> Thanks for pointing this out. I think your code should work, although
> I'm slightly uneasy about actually modifying f, so how about
Just curious, why are you uneasy about that? Does it have side effects?
> len <- length(if (is.list(f)) f[[1]] else f)
The reason I used the interaction() call is that this seems to work too:
> split(1:10,list(a=1:2,b=1:5))
So, lists with unequal lengths.
- Hedderik.
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