Dear all, I`ve got to calculate the ratio of methanogens to bacteria, but I wouldn`t like to divide the total copy numbers of methanogens ( on average 10^8) by bacteria (10^10) because they have different exponents and bases. So, my idea is to standardize both microorganisms counts to 10^3. Hypothetical example of what I`d like to do: Total Methanogens: 28 x 10^3 Total bacteria: 710 x 10^3 Total: 710 + 28= 738 x 10^3 Met/bac Ratio : (28/738)*100 = 3.79% How could I perform this calculation in R? Thanks, -- Andre [[alternative HTML version deleted]]
myfun <- function(a, b) a/(a + b) Leonardo Ferreira Fontenelle Em Sex 24 jun. 2016, ?s 13:05, Andr? Luis Neves escreveu:> Dear all, > > I`ve got to calculate the ratio of methanogens to bacteria, but I > wouldn`t > like to divide the total copy numbers of methanogens ( on average 10^8) > by > bacteria (10^10) because they have different exponents and bases. So, my > idea is to standardize both microorganisms counts to 10^3. > > Hypothetical example of what I`d like to do: > > Total Methanogens: 28 x 10^3 > Total bacteria: 710 x 10^3 > > > Total: 710 + 28= 738 x 10^3 > > Met/bac Ratio : (28/738)*100 = 3.79% > > How could I perform this calculation in R? > > Thanks, > > -- > Andre > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.
pretty simple:> t_m <- 28e3 > t_b <- 710e3 > ratio <- t_m / (t_m + t_b) * 100 > ratio[1] 3.794038 Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. On Fri, Jun 24, 2016 at 12:05 PM, Andr? Luis Neves <andrluis at ualberta.ca> wrote:> Dear all, > > I`ve got to calculate the ratio of methanogens to bacteria, but I wouldn`t > like to divide the total copy numbers of methanogens ( on average 10^8) by > bacteria (10^10) because they have different exponents and bases. So, my > idea is to standardize both microorganisms counts to 10^3. > > Hypothetical example of what I`d like to do: > > Total Methanogens: 28 x 10^3 > Total bacteria: 710 x 10^3 > > > Total: 710 + 28= 738 x 10^3 > > Met/bac Ratio : (28/738)*100 = 3.79% > > How could I perform this calculation in R? > > Thanks, > > -- > Andre > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >[[alternative HTML version deleted]]
This is very basic. Have you gone through any R tutorials? There are many good ones on the web. e.g., see here: https://www.rstudio.com/online-learning/#R In any case, you should not expect this list to teach you basic R. You *should* expect it to help you learn and improve your own efforts. I realize that there is a gray area where these things may overlap. Also see inline below. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Fri, Jun 24, 2016 at 9:05 AM, Andr? Luis Neves <andrluis at ualberta.ca> wrote:> Dear all, > > I`ve got to calculate the ratio of methanogens to bacteria, but I wouldn`t > like to divide the total copy numbers of methanogens ( on average 10^8) by > bacteria (10^10) because they have different exponents and bases. So, my > idea is to standardize both microorganisms counts to 10^3.Why can't you use scientific notation? What form are your data in? e.g.> a <- 6.2E8; b <- 5.4E10 > a/b[1] 0.01148148> > Hypothetical example of what I`d like to do: > > Total Methanogens: 28 x 10^3 > Total bacteria: 710 x 10^3 > > > Total: 710 + 28= 738 x 10^3 > > Met/bac Ratio : (28/738)*100 = 3.79% > > How could I perform this calculation in R? > > Thanks, > > -- > Andre > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.