R help - Jul 2001 - returning quartiles of a list?

Hi, all.  I have a list:

process <- c( 5 , 7 , 4 , 1 , 4 , 1)

and I'd like to get each half (or each third or each quartile) of the list:

process.firsthalf would be (5, 7, 4) and 
process.secondhalf would be (1, 4, 1).

note that I'm not interested in the numeric quartiles (then I could
use quantile or several other functions).

what is the best way to get this kind of thing?  for odd legnth lists,
I don't particularly care if the first or the second half gets the
extra.

 can write a function that does this for halfs, but I'm looking for a
slightly more general way that does it for 1/2, 1/3, 1/4, 1/5, etc.

thanks!
greg
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !)  To: r-help-request at
stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._

On Tue, 10 Jul 2001, Greg Trafton wrote:
> Hi, all.  I have a list:
>
> process <- c( 5 , 7 , 4 , 1 , 4 , 1)
>
> and I'd like to get each half (or each third or each quartile) of the
list:
>
n<-length(process)
process[1:(n/2)]
process[(n/2):1]
process[(n/4):(n/2)]
etc, etc,


	-thomas


-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !)  To: r-help-request at
stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._