charlie@muskrat.stat.umn.edu writes:
> For example, Example 5.4 in Hollander and Wolfe (Nonparametric Statistical,
> Methods, 2nd ed., Wiley, 1999, pp. 180-181)
>
> R Version 1.3.1 (SuSE Linux 7.1)
>
> > X <-
read.table(url("http://www.stat.umn.edu/geyer/5601/hwdata/t5-7.txt"),
> + header = TRUE)
> > names(X)
> [1] "x" "y"
> > attach(X)
> > ks.test(x, y)
>
> Two-sample Kolmogorov-Smirnov test
>
> data: x and y
> D = 0.6, p-value = 0.01234
> alternative hypothesis: two.sided
>
> Not hardly. Hollander and Wolfe say the exact P-value is 0.0524. Note
Here's part of the problem:
Browse[1]> .C("psmirnov2x", p = as.double(STATISTIC),
as.integer(n.x),
as.integer(n.y), PACKAGE = "ctest")$p
[1] 0.9876594
Browse[1]> .C("psmirnov2x", p = as.double(0.6), as.integer(n.x),
as.integer(n.y), PACKAGE = "ctest")$p
[1] 0.9475524
Browse[1]> STATISTIC
[1] 0.6
Perplexed? The reason is of course that
Browse[1]> STATISTIC-0.6
[1] 1.110223e-16
and the KS distribution is discontinuous, so the point probability at
0.6 didn't get counted. Looks like we need a fudge factor.
--
O__ ---- Peter Dalgaard Blegdamsvej 3
c/ /'_ --- Dept. of Biostatistics 2200 Cph. N
(*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918
~~~~~~~~~~ - (p.dalgaard@biostat.ku.dk) FAX: (+45) 35327907
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