CentOS - Sep 2011 - replace multiple string

Hi


I would like to use a bash script that searches files and
subdirectories name in a directory /var/ww/html/web
for a specific string, and when it finds the search string, replaces
the string (old1) with new string (new1), and so on
old2 with new2 ....oldn with newn.



replace_string.sh
#!/bin/bash
for db in $(find /var/www/html/web -name * -exec)
do
  sed -e "s/old1/new1/" \
  sed  -e "s/old2/new2/" \
...
  sed -e "s/oldn/newn/" $db
done

Any recommendation..

Thanks
pons

madunix at gmail.com wrote:
>
> I would like to use a bash script that searches files and
> subdirectories name in a directory /var/ww/html/web
> for a specific string, and when it finds the search string, replaces
> the string (old1) with new string (new1), and so on
> old2 with new2 ....oldn with newn.
>
> replace_string.sh
> #!/bin/bash
> for db in $(find /var/www/html/web -name * -exec)
> do
>   sed -e "s/old1/new1/" \
>   sed  -e "s/old2/new2/" \
> ...
>   sed -e "s/oldn/newn/" $db
> done
Close. I think
find /var/www/html/web -type f -exec sed -i -e
"s/old1/new1/;s/old2/new2/;..." {} \;
would do it. The -i is to make the change inplace, editing the existing file.

         mark

On 2011-09-23 19:47, madunix at gmail.com wrote:
> Hi
>
>
> I would like to use a bash script that searches files and
> subdirectories name in a directory /var/ww/html/web
> for a specific string, and when it finds the search string, replaces
> the string (old1) with new string (new1), and so on
> old2 with new2 ....oldn with newn.
>
>
>
> replace_string.sh
> #!/bin/bash
> for db in $(find /var/www/html/web -name * -exec)
> do
>    sed -e "s/old1/new1/" \
>    sed -e "s/old2/new2/" \
> ...
>    sed -e "s/oldn/newn/" $db
A more efficient way to perform sed is

sed -e "s/old1/new1/" \
     -e "s/old2/new2/" \
...
     -e "s/oldn/newn/" $db

or

sed -e "s/old1/new1/ ; s/old2/new2/" .. $db


Other hints for efficient nash shell scripts..
http://hacktux.com/bash/script/efficient

On Fri, Sep 23, 2011 at 10:47 AM, madunix at gmail.com <madunix at
gmail.com> wrote:
>
> I would like to use a bash script that searches files and
> subdirectories name in a directory /var/ww/html/web
> for a specific string, and when it finds the search string, replaces
> the string (old1) with new string (new1), and so on
> old2 with new2 ....oldn with newn.
It would appear from the subsequent discussion that what you're trying
to do is rename files and subdirectories, NOT change the CONTENTS of
the files.  All these suggestions with sed so far are for changing
strings in the file contents, and won't work on the names of anything.

I think you want to start by simply collecting all the file and
subdirectory names:

find /var/www/html/web -depth -print

(this assumes that none of the file names contains embedded newlines).

Next you want to transform those names using your set of patterns, and
then rename the results:

find /var/www/html/web -depth -print | \
while read oldname
do
 newname="$(echo "$oldname" | sed -e "s/old1/new1/" \
    -e "s/old2/new2/" \
    -e ... \
    -e "s/oldN/newN/")"
 mv "$oldname" "$newname"
done

If the names contain leading/trailing spaces or other odd characters
then a simple pipe to "while read" probably won't work and you
will
have to resort to a perl script or the like.

Note also you can pass multiple -e options to "sed".

how about...

     find . -depth -execdir mv \{} ${\{}/old/new} \;


I do highly recommend test-running this with a "echo " in front of the
mv command.   I didn't test it.


-- 
john r pierce                            N 37, W 122
santa cruz ca                         mid-left coast