llvm dev - Dec 2011 - [LLVMdev] Taking invoke instructions' labels

Hello everybody,
I am writing a pass, that does something on strings. It's a long story, so
I will write shortly.
If I have an iterator on invoke instruction, how can I take its label
parameters?
For example,
invoke void @_ZNSsC1EPKcRKSaIcE(%"class.std::basic_string"* %str, i8*
getelementptr inbounds ([6 x i8]* @.str, i32 0, i32 0),
%"class.std::allocator"* %2)
          to label %7 unwind label %20

Here I am trying to get the *label %7* and *label %20*. Is that possible?
We have tried just to increment our iterator, but it didn't help...

Sincerely, Schuhmacher.
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> invoke void @_ZNSsC1EPKcRKSaIcE(%"class.std::basic_string"* %str,
i8*
> getelementptr inbounds ([6 x i8]* @.str, i32 0, i32 0),
> %"class.std::allocator"* %2)
>           to label %7 unwind label %20
> 
> Here I am trying to get the *label %7* and *label %20*. Is that possible?
> We have tried just to increment our iterator, but it didn't help...
  Try "getNormalDest()" and "getUnwindDest()" functions?
  http://llvm.org/docs/doxygen/html/classllvm_1_1InvokeInst.html  

HTH,
chenwj

-- 
Wei-Ren Chen (陳韋任)
Computer Systems Lab, Institute of Information Science,
Academia Sinica, Taiwan (R.O.C.)
Tel:886-2-2788-3799 #1667
Homepage: http://people.cs.nctu.edu.tw/~chenwj

Hi Schuhmacher,
> I am writing a pass, that does something on strings. It's a long story,
so I
> will write shortly.
> If I have an iterator on invoke instruction, how can I take its label
parameters?
> For example,
> invoke void @_ZNSsC1EPKcRKSaIcE(%"class.std::basic_string"* %str,
i8*
> getelementptr inbounds ([6 x i8]* @.str, i32 0, i32 0),
%"class.std::allocator"* %2)
>            to label %7 unwind label %20
>
> Here I am trying to get the label %7 and  label %20 . Is that possible? We
have
> tried just to increment our iterator, but it didn't help...
if I is an InvokeInst*, then I->getNormalDest() gets you the basic block you
get
to if no exception is unwound, while I->getUnwindDest() gets the basic block
you
unwind to.

Ciao, Duncan.