Hi
slightly different version without as.character
DF1$Comb <- ifelse(DF1$first=="Alex", paste(DF1$first, DF1$YR,
sep="-"), paste(DF1$first, "", sep=""))
[1] "Alex-2001" "Bob" "Cory"
"Cory" "Bob" "Bob"
[7] "Alex-2002" "Alex-2003" "Alex-2004"
Cheers
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Marc
> Schwartz
> Sent: Tuesday, March 14, 2017 12:33 AM
> To: Val <valkremk at gmail.com>
> Cc: R-help <r-help at r-project.org>
> Subject: Re: [R] replace
>
>
> > On Mar 13, 2017, at 5:53 PM, Val <valkremk at gmail.com> wrote:
> >
> > HI all,
> >
> > if first name is Alex then I want concatenate the second column to
> > Alex to produce Alex and the second column value
> >
> > DF1 <- read.table(header=TRUE, text='first YR
> > Alex 2001
> > Bob 2001
> > Cory 2001
> > Cory 2002
> > Bob 2002
> > Bob 2003
> > Alex 2002
> > Alex 2003
> > Alex 2004')
> >
> >
> > Output
> > data frame
> > DF2
> > Alex-2001 2001
> > Bob 2001
> > Cory 2001
> > Cory 2002
> > Bob 2002
> > Bob 2003
> > Alex-2002 2002
> > Alex-2003 2003
> > Alex-2004 2004
> >
> > I tried this one but did not work.
> > DF1$first[DF1$first=="Alex"] <- paste(DF1$first, DF1$YR,
sep='-')
> >
> > Thank you in advance
>
>
> Hi,
>
> See ?ifelse and try this:
>
> DF1$Comb <- ifelse(DF1$first == "Alex",
> paste(DF1$first, DF1$YR, sep = "-"),
> as.character(DF1$first))
>
> > DF1
> first YR Comb
> 1 Alex 2001 Alex-2001
> 2 Bob 2001 Bob
> 3 Cory 2001 Cory
> 4 Cory 2002 Cory
> 5 Bob 2002 Bob
> 6 Bob 2003 Bob
> 7 Alex 2002 Alex-2002
> 8 Alex 2003 Alex-2003
> 9 Alex 2004 Alex-2004
>
>
> Note the coercion of the second returned value to character, otherwise you
> get the numeric code associated with the factor levels of DF1$first.
>
> I generally try to avoid overwriting the source data, or in this case,
column, to
> preserve it for future use as may be needed.
>
> Regards,
>
> Marc Schwartz
>
> ______________________________________________
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> guide.html
> and provide commented, minimal, self-contained, reproducible code.
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