charles.dupont at vanderbilt.edu
2007-Mar-20 15:19 UTC
[Rd] wishlist -- Fix for major format.pval limitation (PR#9574)
Full_Name: Charles Dupont
Version: 2.4.1
OS: linux 2.6.18
Submission from: (NULL) (160.129.129.136)
'format.pval' has a major limitation in its implementation. For example
suppose a person had a vector like 'a' and the error being ?0.001.
> a <- c(0.1, 0.3, 0.4, 0.5, 0.3, 0.0001)
> format.pval(a, eps=0.01)
If that person wants to have the 'format.pval' output with 2 digits
always
showing (like passing nsmall=2 to 'format'). That output would look like
this.
[1] "0.10" "0.30" "0.40"
"0.50" "0.30" "<0.01"
That output is currently impossible because format.pval can only
produce output like this.
[1] "0.1" "0.3" "0.4" "0.5"
"0.3" "<0.01"
---------------------------------------------------------------
a <- c(0.1, 0.3, 0.4, 0.5, 0.3, 0.0001)
format.pval(a, eps=0.01)
murdoch at stats.uwo.ca
2007-Mar-20 16:36 UTC
[Rd] wishlist -- Fix for major format.pval limitation (PR#9574)
On 3/20/2007 11:19 AM, charles.dupont at vanderbilt.edu wrote:> Full_Name: Charles Dupont > Version: 2.4.1 > OS: linux 2.6.18 > Submission from: (NULL) (160.129.129.136) > > > 'format.pval' has a major limitation in its implementation. For example > suppose a person had a vector like 'a' and the error being ?0.001. > > > a <- c(0.1, 0.3, 0.4, 0.5, 0.3, 0.0001) > > format.pval(a, eps=0.01) > > If that person wants to have the 'format.pval' output with 2 digits always > showing (like passing nsmall=2 to 'format'). That output would look like > this. > > [1] "0.10" "0.30" "0.40" "0.50" "0.30" "<0.01" > > That output is currently impossible because format.pval can only > produce output like this. > > [1] "0.1" "0.3" "0.4" "0.5" "0.3" "<0.01" > > > --------------------------------------------------------------- > a <- c(0.1, 0.3, 0.4, 0.5, 0.3, 0.0001) > format.pval(a, eps=0.01)But there's a very easy workaround: format.pval(c(0.12, a), eps=0.01)[-1] gives you what you want (because the 0.12 forces two decimal place display on all values, and then the [-1] removes it). Duncan Murdoch