R help - Feb 2015 - Genrating Ordinal Responses in R

Hi,

  Here assume there are four elements in the ordinal set y and take a random
sample of size 10 according to the cumulative distribution given, or
probability distribution p below.

> y <- c(levels = c("First", "Second",
"Third", "Fourth"))
> y
 levels1  levels2  levels3  levels4 
 "First" "Second"  "Third" "Fourth"
> (x <- c(1/9, 1/4, 3/5, 1))
[1] 0.1111111 0.2500000 0.6000000 1.0000000
> p <- c(x[1], x[2]-x[1], x[3]-x[2], x[4]-x[3])
> p
[1] 0.1111111 0.1388889 0.3500000 0.4000000
> sample(y, 10, replace=TRUE, prob=p)
 levels2  levels4  levels4  levels3  levels1  levels3  levels4  levels2 
levels4  levels3 
"Second" "Fourth" "Fourth"  "Third" 
"First"  "Third" "Fourth" "Second"
"Fourth"  "Third" 



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Thank you very much JS Huang. It helps.

Thanks & Regards,
Arnab



Arnab Kumar Maity
Graduate Teaching Assistant
Division of Statistics
Northern Illinois University
DeKalb, IL 60115
Email: maity at math.niu.edu
Ph:     779-777-3428

On Fri, Feb 13, 2015 at 5:03 PM, JS Huang [via R] <
ml-node+s789695n4703244h14 at n4.nabble.com> wrote:
> Hi,
>
>   Here assume there are four elements in the ordinal set y and take a
> random sample of size 10 according to the cumulative distribution given, or
> probability distribution p below.
>
>
> > y <- c(levels = c("First", "Second",
"Third", "Fourth"))
> > y
>  levels1  levels2  levels3  levels4
>  "First" "Second"  "Third" "Fourth"
> > (x <- c(1/9, 1/4, 3/5, 1))
> [1] 0.1111111 0.2500000 0.6000000 1.0000000
> > p <- c(x[1], x[2]-x[1], x[3]-x[2], x[4]-x[3])
> > p
> [1] 0.1111111 0.1388889 0.3500000 0.4000000
> > sample(y, 10, replace=TRUE, prob=p)
>  levels2  levels4  levels4  levels3  levels1  levels3  levels4  levels2
>  levels4  levels3
> "Second" "Fourth" "Fourth"  "Third"
"First"  "Third" "Fourth" "Second"
> "Fourth"  "Third"
>
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