I don't think this is a bug in the documentation. The help page for
`?[.data.frame` has the following in the last paragraph of the
details:
Both [ and [[ extraction methods partially match row names. By default
neither partially match column names, but [[ will if exact = FALSE
(and with a warning if exact = NA). If you want to exact matching on
row names use match, as in the examples.
The example it refers to is
sw <- swiss[1:5, 1:4] # select a manageable subset
sw["C", ] # partially matches
sw[match("C", row.names(sw)), ] # no exact match
Whether this is good behaviour or not is a different question, but the
documentation seems clear enough (to me, at least).
Best,
Steve
On Fri, 14 Jan 2022 at 20:40, Ben Bolker <bbolker at gmail.com>
wrote:>
>
> People are often surprised that row-indexing a data frame by [ +
> character does partial matching (and annoyed that there is no way to
> turn it off:
>
>
https://stackoverflow.com/questions/18033501/warning-when-partial-matching-rownames
>
>
https://stackoverflow.com/questions/34233235/r-returning-partial-matching-of-row-names
>
>
https://stackoverflow.com/questions/70716905/why-does-r-have-inconsistent-behaviors-when-a-non-existent-rowname-is-retrieved
>
>
> ?"[" says:
>
> Character indices can in some circumstances be partially matched
> (see ?pmatch?) to the names or dimnames of the object being
> subsetted (but never for subassignment). UNLIKE S (Becker et al_
> p. 358), R NEVER USES PARTIAL MATCHING WHEN EXTRACTING BY ?[?, and
> partial matching is not by default used by ?[[? (see argument
> ?exact?).
>
> (EMPHASIS ADDED).
>
> Looking through the rest of that page, I don't see any other text that
> modifies or supersedes that statement.
>
> Is this a documentation bug?
>
> The example given in one of the links above:
>
> b <- as.data.frame(matrix(4:5, ncol = 1, nrow = 2, dimnames >
list(c("A10", "B"), "V1")))
>
> b["A1",] ## 4 (partial matching)
> b[rownames(b) == "A1",] ## logical(0)
> b["A1", , exact=TRUE] ## unused argument error
> b$V1[["A1"]] ## subscript out of bounds error
> b$V1["A1"] ## NA
>
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