R devel - Sep 2006 - Regular expressions

When I type

ls("package:base", pattern="log*")
functions with names like "floor" and
"Sys.setlocale" are included. I don't
think this is how "*" is supposed to work.

To get the desired response I have to use:
ls("packge:base", pattern="logg*")

I thought "log*" means "log" followed by
anything?

Thanks for any tips.

(I'm using R-alpha as of a week ago, perhaps)

ds

On Sat, 23 Sep 2006, Dominick Samperi wrote:
> When I type
>
> ls("package:base", pattern="log*")
> functions with names like "floor" and
> "Sys.setlocale" are included. I don't
> think this is how "*" is supposed to work.
>
> To get the desired response I have to use:
> ls("packge:base", pattern="logg*")
If you want a wildcard-like behaviour, use glob2rx, e.g.
> glob2rx("log*")
[1] "^log"
> I thought "log*" means "log" followed by anything?
Please read ?regexp.
It means 'lo' followed by zero or more occurrences of 'g'.

-- 
Brian D. Ripley,                  ripley at stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
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