similar to: perform subgroup meta-analysis and create forest plot displaying subgroups

Hello, I'm switching over from SAS to R and am having trouble merging data frames. The data frames have several columns with the same name, and each has a different number of rows. Some of the values are missing from cells with the same column names in each data frame. I had hoped that when I merged the dataframes, every column with the same name would be merged, with the value in a complete

I have a samba 3.0.14a PDC on FreeBSD 6.0-RELEASE. With pam_mount on Ubuntu 5.10 users have their home mounted with mount.cifs. I have 2 issues with this setting. First with the evolution email client, when I pop my mails I have the following error: Cannot append message to mbox file: /home/profs/user1/.evolution/mail/local/Inbox: Permission denied The log.smbd shows: [2006/06/10 08:25:33, 2]

Hi, I want to do a meta-analysis with count data for treatement/control cases. Mi problem is that I need to use zero values (an informative zero value) for the mean and standard deviation for one of the treatement, but R has a problem: "Studies with zero values for sd.e or sd.c get no weight in meta-analysis". I can agroup the case by Family (byvar=Family). ¿Can you help me? Thanks!

I am stuck on trying to get the Lattice xyplot to output a separate PNG file each time through my 'for' loop. The files get produced but are empty. Here is the code. I'm running 1.9 on Windows. BTW is there a more efficient way of creating the separate output files than looping over the levels and subsetting? ......................................................... lev <-

Hi All, I have conducted a meta analysis using the metabin function. I want to plot 5 subgroups on the same forest plot. I have managed to do this using the byvar argument but when i plot the forest plot in R graphics I am unable to view the very top and very bottom of the image. It is as though the plot is too long. Is there a way in which I can ask R to show the entire plot within the

Hi! I want to do a meta-analysis with count data for treatement/control cases. Mi problem is that I need to use zero values (an informative value) for the mean and standard deviation for one of the treatement, but R has a problem: "Studies with zero values for sd.e or sd.c get no weight in meta-analysis". I can agroup the case by Family (byvar=Family). ¿anybody help me? Thanks! >

I use the following function to select a subgroup from a data vector (usually to calculate descriptive stats). select.range<-function (groupvec, min, max, data) { if (nargs() > 3) { min.cond <- groupvec >= min max.cond <- groupvec < max cond <- min.cond & max.cond selected <- na.remove(ifelse(cond, data, NA))

I would very much like to apply "subgroup discovery" techniques to some of the data I am analyzing at this moment. Subgroup discovery is an interesting approach and is quite well known in the Data Mining community, though in essence it is a purely statistical approach. To read an introductory article see "Subgroup discovery and visualization methods"

Dear Members of the R-Help, While using a R function - 'aggregate' that you developed, I become to have a question. In that function, > aggregate(x, by, FUN, ..., simplify = TRUE) I was wondering about what type of FUN I should write if I want to get "the most frequent value of the subgroup" as a summary statistics of the subgroups. I will appreciate if I can get

I need to do a simple cumulative sum by group and add the result to the data. I found an earlier thread in the help files with a few suggestions. Somewhat, one of the suggestions does not work with "my data", and I don't really understand why ? The error am getting using the "my data" below is... Error in data.frame(..., check.names = FALSE) : arguments imply

Dear all, If I have the following data frame: > set.seed(21) > df1 <- data.frame(col1=c(rep('a',5), rep('b',5), rep('c',5)), col4=rnorm(1:15)) col1 col4 1 a 0.793013171 2 a 0.522251264 3 a 1.746222241 4 a -1.271336123 5 a 2.197389533 6 b 0.433130777 7 b -1.570199630 8 b -0.934905667 9 b 0.063493345 10 b

Hi, I'm sure there's an easy approach to this issue, I'm just not seeing it. I have a data frame of the following form: Date class subclass count 8/1/2009 A X 1 8/1/2009 B X 2 8/1/2009 A Y 9 8/1/2009 B Y 3 8/2/2009 A X 1 8/2/2009 B X 5 8/2/2009 A Y

Dear R-ers, I have a large data frame (several thousands of rows and about 2.5 thousand columns). One variable ("group") is a grouping variable with over 30 levels. And I have a lot of NAs. For each variable, I need to divide each value by variable mean - by subgroup. I have the code but it's way too slow - takes me about 1.5 hours. Below is a data example and my code that is too

Hello, I'm having some difficulty understanding the useage of the "dropterm()" function in the MASS library. What exactly does it do? I'm very new to R, so any pointers would be very helpful. I've read many definitions of what dropterm() does, but none seem to stick in my mind or click with me. I've coded everything fine for an interaction that runs as follows: two sets

Hello, Using the following code i want to make a level or contourplot of some data that I produced library(grid);library(lattice); mydata <- read.table("avgee.dat"); mymat <- as.matrix(mydata); mymat <-t(mymat) vals<-as.vector(mymat); conc<-c(0.0, 0.5, 1, 1.5, 2, 2.5, 3, 3.5, 4, 4.5, 5); a<- c(0.01, 0.025, 0.05, 0.075, 0.1, 0.25, 0.5, 0.75, 1, 2.5,5.0, 7.5,10,

Hello all, I am trying to make a genome association plot for p-values related to SNPs and was fortunate to find that R contains a package that produces Manhattan plots which is what's preferred for my current project. The function mhtplot() is found in the 'gap' package which I installed in R 2.11.1 on Windows. I thought I'd test out the function first with the examples they

Hi, I posted this on StackOverflow also but did not get a response so I thought that I would also try luck here. The post is at: https://stackoverflow.com/questions/49120060/ggplot2-display-blocks-of-nested-split-violins Basically, I have the following test example: --cut-and-paste-from-here-on df <- data.frame(dens = rnorm(5000), split = as.factor(sample(1:2, 5000, replace =

Hello! Just would like to make sure I am not doing something wrong. I am running an OLS regression. I have several subgroups in the data set (locations) - and in each location I have weekly data for 2 years - on my DV and on all predictors. Looks like this: location week DV Predictor1 Predictor 2 location1 week1 xxx xxxxxxx xxxxxxxxx location1 week2 xxx xxxxxxx xxxxxxxxx . .

Dear all, I'm trying to solve the following problem, and hoping to get some advise here from the group I have a dataframe in which the same sample was measured more than once on the same day. I would reorganize the dataframe to get a single value (mean /median) for one day Patient Day Sample Test A 1 A 23 A 1 A 36 A 5 B 44 A 5 B 23 B 2 C 10 B 2 C 5 mean Patient Day Sample Test.mean A

I have Samba as a PDC w/ openLDAP backend. Everything works great. I have a question on how sub-groups work. For instance, my "Domain Users" group will have a SID of S-1-5-21-2213288279-2770996180-1086272762-513 What if I create a group under that one. Should it be "...-513-something" I am wondering how samba will know it is a sub group without a different ID. I am using