wanted to get a difference in dates
for each unique ID and record it as a new X and have binary input for each one.
ID? Date
1? ? ? ? 06-Sep-13
1? ? ? ? 20-Jan-14
2? ? ? ? 06-Mar-12
2? ? ? ? 25-Jun-11
2? ? ? ? 29-Oct-13
For example for the first two date for ID=1 ( 20-Jan-14 - 06-Sep-13 ~ 121) and I
want the data to be like follow:
ID? Visit? 121
1? ? ? 2? ? ? ? 1
2? ? ? 3? ? ? ? 0
I really appreciate if you can help me with this. I know I need to write some
kind of loop, but I don't know how to think of the logic behind it.
Thanks a lot.
Farnoosh
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