You might save yourself some headaches by turning it into a matrix instead,
since all the columns are either integer or numeric:
tonedata <- data.matrix(tonedata)
Data frames are really lists, so even when you get a one-row subset, it's
still a one-row data frame. You can use unlist() to turn that into a
vector.
Andy
> From: Morten Sickel
>
> I have a huge frame holding holding model results for a number of
> locations and time series:
>
> > str(tonedata)
> `data.frame': 434 obs. of 339 variables:
> $ VALUE : int 101 104 105 106 111 118 119 121 122 123 ...
> $ COUNT : int 2443 184 1539 1016 132 1208 1580 654 864 560 ...
> $ AREA : num 6.11e+08 4.60e+07 3.85e+08 2.54e+08 3.30e+07 ...
> $ D1_1958 : num 470 446 452 457 407 ...
> $ D2_1958 : num 480 455 461 467 416 ...
> $ D3_1958 : num 493 469 475 480 429 ...
> $ D4_1958 : num 542 517 522 526 475 ...
> $ D5_1958 : num 585 560 565 568 517 ...
>
> I would like to be able to take all values, except the three first
> (value, count, area) and be able to plot them. I have managed
> to make a
> subset that looks like what I want, by doing tonedata[11,4:339], but
> that data set is not a vector that can be plottet, it is
> treated like a
> set of single values. I tried to use as.vector on the set, bot to no
> help. I am probably overlooking somehing quite simple, (not to mention
> not really understanding R's data model..) so help would be
> appreciated.
>
> --
> Morten Sickel
> Norwegian Radiation Protection Authority
>
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