similar to: North Arrow (.png file) on a Map

Hi list, Well, this time I’ve a doubt with mapping generation. I was already able to read and plot shapefiles, plot point on this map. All this without any problems, but now I want to do something that I think, only Golden Software Surfer is capable of. I would like to plot a kriging result on the existing map (map script below). Well I looked for on the net, but I was not able to be sure of

Dear colleagues, I have troubles while trying to display legend on the plot. I have data.frame fr > fr year M1 M2 1 1979 58.85198 56.77303 2 1980 57.59725 55.93749 3 1981 57.32133 55.55232 4 1982 54.69320 53.10566 5 1983 56.58973 55.03811 6 1984 58.81363 56.97641 7 1985 58.35583 56.82091 8 1986 60.41842 58.45457 9 1987

I am using R 2.2.1 on a Windows 2000 PC. When I do a grid() after the boxplot it overprints the boxplot: > boxplot(count ~ spray, data = InsectSprays, col = "lightgray") > grid(nx=NA, ny=NULL) > if I try the panel.first > boxplot(count ~ spray, data = InsectSprays, col = "lightgray", + panel.first=grid(nx=NA, ny=NULL)) > I can see the grid flash

Hi, I want to produce two parallel rotated strips with color gradient. So far, the sample strip is something produced by this: pushViewport(viewport(x = unit(0.638, "npc"), y =unit(0.386, "npc"), width=.62, height=0.006, angle=137.2)) grid.rect(y=100:1/100, just="top", gp=gpar(col=NA, fill=colorRampPalette(c("lightgray",

Hi, I wonder whether there is a way to generate a polygon (a triangle in my case) with color gradient using grid.polygon() in package grid? I tried something like library(grid) grid.polygon(x=c(0, 0.5, 1), y=c(0.5, 1, 0.5), gp=gpar(col=NA, fill=colorRampPalette(c("green", "lightgray"), space="Lab")(200))) But am only

Dear R list, I would like to illustrate the origin of the Student t distribution using R. So, if (sample.mean - pop.mean) / standard.error(sample.mean) has t distribution with (sample.size - 1) degree free, what is wrong with the simulation below? I think that the theoretical curve should agree with the relative frequencies of the t values calculated: #== begin options===== # parameters

Hi Pedro, If you keep that same margins for the second plot: par(mar=c(10,0,6,6)) barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray") it looks reasonably well aligned to me. Because you are plotting the counts of the values in Simulation, the ordinate (vertical axis) of the bar plot is in quite different units from that of the plot on the left side. Jim On Wed, Jun

Please can you send me some orientation? Many thanks in advance. Only if posible one book o similar example to understand why it is not what I try. El 8 jun. 2017 7:50 PM, "Pedro p?ramo" <percentil101 at gmail.com> escribi?: > Many thanks Jim. > > What I,m trying to show with the fhist plot is the empirical distribution > of the values of the left plot simulation.

Many thanks Jim. What I,m trying to show with the fhist plot is the empirical distribution of the values of the left plot simulation. You say: However, I don't think that this plot illustrates quite what you think it does. Can you give me a clue to try to illustrate better if it is not showing what I believe it shows a better way to show it? Many thanks in advance. El 7 jun. 2017

Hi Pedro, As a one-off, you just shove the coordinates around a bit: par(mar=c(11,0,6,6)) barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray", ylim=c(0,24)) However, I don't think that this plot illustrates quite what you think it does. Jim On Wed, Jun 7, 2017 at 4:01 PM, Pedro p?ramo <percentil101 at gmail.com> wrote: > Please, I'm trying to put

Hello, I have written a function that demonstrates the CLT by generating samples following the exponential distribution, calculating the means, plotting the histogram, and drawing the limiting normal curve as an overlay. I have the title of each histogram state the sample size and rate (1/theta) for the exponential (the output is actually 4 histograms), but I can't get the greek letter theta

Can you suggest a plot on the right side so that the right plot has the same units of left plot and reflect the counts of the number of time the values repeat, something like the empirical distribution? 2017-06-14 12:30 GMT+02:00 Jim Lemon <drjimlemon at gmail.com>: > Hi Pedro, > If you keep that same margins for the second plot: > > par(mar=c(10,0,6,6)) >

Dear R-ers, I hope there is a really simple solution to my problem. I've written a function that I saved in an .r file. I source this file in my code. For a while it worked fine. But then when I run the line: source("F mylineplot.r") I started getting a warning: In readLines(file) : incomplete final line found on 'F mylineplot.r' I have no idea why - I tried to check and

Hello, everybody! I have a code below that creates a data set and then a stacked bar chart based on that data set. No need to look at it - just notice please that my horizontal axis is a date varible (x=my.data$date). I have a question about the last 2 lines of this code: grid(nx=NULL,ny=NULL,col = "lightgray", lty = "dotted",lwd = par("lwd")) axis(1, las = 2) Could

Hi all, I have this code, but the marginal distribution plot doesn?t appear aligned with the left plot. I think could be something about layout or par() mar. The code was programmed by me time ago. Can anyone help me to get the marginal distribution on the center (more higher centered) id.txt Could have this code: 05/01/2016;9335,200195 06/01/2016;9197,400391 07/01/2016;9059,299805

Hola. Estoy realizando una ANOVA con la función lm() El ensayo tiene 3 réplicas por tratamiento y no se cómo incluir estas réplicas en la función lm(). Gracias por vuestra ayuda Yesica [[alternative HTML version deleted]]

Please, I'm trying to put the right plot higher and centered on the left values but I don't achive. I would appreciate so much your help El 6 jun. 2017 22:37, "Pedro p?ramo" <percentil101 at gmail.com> escribi?: > Hi all, > > I have this code, but the marginal distribution plot doesn?t appear > aligned with the left plot. > > > I think could be

Hi List, I’m using the vegan function specaccum to produce a rarefaction curve. In the function’s help it says: “Function ‘specaccum’ finds species accumulation curves or the number of species for a certain number of sampled sites or individuals”. Well, I would like to finds this curve for individuals, but when I compute it the function (using the ‘rarefaction’ method) gives me Sites, Richness

Dear list, I have done a scatter plot of multiple variables in the same graph, with different col and pch. I managed to do it with the following code but not know how to make a function of these so that next time if I want to do similar graph but with new variables, I dont have to copy the code and then change the old variables with the new ones but just call a function with the new

Dear List, I am creating a plot and I want to insert the tabular data below the X axis. I mean for every value of X I want to show the value in Y as a table below the plot. I think the attached image gives an idea of what I mean by this. Below is the code i am using now... but as you see the Y values don't have the right location. Maybe I should insert them as a table? Any ideas on that.