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Lir

2007-Oct-02 20:35 UTC

HOW DO I DO THIS

Hello I want to submit a form that has a select which was updated
using ajax.updater
My Ajax.updater works fine. The problems is that in FIREFOX don''t
recognize or don''t get the name of the select tag and don''t
submit the
value or option.
Inside the form I have a <Div> where ajax.updater will replace the
select results. Once it''s updated I submit the form but the select
information isn''t post. at least it works fine in IE
Thanks in  advance for any help. This is the code

HTML
<form enctype="multipart/form-data" name="uploadt"
method="post"
action="'' . $form_action . ''" ">
<tr><td>Loss Seq</td>
      <td><div id="lossResult">
             <select
name="temp"><option></option></select> //AJAX
RESULT HERE
              </div>
      </td></tr>
</form>


NEW SELECT - AJAX UPDATER
echo "<select name=''submit_loss''
class=''upload''>"; //IT LOOKS GOOD BUT
IT''S NOT SUBMITTED
     echo "<option value=''000''
></option>";
        foreach ($return as $row)
        {
            echo "<option value=''$row[LOSS]''
selected>$row[LOSS]</
option></br>";
        }
    echo"</select>";


AFTER I SUBMIT EVERYTHING I WANT TO DISPLAY THE $_POST[SUBMIT_LOSS]
that right now I don''t see it                            . Something
like that
 <tr>
      <td>Loss Sequence Numbers:</td>
      
<td>''.$_POST[''submit_loss''].''</td>//NOTHING
APPEAR HERE
 </tr>


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Diodeus

2007-Oct-02 20:54 UTC

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Re: HOW DO I DO THIS

Why are you using enctype="multipart/form-data"? You''re not
uploading
a file. Perhaps this is why.


On Oct 2, 4:35 pm, Lir
<liriavillami...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
wrote:> Hello I want to submit a form that has a select which was updated
> using ajax.updater
> My Ajax.updater works fine. The problems is that in FIREFOX don''t
> recognize or don''t get the name of the select tag and
don''t submit the
> value or option.
> Inside the form I have a <Div> where ajax.updater will replace the
> select results. Once it''s updated I submit the form but the select
> information isn''t post. at least it works fine in IE
> Thanks in  advance for any help. This is the code
>
> HTML
> <form enctype="multipart/form-data" name="uploadt"
method="post"
> action="'' . $form_action . ''" ">
> <tr><td>Loss Seq</td>
>       <td><div id="lossResult">
>              <select
name="temp"><option></option></select> //AJAX
> RESULT HERE
>               </div>
>       </td></tr>
> </form>
>
> NEW SELECT - AJAX UPDATER
> echo "<select name=''submit_loss''
class=''upload''>"; //IT LOOKS GOOD BUT
> IT''S NOT SUBMITTED
>      echo "<option value=''000''
></option>";
>         foreach ($return as $row)
>         {
>             echo "<option value=''$row[LOSS]''
selected>$row[LOSS]</
> option></br>";
>         }
>     echo"</select>";
>
> AFTER I SUBMIT EVERYTHING I WANT TO DISPLAY THE $_POST[SUBMIT_LOSS]
> that right now I don''t see it                            .
Something
> like that
>  <tr>
>       <td>Loss Sequence Numbers:</td>
>       
<td>''.$_POST[''submit_loss''].''</td>//NOTHING
APPEAR HERE
>  </tr>

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Lir

2007-Oct-02 21:21 UTC

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Re: HOW DO I DO THIS

Well before the select tag I upload a file and have more input tags
that works fine.
I tried anyway without the enctype but it didn''t work.
Thanks anyways.


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Brian Williams

2007-Oct-02 22:51 UTC

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Re: HOW DO I DO THIS

ok, what''s yer ajax code, i think i might have it figured out.



On 10/2/07, Lir <liriavillamizar-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
wrote:>
>
> Well before the select tag I upload a file and have more input tags
> that works fine.
> I tried anyway without the enctype but it didn''t work.
> Thanks anyways.
>
>
> >
>
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Lir

2007-Oct-03 15:11 UTC

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Re: HOW DO I DO THIS

Here is my Ajax Code

function findLoss()
{
        var url = ''find_loss_seq.php'';
        var params = ''submit_policy='' +
$F(''submit_policy'');
        var ajax = new Ajax.Updater(
        {success: ''lossResult''}, url,{method:
''get'', parameters:
params, asynchronous:true, evalScripts:true});


}

this is find_loss-seq.php

 $query_loss = "SELECT"
                  . " LOSS_NUM"
                  . " FROM LOSS"
                  . " WHERE POL_NUM = ''".
$_GET[''submit_policy'']."''";

        $result_query_loss = $this->DB->Execute($query_loss);
        $return= $this->DB->GetAll($query_loss);


    echo ''<select name="submit_loss"
style="width:136px">'';
    echo ''<option value="000"
>&nbsp;</option>'';
        foreach ($return as $row)
        {
            echo "<option value=''$row[LOSS_NUM]''
selected>
$row[LOSS_NUM]</option>";
        }
   echo''</select>'';


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Frank Schummertz

2007-Oct-03 15:29 UTC

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Re: HOW DO I DO THIS

Slightly OT:

I hope this is not your real code, you are open for a SQL injection 
here. You need to remove any bad SQL inserted in
''submit_policy'', eg. by
using mysqlspecialchars().

>  $query_loss = "SELECT"
>                   . " LOSS_NUM"
>                   . " FROM LOSS"
>                   . " WHERE POL_NUM = ''".
> $_GET[''submit_policy'']."''";

-- 
"Laut einer Studie der deutschen Ärztevereinigung sterben immer
mehr Rentner vor dem Computer. Sie drücken versehentlich die
Tastenkombination Alt+Entfernen."

http://www.landseer-stuttgart.de
http://www.pn-cms.de

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Lir

2007-Oct-03 15:43 UTC

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Re: HOW DO I DO THIS

Thanks Frank for replay. Well this is my real code and I don''t
understand very well what do you mean?
I valid the submit_policy before send it to MYSQL but I don''t know if
it''s relevant with what you said.


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Brian Williams

2007-Oct-03 15:45 UTC

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Re: HOW DO I DO THIS

hrm... i''m not a pt expert... can anyone else say if that is a valid
target
for the updater?  I can''t find any reference to a success event used as
a
switch like used below...


var ajax = new Ajax.Updater(
       {success: ''lossResult''}, url,{method:
''get'', parameters:
params, asynchronous:true, evalScripts:true});



On 10/3/07, Lir <liriavillamizar-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
wrote:>
>
> Here is my Ajax Code
>
> function findLoss()
> {
>         var url = ''find_loss_seq.php'';
>         var params = ''submit_policy='' +
$F(''submit_policy'');
>         var ajax = new Ajax.Updater(
>         {success: ''lossResult''}, url,{method:
''get'', parameters:
> params, asynchronous:true, evalScripts:true});
>
>
> }
>
> this is find_loss-seq.php
>
> $query_loss = "SELECT"
>                   . " LOSS_NUM"
>                   . " FROM LOSS"
>                   . " WHERE POL_NUM = ''".
> $_GET[''submit_policy'']."''";
>
>         $result_query_loss = $this->DB->Execute($query_loss);
>         $return= $this->DB->GetAll($query_loss);
>
>
>     echo ''<select name="submit_loss"
style="width:136px">'';
>     echo ''<option value="000"
>&nbsp;</option>'';
>         foreach ($return as $row)
>         {
>             echo "<option value=''$row[LOSS_NUM]''
selected>
> $row[LOSS_NUM]</option>";
>         }
>    echo''</select>'';
>
>
> >
>
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Brian Williams

2007-Oct-03 15:55 UTC

head link

Re: HOW DO I DO THIS

what he means is

given
 $query_loss = "SELECT"
                 . " LOSS_NUM"
                 . " FROM LOSS"
                 . " WHERE POL_NUM = ''".
$_GET[''submit_policy'']."''";

the user can alter the url to (and this is just to get the point across I
don''t know the %chars to make it work as a real url)

yourpage.php?submit_policy=insert into users set
`username`=''username'',
`password`=''password'',`admin_level`=1

unfortunately I''m not as much of an expert on sql injections as i
should be,
but i think that gets the general idea across, if you don''t pasteurize
that
incoming $_GET statement you could be hurting when your site says
''Pwned by
n4t0 h4t0rz'' or some crap on it on the main page, and that would be the
least of your worries.  If your db carries sensitive information you could
be looking at not only lost income and security expenses but also lawsuits.




On 10/3/07, Lir <liriavillamizar-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
wrote:>
>
> Thanks Frank for replay. Well this is my real code and I don''t
> understand very well what do you mean?
> I valid the submit_policy before send it to MYSQL but I don''t know
if
> it''s relevant with what you said.
>
>
> >
>
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Frank Schummertz

2007-Oct-03 15:56 UTC

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Re: HOW DO I DO THIS

Lir schrieb:
> I valid the submit_policy before send it to MYSQL but I don''t know
if
Obviously not.

See http://en.wikipedia.org/wiki/SQL_Injection for more information 
about this topic.



-- 
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mehr Rentner vor dem Computer. Sie drücken versehentlich die
Tastenkombination Alt+Entfernen."

http://www.landseer-stuttgart.de
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Lir

2007-Oct-03 15:59 UTC

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Re: HOW DO I DO THIS

Ajax Updater shows the new values without problems in both IE and
Mozilla. But once I send the form to itself it shows nothing in
Mozilla. Is like the values weren''t send to the server.


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Brian Williams

2007-Oct-03 16:36 UTC

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Re: HOW DO I DO THIS

ok...not sure then

but another problem is
   echo ''<select name="submit_loss"
style="width:136px">'';
   echo ''<option value="000"
>&nbsp;</option>'';
       foreach ($return as $row)
       {
           echo "<option value=''$row[LOSS_NUM]''
selected>
$row[LOSS_NUM]</option>";
       }
  echo''</select>'';

all of your options are being marked as selected when they get returned to
the browser.



On 10/3/07, Lir <liriavillamizar-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
wrote:>
>
> Ajax Updater shows the new values without problems in both IE and
> Mozilla. But once I send the form to itself it shows nothing in
> Mozilla. Is like the values weren''t send to the server.
>
>
> >
>
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Lir

2007-Oct-03 16:48 UTC

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Re: HOW DO I DO THIS

I took out the selected from the options but it didn''t work.

echo "<option value=''$row[LOSS_NUM]''>
$row[LOSS_NUM]</option>";



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Brian Williams

2007-Oct-03 17:02 UTC

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Re: HOW DO I DO THIS

it''s got to be something easy, I have a site with 3 ajax based select
boxes
and all of them work just fine.

you say you use the form first to upload a file and then again to submit a
select box value?

and it returns the select box fine, but when you submit the data the second
time it doesn''t show the value of the select box?

have you tried making a form with just the ajax created select box and
submitting the form then?  I.e. the submitting of the select box will be the
first time the form is submitted.

On 10/3/07, Lir <liriavillamizar-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
wrote:>
>
> I took out the selected from the options but it didn''t work.
>
> echo "<option value=''$row[LOSS_NUM]''>
> $row[LOSS_NUM]</option>";
>
>
>
> >
>
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Lir

2007-Oct-03 17:15 UTC

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Re: HOW DO I DO THIS

Well not exactly. I send the form just one time. Here is what it does:
The user upload a file, enter the policy_number and once the
policy_number is enter
I call the ajax function (onBlur="findLoss()") to update immediately
the select box and then I submit the form to itself.
I know it should be something easy but I don''t see it. thanks for your
help


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Stan Rogers

2007-Oct-08 06:41 UTC

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Re: HOW DO I DO THIS

If your original post is anything like reality, the problem is simply
that the submit_loss <select> element is outside of the <form> that
is
getting submitted.


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Lisa B

2007-Oct-08 17:27 UTC

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Re: HOW DO I DO THIS

maybe you need double quotes around that value attribute, you are echo-
ing single quotes around your value, is that even valid html?

foreach ($return as $row)
        {
            echo "<option value=''$row[LOSS]''
selected>$row[LOSS]</
option></br>";
        }


and, is that value really being echoed?  I''ve had trouble with echo-
ing associative arrays inside double quotes. maybe something like
this..
            echo ''<option
value="''.$row[LOSS].''" selected>''.
$row[LOSS].''</
option></br>'';


btw, is LOSS the name of the array element or a variable holding the
name?  php is going to take a long time to figure that out.. should
have single or double quotes around ''LOSS'' I think...

also what about this:

new Ajax.Updater(
        {success: ''lossResult''}, url,{method:
''get'', parameters:
params, asynchronous:true, evalScripts:true});


why brackets and the word ''success'' in the first attribute? 
maybe I''m
just not familiar with that syntax.. I would do this:

new Ajax.Updater(''lossResult'', url, {method:
''get'', parameters:
params, asynchronous:true, evalScripts:true}
);


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Brian Williams

2007-Oct-08 17:46 UTC

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Re: HOW DO I DO THIS

Very good point Lisa.  It reminded me of what I forgot to ask earlier to the
OP..

Do you use Firebug? or Fiddler or some other HTTP Proxy?

If so can you verify that there is actually a value SET to each option on
the AJAX returned text?

a.k.a. verify that the returned text is not something along the lines of:

<option value="">Something</option>

if it is it would result in the error you are experiencing.




On 10/8/07, Lisa B
<beforeamillionuniverses-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
wrote:>
>
> maybe you need double quotes around that value attribute, you are echo-
> ing single quotes around your value, is that even valid html?
>
> foreach ($return as $row)
>         {
>             echo "<option value=''$row[LOSS]''
selected>$row[LOSS]</
> option></br>";
>         }
>
>
> and, is that value really being echoed?  I''ve had trouble with
echo-
> ing associative arrays inside double quotes. maybe something like
> this..
>             echo ''<option
value="''.$row[LOSS].''" selected>''.
> $row[LOSS].''</
> option></br>'';
>
>
> btw, is LOSS the name of the array element or a variable holding the
> name?  php is going to take a long time to figure that out.. should
> have single or double quotes around ''LOSS'' I think...
>
> also what about this:
>
> new Ajax.Updater(
>         {success: ''lossResult''}, url,{method:
''get'', parameters:
> params, asynchronous:true, evalScripts:true});
>
>
> why brackets and the word ''success'' in the first
attribute?  maybe I''m
> just not familiar with that syntax.. I would do this:
>
> new Ajax.Updater(''lossResult'', url, {method:
''get'', parameters:
> params, asynchronous:true, evalScripts:true}
> );
>
>
> >
>
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Bastian Feder

2007-Oct-08 19:43 UTC

head link

Re: HOW DO I DO THIS

Hi Lir,
after such a mass of response it took me some time to catch up ;o)

Ok here is what I think:
You are returning the HTML- Tags from your Script urging Ajax.Updater
to add it to your webpage, right?

Did you try to return some JSON or XML data using Ajax.Request and
create the options by Javascript ??
I think I had a similar problem like you a while ago and solved it that way ..

If you are using prototype you might find the following useful:

<-- snip -->
// var select is the DOM- object of the select- field to be modified
// var data is normaly returned from the response script. here it is
created by hand to show the structure
var data      = new Array();
    data.push({optText:''Red'',
optValue:''red''}, {optText:''Yellow'',
optValue:''yel''},
              {optText:''Green'',
optValue:''gre''});
// add the new options
        data.each ( function (item){
		                var option = new Option(item.optText , item.optValue);
		                select.options[select.length] = option; // add an
option to the end of the current selection list
		            }
        );
<-- snip -->

I use this to create a set of selection field depending on each other.

hope this helps after all

lg
Bastian


On 10/8/07, Brian Williams
<brianw1975-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
wrote:> Very good point Lisa.  It reminded me of what I forgot to ask earlier to
the
> OP..
>
> Do you use Firebug? or Fiddler or some other HTTP Proxy?
>
> If so can you verify that there is actually a value SET to each option on
> the AJAX returned text?
>
> a.k.a. verify that the returned text is not something along the lines of:
>
> <option value="">Something</option>
>
> if it is it would result in the error you are experiencing.
>
>
>
>
>
> On 10/8/07, Lisa B
<beforeamillionuniverses-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org>
> wrote:
> >
> > maybe you need double quotes around that value attribute, you are
echo-
> > ing single quotes around your value, is that even valid html?
> >
> > foreach ($return as $row)
> >         {
> >             echo "<option value=''$row[LOSS]''
selected>$row[LOSS]</
> > option></br>";
> >         }
> >
> >
> > and, is that value really being echoed?  I''ve had trouble
with echo-
> > ing associative arrays inside double quotes. maybe something like
> > this..
> >             echo ''<option
value="''.$row[LOSS].''" selected>''.
> > $row[LOSS].''</
> > option></br>'';
> >
> >
> > btw, is LOSS the name of the array element or a variable holding the
> > name?  php is going to take a long time to figure that out.. should
> > have single or double quotes around ''LOSS'' I
think...
> >
> > also what about this:
> >
> > new Ajax.Updater(
> >         {success: ''lossResult''}, url,{method:
''get'', parameters:
> > params, asynchronous:true, evalScripts:true});
> >
> >
> > why brackets and the word ''success'' in the first
attribute?  maybe I''m
> > just not familiar with that syntax.. I would do this:
> >
> > new Ajax.Updater(''lossResult'', url, {method:
''get'', parameters:
> > params, asynchronous:true, evalScripts:true}
> > );
> >
> >
> > > >
> >
>

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Lisa B

2007-Oct-11 16:07 UTC

head link

Re: HOW DO I DO THIS

I have a form that works and I drop in form fields via ajax.updater,
dropping in the html.. but maybe it works because I''m not relying on
the default behavior of the submit button.. on click of submit I
serialize the form and then submit that string..


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