Henrik Bengtsson
2014-Oct-03 17:28 UTC
[Rd] Any penalty for using gzfile() in place of file() for reading?
A question I meant to ask for a very long time: I have several functions that temporarily open files using file(..., open="rb"). I'd like to support gzip'ed files also and noticed that gzfile(..., open="rb") handles also non-compressed files, cf. help("gzfile"): For 'gzfile' the description is the path to a file compressed by 'gzip': it can also open for reading uncompressed files and those compressed by 'bzip2', 'xz' or 'lzma'.>From simple benchmarking I cannot measure any overhead from usinggzfile(). I assume the only overhead would come from inspecting the first few bytes in the file. Also, there is no risk that my non-compressed files have gzip header (by chance), so that is not a concern. Does anyone see a reason for not just using gzfile(..., open="rb") everywhere I use file(..., open="rb") today? /Henrik