Hi:
Try the expm package. Using your example,
> R = A%*%B
> for(i in 1:100)
+ {
+ R = R%*%B
+ }> R
[,1] [,2] [,3] [,4] [,5]
[1,] 9.934879e+47 1.098761e+48 8.868476e+47 7.071831e+47 6.071370e+47
[2,] 1.492692e+48 1.650862e+48 1.332468e+48 1.062526e+48 9.122090e+47
[3,] 6.693145e+47 7.402373e+47 5.974708e+47 4.764305e+47 4.090293e+47
[4,] 5.895689e+47 6.520416e+47 5.262850e+47 4.196661e+47 3.602954e+47
[5,] 8.347321e+47 9.231830e+47 7.451326e+47 5.941778e+47 5.101187e+47
library(expm)
# The matrix power function is an operator % ^ %> A %*% (B %^% 101)
[,1] [,2] [,3] [,4] [,5]
[1,] 9.934879e+47 1.098761e+48 8.868476e+47 7.071831e+47 6.071370e+47
[2,] 1.492692e+48 1.650862e+48 1.332468e+48 1.062526e+48 9.122090e+47
[3,] 6.693145e+47 7.402373e+47 5.974708e+47 4.764305e+47 4.090293e+47
[4,] 5.895689e+47 6.520416e+47 5.262850e+47 4.196661e+47 3.602954e+47
[5,] 8.347321e+47 9.231830e+47 7.451326e+47 5.941778e+47 5.101187e+47
> system.time(replicate(1000, A %*% (B %^% 101)))
user system elapsed
0.02 0.00 0.01> system.time(replicate(1000, {R = A%*%B
+ for(i in 1:100)
+ {
+ R = R%*%B
+ } }))
user system elapsed
0.15 0.00 0.15
HTH,
Dennis
On Mon, Apr 18, 2011 at 9:06 AM, Filoche <pmassicotte at hotmail.com>
wrote:> Hi everyone.
>
> I'm using matrix product such as :
>
>
> #Generate some data
> NCols = 5
> NRows = 5
> A = matrix(runif(NCols*NRows), ncol=NCols)
> B = matrix(runif(NCols*NRows), ncol=NCols)
>
> #First calculation
> R = A%*%B
>
>
> for(i in 1:100)
> {
> ? ? ? ?R = R%*%B
> }
>
>
> I would like to know if it was possible to avoid the loop by using
something
> like mapply or anything else.
>
> Tx in advance,
> Phil
>
> --
> View this message in context:
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> Sent from the R help mailing list archive at Nabble.com.
>
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