In our work on a Google Summer of Code project "Improvements to nls()", the code has proved sufficiently entangled that we have found (so far!) few straightforward changes that would not break legacy behaviour. One issue that might be fixable is that nls() returns no result if it encounters some computational blockage AFTER it has already found a much better "fit" i.e. set of parameters with smaller sum of squares. Here is a version of the Tetra example: time=c( 1, 2, 3, 4, 6 , 8, 10, 12, 16) conc = c( 0.7, 1.2, 1.4, 1.4, 1.1, 0.8, 0.6, 0.5, 0.3) NLSdata <- data.frame(time,conc) NLSstart <-c(lrc1=-2,lrc2=0.25,A1=150,A2=50) # a starting vector (named!) NLSformula <-conc ~ A1*exp(-exp(lrc1)*time)+A2*exp(-exp(lrc2)*time) tryit <- try(nls(NLSformula, data=NLSdata, start=NLSstart, trace=TRUE)) print(tryit) If you run this, tryit does not give information that the sum of squares has been reduced from > 60000 to < 2, as the trace shows. Should we propose that this be changed so the returned object gives the best fit so far, albeit with some form of message or return code to indicate that this is not necessarily a conventional solution? Our concern is that some examples might need to be adjusted slightly, or we might simply add the "try-error" class to the output information in such cases. Comments are welcome, as this is as much an infrastructure matter as a computational one. Best, John Nash
Martin Maechler
2021-Aug-20 15:35 UTC
[Rd] Seeking opinions on possible change to nls() code
>>>>> J C Nash >>>>> on Fri, 20 Aug 2021 11:06:25 -0400 writes:> In our work on a Google Summer of Code project > "Improvements to nls()", the code has proved sufficiently > entangled that we have found (so far!) few > straightforward changes that would not break legacy > behaviour. One issue that might be fixable is that nls() > returns no result if it encounters some computational > blockage AFTER it has already found a much better "fit" > i.e. set of parameters with smaller sum of squares. Here > is a version of the Tetra example: time=c( 1, 2, 3, 4, 6 , 8, 10, 12, 16) conc = c( 0.7, 1.2, 1.4, 1.4, 1.1, 0.8, 0.6, 0.5, 0.3) NLSdata <- data.frame(time,conc) NLSstart <-c(lrc1=-2,lrc2=0.25,A1=150,A2=50) # a starting vector (named!) NLSformula <-conc ~ A1*exp(-exp(lrc1)*time)+A2*exp(-exp(lrc2)*time) tryit <- try(nls(NLSformula, data=NLSdata, start=NLSstart, trace=TRUE)) print(tryit) > If you run this, tryit does not give information that the > sum of squares has been reduced from > 60000 to < 2, as > the trace shows. > Should we propose that this be changed so the returned > object gives the best fit so far, albeit with some form of > message or return code to indicate that this is not > necessarily a conventional solution? Our concern is that > some examples might need to be adjusted slightly, or we > might simply add the "try-error" class to the output > information in such cases. > Comments are welcome, as this is as much an infrastructure > matter as a computational one. Hmm... many years ago, we had introduced the 'warnOnly=TRUE' option to nls() i.e., nls.control() exactly for such cases, where people would still like to see the solution: So, ------------------------------------------------------------------------------> try2 <- nls(NLSformula, data=NLSdata, start=NLSstart, trace=TRUE,control = nls.control(warnOnly=TRUE)) 61215.76 (3.56e+03): par = (-2 0.25 150 50) 2.175672 (2.23e+01): par = (-1.9991 0.3171134 2.618224 -1.366768) 1.621050 (7.14e+00): par = (-1.960475 -2.620293 2.575261 -0.5559918) Warning message: In nls(NLSformula, data = NLSdata, start = NLSstart, trace = TRUE, : singular gradient> try2Nonlinear regression model model: conc ~ A1 * exp(-exp(lrc1) * time) + A2 * exp(-exp(lrc2) * time) data: NLSdata lrc1 lrc2 A1 A2 -22.89 96.43 156.70 -156.68 residual sum-of-squares: 218483 Number of iterations till stop: 2 Achieved convergence tolerance: 7.138 Reason stopped: singular gradient> coef(try2)lrc1 lrc2 A1 A2 -22.88540 96.42686 156.69547 -156.68461> summary(try2)Error in chol2inv(object$m$Rmat()) : element (3, 3) is zero, so the inverse cannot be computed>------------------------------------------------------------------------------ and similar for vcov(), of course, where the above error originates. { I think GSoC (andr other) students should start by studying and exploring relevant help pages before drawing conclusions ...... but yes, I've been born in the last millennium ... } ;-) Have a nice weekend! Martin