R help - Jul 2018 - RStudio 1.1.453 - Windows 10 - How to subset named vector by names that are NOT "foo"

H
i All,

If I have this vector:
> vect <- c(foo = 11, bar = 2, norf = 45)
I can have a subset that has only "bar and "norf" this
way:
> vect[c("bar","norf")]
Now how do I achieve the same by asking it for a subset that simply
excludes "foo"? I tried all these, resulting in errors:

vect[-"foo"]
vect[-c("foo")]
vect[!"foo"]
vect[!c("foo")]

Thanks!

	[[alternative HTML version deleted]]

try:

vect[which(names(vect) != "foo")]

On Tue, Jul 31, 2018 at 1:41 PM, ??????? ???? Ibrauheem Khat'taub
<barhomopolis at gmail.com> wrote:
> H
> i All,
>
> If I have this vector:
>
>> vect <- c(foo = 11, bar = 2, norf = 45)
>
> I can have a subset that has only "bar and "norf" this way:
>> vect[c("bar","norf")]
>
> Now how do I achieve the same by asking it for a subset that simply
> excludes "foo"? I tried all these, resulting in errors:
>
> vect[-"foo"]
> vect[-c("foo")]
> vect[!"foo"]
> vect[!c("foo")]
>
> Thanks!
>
>         [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

Hi,

You need to tell R to look in the names component of your vector. Here
are three different ways:

vect <- c(foo = 11, bar = 2, norf = 45)

vect[!(names(vect) %in% c("foo"))] # easily generalizable to a longer
list

vect[!grepl("foo", names(vect))]

vect[!(names(vect) == "foo")]

There are many more ways to do this, all predicated on matching a
string within the character vector containing the names of your
object.

Also, on this list we don't care at all if you're using R Studio, or
what the version is. We do potentially care what version of R itself
you are using.

Sarah

On Tue, Jul 31, 2018 at 1:41 PM, ??????? ???? Ibrauheem Khat'taub
<barhomopolis at gmail.com> wrote:
> H
> i All,
>
> If I have this vector:
>
>> vect <- c(foo = 11, bar = 2, norf = 45)
>
> I can have a subset that has only "bar and "norf" this way:
>> vect[c("bar","norf")]
>
> Now how do I achieve the same by asking it for a subset that simply
> excludes "foo"? I tried all these, resulting in errors:
>
> vect[-"foo"]
> vect[-c("foo")]
> vect[!"foo"]
> vect[!c("foo")]
>
> Thanks!
>

-- 
Sarah Goslee
http://www.functionaldiversity.org

Awesome, Sarah, thanks!

And thanks for the clarification about declaring the version of R.

Best,
Ibrahim

On Tue, 31 Jul 2018 at 13:50, Sarah Goslee <sarah.goslee at gmail.com>
wrote:
> Hi,
>
> You need to tell R to look in the names component of your vector. Here
> are three different ways:
>
> vect <- c(foo = 11, bar = 2, norf = 45)
>
> vect[!(names(vect) %in% c("foo"))] # easily generalizable to a
longer list
>
> vect[!grepl("foo", names(vect))]
>
> vect[!(names(vect) == "foo")]
>
> There are many more ways to do this, all predicated on matching a
> string within the character vector containing the names of your
> object.
>
> Also, on this list we don't care at all if you're using R Studio,
or
> what the version is. We do potentially care what version of R itself
> you are using.
>
> Sarah
>
> On Tue, Jul 31, 2018 at 1:41 PM, ??????? ???? Ibrauheem Khat'taub
> <barhomopolis at gmail.com> wrote:
> > H
> > i All,
> >
> > If I have this vector:
> >
> >> vect <- c(foo = 11, bar = 2, norf = 45)
> >
> > I can have a subset that has only "bar and "norf" this
way:
> >> vect[c("bar","norf")]
> >
> > Now how do I achieve the same by asking it for a subset that simply
> > excludes "foo"? I tried all these, resulting in errors:
> >
> > vect[-"foo"]
> > vect[-c("foo")]
> > vect[!"foo"]
> > vect[!c("foo")]
> >
> > Thanks!
> >
>
>
> --
> Sarah Goslee
> http://www.functionaldiversity.org
>
	[[alternative HTML version deleted]]

You can do

Vect[-grep (?foo?, names(vect))]

On Tue, 31 Jul 2018 at 11:12 PM, ??????? ???? Ibrauheem Khat'taub <
barhomopolis at gmail.com> wrote:
> H
> i All,
>
> If I have this vector:
>
> > vect <- c(foo = 11, bar = 2, norf = 45)
>
> I can have a subset that has only "bar and "norf" this way:
> > vect[c("bar","norf")]
>
> Now how do I achieve the same by asking it for a subset that simply
> excludes "foo"? I tried all these, resulting in errors:
>
> vect[-"foo"]
> vect[-c("foo")]
> vect[!"foo"]
> vect[!c("foo")]
>
> Thanks!
>
>         [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
-- 
Regards,
Data Science Classes

	[[alternative HTML version deleted]]

Awesome, thanks!
?? ???? ????? ??????? ?????.
??????? ????


On Tue, 31 Jul 2018 at 13:54, Data Science Classes <
datascienceclasses at gmail.com> wrote:
> You can do
>
> Vect[-grep (?foo?, names(vect))]
>
> On Tue, 31 Jul 2018 at 11:12 PM, ??????? ???? Ibrauheem Khat'taub <
> barhomopolis at gmail.com> wrote:
>
>> H
>> i All,
>>
>> If I have this vector:
>>
>> > vect <- c(foo = 11, bar = 2, norf = 45)
>>
>> I can have a subset that has only "bar and "norf" this
way:
>> > vect[c("bar","norf")]
>>
>> Now how do I achieve the same by asking it for a subset that simply
>> excludes "foo"? I tried all these, resulting in errors:
>>
>> vect[-"foo"]
>> vect[-c("foo")]
>> vect[!"foo"]
>> vect[!c("foo")]
>>
>> Thanks!
>>
>>         [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
> --
> Regards,
> Data Science Classes
>
	[[alternative HTML version deleted]]