x <- 0; names(x) <- "recursive"
I am saying more plainly: With 'x' above, deparse(x, control =
"all") is wrong in R devel.
--------------------------------------------
On Sat, 16/12/17, Suharto Anggono Suharto Anggono <suharto_anggono at
yahoo.com> wrote:
Subject: Nice names in deparse
To: r-devel at r-project.org
Date: Saturday, 16 December, 2017, 11:09 PM
Tags (argument names) in call to 'list'
becomes names of the result. It is not necessarily so with
call to 'c'. The default method of 'c' has 'recursive'
and
'use.names' arguments.
In R devel r73778, with
x <- 0; names(x) <- "recursive"?
,
dput(x)
or even
dput(x, control = "all")
gives
c(recursive = 0)
However, actual result of c(recursive 0) is NULL.
Also with
x <- 0; names(x) <- "recursive"?
,
dput(x, control = c("keepNA",
"keepInteger", "showAttributes"))
in R devel r73778
gives
structure(c(0), .Names = "recursive")
The 'control' is suggested by an
example for output as in R < 3.5.0. However, the output
is slightly different from
dput(x)
in R 3.3.2:
structure(0, .Names = "recursive")
Part of NEWS item related with
"niceNames" control option:
as.character(list( c (one = 1))) now
includes the name, as as.character(list(list(one = 1))) has
always done.
Please reconsider.
As
as.numeric(list(c(one = 1)))
gives
1 ,
I expect that
as.character(list(c(one = "1")))
gives
"1" .
It does in R devel r73778.
Why does
as.character(list(c(one = 1)))
give
"c(one = 1)" ?
as.numeric(list(c(one = "1")))
gives
1 .
list(list(one = 1))
is not quite the same.
as.numeric(list(list(one = 1)))
gives
NA .