Jonathan H
2016-Oct-10 21:47 UTC
[asterisk-users] AGI: How to break out of AGI when stream_file escape_digits are detected in middle of long sequence of files?
For reasons best known to myself, I call a python agi (PYST2 - love
it!) which streams a series of very short files in quick succession.
Like this:
escape_digits = str("0")
agi.stream_file(promptFile,escape_digits)
and this is what I see on the AGI debug:
<Local/s at root-00000061;2>AGI Tx >> 200 result=0 endpos=6784
<Local/s at root-00000061;2>AGI Rx << STREAM FILE
/home/DefaultPrompts/en_GB/female/wx/low "0" 0
-- <Local/s at root-00000061;2> Playing
'/home/DefaultPrompts/en_GB/female/wx/low.alaw' (escape_digits=0)
(sample_offset 0) (language 'en_GB')
<Local/s at root-00000061;2>AGI Tx >> 200 result=48 endpos=1440
The FIRST line is a file that finished normally, with result=0, the
LAST line is a file that was interrupted, and receives result=48 from
asterisk.
Yes, zero stops the file playing, but it just goes onto the next file.
So, how do I get that variable? It doesn't become available in python,
and trying to get it via either
agi.env[result']
agi.get_variable('result')
just makes python choke and the AGI quits. That would be fine if it
was a result of result being 48!
I feel like I'm going slightly bonkers here because it's something so
obvious, and yet I've googled so hard over this!
Thanks.
Lefteris Zafiris
2016-Oct-11 08:31 UTC
[asterisk-users] AGI: How to break out of AGI when stream_file escape_digits are detected in middle of long sequence of files?
On Mon, 10 Oct 2016, at 22:47, Jonathan H wrote:> For reasons best known to myself, I call a python agi (PYST2 - love > it!) which streams a series of very short files in quick succession. > > Like this: > > escape_digits = str("0") > agi.stream_file(promptFile,escape_digits) > > and this is what I see on the AGI debug: > > <Local/s at root-00000061;2>AGI Tx >> 200 result=0 endpos=6784 > <Local/s at root-00000061;2>AGI Rx << STREAM FILE > /home/DefaultPrompts/en_GB/female/wx/low "0" 0 > -- <Local/s at root-00000061;2> Playing > '/home/DefaultPrompts/en_GB/female/wx/low.alaw' (escape_digits=0) > (sample_offset 0) (language 'en_GB') > <Local/s at root-00000061;2>AGI Tx >> 200 result=48 endpos=1440 > > The FIRST line is a file that finished normally, with result=0, the > LAST line is a file that was interrupted, and receives result=48 from > asterisk. > > Yes, zero stops the file playing, but it just goes onto the next file. > > So, how do I get that variable? It doesn't become available in python, > and trying to get it via either > > agi.env[result'] > agi.get_variable('result') > > just makes python choke and the AGI quits. That would be fine if it > was a result of result being 48! > > I feel like I'm going slightly bonkers here because it's something so > obvious, and yet I've googled so hard over this! > > Thanks.Hello, as the docs on stream_file() mention it returns the digit if one was pressed. So you might want to try something like: pressed_digit = agi.stream_file(promptFile,escape_digits) in you case the raw value 48 is converted to its ascii equivalent so pressed_digit will have the value 0 -- Lefteris Zafiris
Jonathan H
2016-Oct-11 10:31 UTC
[asterisk-users] AGI: How to break out of AGI when stream_file escape_digits are detected in middle of long sequence of files?
Arrrgh! You are correct, of course. I hadn't realised you could do it
that way - I was assuming it was a variable that was returned to the
dialplan/channel.
Some of the finer points of AGI are still a slight mystery to me!
Thank you very much - working perfectly now, with your help and the
following code. Thank you again.
escape_digits = str("*")
pressed_digit=agi.stream_file(promptFile,escape_digits)
if pressed_digit == "*":
sys.exit(0)
On 11 October 2016 at 09:31, Lefteris Zafiris <zaf at fastmail.com>
wrote:> On Mon, 10 Oct 2016, at 22:47, Jonathan H wrote:
>> For reasons best known to myself, I call a python agi (PYST2 - love
>> it!) which streams a series of very short files in quick succession.
>>
>> Like this:
>>
>> escape_digits = str("0")
>> agi.stream_file(promptFile,escape_digits)
>>
>> and this is what I see on the AGI debug:
>>
>> <Local/s at root-00000061;2>AGI Tx >> 200 result=0
endpos=6784
>> <Local/s at root-00000061;2>AGI Rx << STREAM FILE
>> /home/DefaultPrompts/en_GB/female/wx/low "0" 0
>> -- <Local/s at root-00000061;2> Playing
>> '/home/DefaultPrompts/en_GB/female/wx/low.alaw'
(escape_digits=0)
>> (sample_offset 0) (language 'en_GB')
>> <Local/s at root-00000061;2>AGI Tx >> 200 result=48
endpos=1440
>>
>> The FIRST line is a file that finished normally, with result=0, the
>> LAST line is a file that was interrupted, and receives result=48 from
>> asterisk.
>>
>> Yes, zero stops the file playing, but it just goes onto the next file.
>>
>> So, how do I get that variable? It doesn't become available in
python,
>> and trying to get it via either
>>
>> agi.env[result']
>> agi.get_variable('result')
>>
>> just makes python choke and the AGI quits. That would be fine if it
>> was a result of result being 48!
>>
>> I feel like I'm going slightly bonkers here because it's
something so
>> obvious, and yet I've googled so hard over this!
>>
>> Thanks.
>
> Hello,
>
> as the docs on stream_file() mention it returns the digit if one was
> pressed.
> So you might want to try something like:
>
> pressed_digit = agi.stream_file(promptFile,escape_digits)
>
> in you case the raw value 48 is converted to its ascii equivalent so
> pressed_digit will have the value 0
>
> --
> Lefteris Zafiris
>
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