similar to: Fwd: Summary vs fivenum results for Q3

I've just started using R and am still a neophyte, but I found the following curious result. I'm using the current version of R (2.5.1 (2007-06-27) ). Why are the results for the third quartile different in the output from the summary and fivenum commands? For the following data set 457 514 530 530 538 560 687 745 745 778 786 790 792

Full_Name: Richard Huggins Version: 1.7.1 OS: windows 2000 Submission from: (NULL) (131.172.4.44) > x<-rnorm(100,2,1) > mean(x) [1] 1.73299 > summary(fivenum(x)) Min. 1st Qu. Median Mean 3rd Qu. Max. -0.3655 1.1070 1.7430 1.7320 2.3840 3.7910 > summary(x) Min. 1st Qu. Median Mean 3rd Qu. Max. -0.3655 1.1070 1.7430 1.7330 2.3830 3.7910 >

Full_Name: David Leong Version: 2.7.2 OS: Windows XP Submission from: (NULL) (12.187.86.2) It appears for the fivenum function, there is a strait average between two ranked samples. This should be a linear interpolation between ranks. For the following data set #data

Dear useRs, how can I construct a box&whisker plot based on the vector "fivenum"? The challenge I face is as follow: I have a table such as x | fivenum --------------- ... | (.....) ... | (.....) and so forth.... For each observation x I have generated a vector containing the fivenum estimates. The first challenge is to group my fivenum vectors into groups based on a

When all else fails, read the help page... ?fivenum says to look at ?boxplot.stats, and the "Details" section of ?boxplot.stats has, well, details. Tukey had reasons to call those hinges rather than quartiles. Andy > -----Original Message----- > From: Knut M. Wittkowski [mailto:kmw at rockefeller.edu] > Sent: Thursday, May 29, 2003 5:58 PM > To: Matthias Kirschner >

Dear all i use R only a few days and don't understand the difference between fivenum(x) und summary(x). > x [1] 20.77 22.56 22.71 22.99 26.39 27.08 27.32 27.33 27.57 27.81 28.69 29.36 [13] 30.25 31.89 32.88 33.23 33.28 33.40 33.52 33.83 33.95 34.82 > fivenum(x) [1] 20.770 27.080 29.025 33.280 34.820 > summary(x) Min. 1st Qu. Median Mean 3rd Qu. Max. 20.77 27.14

I must apologize in advance for asking a simple question. I am sure that a clue will be sufficient to get this show on the road. I am trying to graph tide prediction data in various ways. I haven't been able to answer this question after pouring over TFM. I read the datafile theight <- read.table("tides",header=TRUE) I do get a summary() or fivenum()

Dear Experts, I am trying to do a time-stratified case-crossover analysis on air pollution data and number of myocardial infarctions. In order to avoid model selection bias, I started with a simple simulation. I'm still not sure if my simulation is right. But the results I get from the "ts-case-crossover" are much more variable than those from a glm. Is this: a. Due to

Hi, I'm playing with moving some of my lattice graphics into ggplot2, and I'd like to ask how to achieve a couple of things, both of which are fully illustrated in self-contained code (and mostly minimal, although that left quite a bit) following this written description. 1. I quite often like to use a 'ghosted' reference across facets - for example, in my example program below,

Dear Experts, I am trying to do a time-stratified case-crossover analysis on air pollution data and number of myocardial infarctions. In order to avoid model selection bias, I started with a simple simulation. I'm still not sure if my simulation is right. But the results I get from the "ts-case-crossover" are much more variable than those from a glm. Is this: a. Due to the simple

Okay, so I have a homework projecr for R, and we had to input the following link as some sort of data: nb10 <- read.table("http://www.adjoint-functors.net/su/web/314/R/NB10"). Afterwards, we have to use fivenum(nb10) to find max, min, quantiles, and sd, but I'm okay with this. The next question is where I'm stuck. The question is as follows; Compare the median (use the

Dear Rusers, I would like to color different sections of a histogram different colors. I have an example that was done by "brute force" given below. Has anyone implemented something like this in general? If not, any suggestions/pointers on how to write a general function to do so would be most appreciated. Alan-

Full_Name: Arne Henningsen Version: 2.3.0, 2005-11-21, i686-pc-linux-gnu OS: SuSE Linux 9.0, Kernel 2.4.21 Submission from: (NULL) (134.245.140.242) I did not find any problems in "./configure" and "make", but "make check" fails: make[4]: Entering directory `/home/suapm095/Download/R-devel/tests/Examples' collecting examples for package 'base' ...

Hi. > a [1] 13 13 14 14 15 15 16 20 21 26 > summary(a) Min. 1st Qu. Median Mean 3rd Qu. Max. 13.0 14.0 15.0 16.7 19.0 26.0 > mean(a) [1] 16.7 > quantile(a) 0% 25% 50% 75% 100% 13 14 15 19 26 Clearly, this is not right. My Instructor and I have no idea why the program does that. I removed the program from the computer , installed it

Dear list, I am using a external program that outputs Q1, Q3, median, upper and lower whisker values for various datasets simultaneously in a tab delimited format. After importing this text file into R, I would like to plot a boxplot using these given values and not the original series of data points, i.e. not using something like boxplot(mydata). Is there an easy way for doing this? If I am not

I'm having trouble understanding the output from as.windrose(). For one thing, data on a boundary between sectors seem to be left out of the counts. I assume that explains the missing point in the output below (angle 45). Shouldn't one side of each sector interval be open, to include values such as my 45 in the example? Also, why does the angle 180 in my input apparently not result in

I'm not sure who is responsible for quantile(), but I assume they read this list. Ivan Frohne and I have produced a revision of the quantile.default() function which enables the computation of alternative sample quantile definitions. The code and .Rd file are attached. This enables the user to produce quantiles that are equivalent to those in various statistics package. There is a type

I was trying to help someone who used a spanish keyboard on a PC running Windows. he discovered that he had no tilde key. Does anyone know of any simple work-arounds? Thanks, Hank Dr. Hank Stevens, Associate Professor 338 Pearson Hall Botany Department Miami University Oxford, OH 45056 Office: (513) 529-4206 Lab: (513) 529-4262 FAX: (513) 529-4243 http://www.cas.muohio.edu/~stevenmh/

Windows 2000, R 1.6.1 When I try use the menu to download and install new packages, the result looks like this: {a <- CRAN.packages() + install.packages(select.list(a[,1],,TRUE), .libPaths()[1], available=a)} trying URL `[1]http://cran.r-project.org/bin/windows/contrib/PACKAGES' Error in download.file(url = paste(contriburl, "PACKAGES", sep = "/"),

I'm using the image.plot() function (fields package), but I want to enlarge the characters of the legend (as they are too small to be read in a combined figure), but there is no way I can find a command to do this. I can enlarge the legend bar (with legend.witdh), axis character size (cex.axis) or the total legend size (legend.shrink), but not the character size of the legend characters