Displaying 2 results from an estimated 2 matches for "b44r15c20".
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b44r15c19
2011 Dec 01
1
Fw: calculate mean of multiple rows in a data frame
...obe~B01R01C01
381
213
345
653
2
Control_2
probe~B01R01C02
574
629
563
783
3
Control_1
probe~B01R09C01
673
511
521
967
4
Control_3
probe~B01R09C02
53
809
999
50
5
MM0289~RFU:11810.15
probe~B29R13C06
681
34
115
587
6
MM0289~RFU:9238.41
probe~B29R13C05
784
443
20
784
7
MM16597~RFU:36765.38
probe~B44R15C20
719
251
790
445
8
MM16597~RFU:41258.94
probe~B44R15C19
677
363
268
686
NAME
ID
a
b
c
d
1
Control_1
probe~B01R01C01
381
213
345
653
2
Control_2
probe~B01R01C02
574
629
563
783
3
Control_1
probe~B01R09C01
673
511
521
967
4
Control_3
probe~B01R09C02
53
809
999
50
5
MM0289~RFU:11810.15
probe~B...
2011 Dec 01
1
calculate mean of multiple rows in a data frame
...obe~B01R01C01
381
213
345
653
2
Control_2
probe~B01R01C02
574
629
563
783
3
Control_1
probe~B01R09C01
673
511
521
967
4
Control_3
probe~B01R09C02
53
809
999
50
5
MM0289~RFU:11810.15
probe~B29R13C06
681
34
115
587
6
MM0289~RFU:9238.41
probe~B29R13C05
784
443
20
784
7
MM16597~RFU:36765.38
probe~B44R15C20
719
251
790
445
8
MM16597~RFU:41258.94
probe~B44R15C19
677
363
268
686.....
I would like to consolidate the data frame by parsing through the rows, and where the NAME is identical, consolidate into one row and return the mean.
I can do this for the first lines (Control_1 etc) by using aggregate()...