Full_Name: Hsiu-Khuern Tang
Version: 1.3.1
OS: Debian GNU/Linux unstable
Submission from: (NULL) (192.6.19.124)
Hi,
The current documentation for approx() contains the following paragraph:
f: For `method="constant"' a number between 0 and 1
inclusive,
indicating a compromise between left- and right-continuous
step functions. If `y0' and `y1' are the values to the left
and right of the point then the value is `y0*f+y1*(1-f)' so
that `f=0' is right-continuous and `f=1' is left-continuous.
The formula
y0*f+y1*(1-f)
should be
y0*(1-f)+y1*f
This will make it consistent with the claim that "`f=0' is
right-continuous and
`f=1' is left-continuous", as well as with the actual code:
approx(1:2, 1:2, xout=1.5, method="constant", f=1)
$x
[1] 1.5
$y
[1] 2
Best,
Hsiu-Khuern.
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