llvm dev - Dec 2013 - [LLVMdev] Help needed with creating new and replacing an old instruction

Hi,I have the following instruction in my IR-%call2 = call i8* @strcpy(i8* %1,
i8* %2) #2I intend to change call to strcpy with strncpy. I have included the
following code in runOnFunction, so that when it is strcpy's turn to be
invoked, strncpy is invoked instead.Assuming I* is the strcpy
instruction,CallInst* x=new
CallInst::CreateCall3(strncpy,1,2,ConstantInt(16),"my_strncpy");ReplaceInstWithInst(I*,x);I'm
running into a whole bunch of errors in CreateCall3(). How can I go about
writing this correctly?Any help would be appreciated.Thanks.Marc----email.biz 
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On Dec 2, 2013, at 6:42 PM, marc chellarmani <marcchellarmani at
email.biz> wrote:
> Hi,
> 
> I have the following instruction in my IR-
> %call2 = call i8* @strcpy(i8* %1, i8* %2) #2
> 
> I intend to change call to strcpy with strncpy. I have included the
following code in runOnFunction, so that when it is strcpy's turn to be
invoked, strncpy is invoked instead.
> 
> Assuming I* is the strcpy instruction,
> 
> CallInst* x=new
CallInst::CreateCall3(strncpy,1,2,ConstantInt(16),"my_strncpy");
> ReplaceInstWithInst(I*,x);
> 
> I'm running into a whole bunch of errors in CreateCall3(). How can I go
about writing this correctly?
> 
You’re using ‘new’ incorrectly. The ‘CreateCall3’ does all of the allocation and
creation of the call instruction.

-bw


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