Jason Wang
2020-Jul-15 09:06 UTC
[PATCH 3/7] vhost_vdpa: implement IRQ offloading functions in vhost_vdpa
On 2020/7/15 ??4:56, Zhu, Lingshan wrote:> > > On 7/15/2020 4:51 PM, Jason Wang wrote: >> >> On 2020/7/13 ??5:47, Zhu, Lingshan wrote: >>> >>> >>> On 7/13/2020 4:22 PM, Jason Wang wrote: >>>> >>>> On 2020/7/12 ??10:49, Zhu Lingshan wrote: >>>>> This patch introduce a set of functions for setup/unsetup >>>>> and update irq offloading respectively by register/unregister >>>>> and re-register the irq_bypass_producer. >>>>> >>>>> Signed-off-by: Zhu Lingshan <lingshan.zhu at intel.com> >>>>> --- >>>>> ? drivers/vhost/vdpa.c | 69 >>>>> ++++++++++++++++++++++++++++++++++++++++++++++++++++ >>>>> ? 1 file changed, 69 insertions(+) >>>>> >>>>> diff --git a/drivers/vhost/vdpa.c b/drivers/vhost/vdpa.c >>>>> index 2fcc422..92683e4 100644 >>>>> --- a/drivers/vhost/vdpa.c >>>>> +++ b/drivers/vhost/vdpa.c >>>>> @@ -115,6 +115,63 @@ static irqreturn_t vhost_vdpa_config_cb(void >>>>> *private) >>>>> ????? return IRQ_HANDLED; >>>>> ? } >>>>> ? +static void vhost_vdpa_setup_vq_irq(struct vdpa_device *dev, >>>>> int qid, int irq) >>>>> +{ >>>>> +??? struct vhost_vdpa *v = vdpa_get_drvdata(dev); >>>>> +??? struct vhost_virtqueue *vq = &v->vqs[qid]; >>>>> +??? int ret; >>>>> + >>>>> +??? vq_err(vq, "setup irq bypass for vq %d with irq = %d\n", qid, >>>>> irq); >>>>> +??? spin_lock(&vq->call_ctx.ctx_lock); >>>>> +??? if (!vq->call_ctx.ctx) >>>>> +??????? return; >>>>> + >>>>> +??? vq->call_ctx.producer.token = vq->call_ctx.ctx; >>>>> +??? vq->call_ctx.producer.irq = irq; >>>>> +??? ret = irq_bypass_register_producer(&vq->call_ctx.producer); >>>>> +??? spin_unlock(&vq->call_ctx.ctx_lock); >>>>> + >>>>> +??? if (unlikely(ret)) >>>>> +??????? vq_err(vq, >>>>> +??????? "irq bypass producer (token %p registration fails: %d\n", >>>>> +??????? vq->call_ctx.producer.token, ret); >>>> >>>> >>>> Not sure this deserves a vq_err(), irq will be relayed through >>>> eventfd if irq bypass manager can't work. >>> OK, I see vq_err() will eventfd_signal err_ctx than just print a >>> message, will remove all vq_err(). >>>> >>>> >>>>> +} >>>>> + >>>>> +static void vhost_vdpa_unsetup_vq_irq(struct vdpa_device *dev, >>>>> int qid) >>>>> +{ >>>>> +??? struct vhost_vdpa *v = vdpa_get_drvdata(dev); >>>>> +??? struct vhost_virtqueue *vq = &v->vqs[qid]; >>>>> + >>>>> +??? spin_lock(&vq->call_ctx.ctx_lock); >>>>> + irq_bypass_unregister_producer(&vq->call_ctx.producer); >>>>> +??? spin_unlock(&vq->call_ctx.ctx_lock); >>>>> + >>>>> +??? vq_err(vq, "unsetup irq bypass for vq %d\n", qid); >>>> >>>> >>>> Why call vq_err() here? >>>> >>>> >>>>> +} >>>>> + >>>>> +static void vhost_vdpa_update_vq_irq(struct vhost_virtqueue *vq) >>>>> +{ >>>>> +??? struct eventfd_ctx *ctx; >>>>> +??? void *token; >>>>> + >>>>> +??? spin_lock(&vq->call_ctx.ctx_lock); >>>>> +??? ctx = vq->call_ctx.ctx; >>>>> +??? token = vq->call_ctx.producer.token; >>>>> +??? if (ctx == token) >>>>> +??????? return; >>>> >>>> >>>> Need do unlock here. >>> sure! >>>> >>>> >>>>> + >>>>> +??? if (!ctx && token) >>>>> + irq_bypass_unregister_producer(&vq->call_ctx.producer); >>>>> + >>>>> +??? if (ctx && ctx != token) { >>>>> + irq_bypass_unregister_producer(&vq->call_ctx.producer); >>>>> +??????? vq->call_ctx.producer.token = ctx; >>>>> + irq_bypass_register_producer(&vq->call_ctx.producer); >>>>> +??? } >>>>> + >>>>> +??? spin_unlock(&vq->call_ctx.ctx_lock); >>>> >>>> >>>> This should be rare so I'd use simple codes just do unregister and >>>> register. >>> >>> do you mean remove "if (ctx && ctx != token)"? I think this could be >>> useful, we should only update it when ctx!=NULL and ctx!= existing >>> token. >>> >> >> I meant something like: >> >> unregister(); >> vq->call_ctx.producer.token = ctx; >> register(); > This is what we are doing now, or I must missed somethig: > if (ctx && ctx != token) { > irq_bypass_unregister_producer(&vq->call_ctx.producer); > vq->call_ctx.producer.token = ctx; > irq_bypass_register_producer(&vq->call_ctx.producer); > > } > > It just unregister and register.I meant there's probably no need for the check and another check and unregister before. The whole function is as simple as I suggested above. Thanks> > Thanks, > BR > Zhu Lingshan
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