similar to: dotplot points color

Dear R experts, is there a simple way to remove the last char of a text string? substr() function use as parameter start end only... but my strings are of different length... 01asap05a -> 01asap05 02ee04b -> 02ee04 Thank you all, Gianandrea -- View this message in context: http://r.789695.n4.nabble.com/remove-last-char-of-a-text-string-tp2254377p2254377.html Sent from the R help mailing

Hi folk, I tried this and it works just perfectly tapply(iris[,1],iris[5],mean) but, how to obtain a single table from multiple variables? In tapply x is an atomic object so this code doesn't work tapply(iris[,1:4],iris[5],mean) Thanx and great summer holidays Gianandrea -- View this message in context: http://www.nabble.com/multiple-tapply-tp18868063p18868063.html Sent from the R help

Hi, sqldf is a fantastic package, but when the SELECT procedure runs unused levels remain in the output. I tried with the drop function, but without success. Do you have any suggestions? Thanx, Gianandrea data(iris) require(sqldf) base<-sqldf("select * from iris where Species <> 'setosa'") str(base) # Species with 3 levels! -- View this message in context:

Dear list, I read the SOM package manual but I don't understand how to perform (for example) 1) the SOM analysis on Iris data 2) with a visualization similar to that of figure 7 in http://www.cis.hut.fi/projects/somtoolbox/package/papers/techrep.pdf Any suggestion? Thanks in advance, Gianandrea -- View this message in context:

HI there, why these lines of code are correct plot(count~spray, data = InsectSprays) plot(InsectSprays$count) but this return an error: plot(count, data = InsectSprays); "data" method is not implemented in plot?! Thanx, Gianandrea -- View this message in context: http://www.nabble.com/plot-error-tp19624873p19624873.html Sent from the R help mailing list archive at Nabble.com.

I performed canonical correspondence analysis (cca) with the example data of vegan, but I'm not able to obtain a table like scores() for the constraining variables. I can see them in the summary() mode, but it would be great to have in a separate table. Any suggestion?, thanx Gianandrea require(vegan) data(varespec) data(varechem) vare.cca<-cca(varespec,varechem) scores(vare.cca)

Hi list, is it possible convert the xtabs result xtabs(breaks~tension+wool,data=warpbreaks) wool tension A B L 401 254 M 216 259 H 221 169 to a simple matrix or data frame? A B L 401 254 M 216 259 H 221 169 Thanks a lot! Gianandrea -- View this message in context: http://www.nabble.com/From-xtabs-to-matrix-tp24304588p24304588.html

Hi, The following produces almost exactly what I needed. The problems are that the 'panel.dotplot' call (commented) generates the error 'Error in NextMethod("[") : argument "subscripts" is missing, with no default'. The other problem is that the colors alternate between the levels of the 'site' variable, rather than 'year'. barley$yield2

Hello! In a grouped Dotplot, is there any way to set the color of error bars to be the same as the corresponding symbols? Example data: require(lattice) require(Hmisc) data(barley) Dotplot(variety~Cbind(yield, yield+2, yield-2)|year, groups=site, data=barley) I experimented with changing trellis settings of plot.line (as mentioned in the Hmisc documentation) as well as col.line settings in

Hello all, This question concerns the function Dotplot from the Hmisc package. My aim is to compare values between groups in each panel of the Dotplot, with the values of different groups clearly distinguishable by different symbols. All lines and symbols should be coloured in black. Before adding the panel function to the Dotplot, the groups behaved as desired and were marked by different

by considering this example from barley dataset #code start dotplot(variety ~ yield | site, data = barley, scales=list(x=list(log=TRUE)), layout = c(1,6), panel = function(...) { panel.dotplot(...) #median.values <- tapply(x, y, median) # medians for each variety #panel.abline(v=median.values, col.line="red") # but this

Hi, I'm experimenting with using (R)SQLite to do data management. Here are two little problems that I've encountered: 1. The presence of ',' in string values causes trouble since ',' is also the delimiter used in the SQL statement. 2. A newline '\n' line attached to the last string value of each row. Some examples: > library (RSQLite) Loading required

How to show panels for factor levels of conditioning variables which do have no values? E.g. there are panels for "Grand Rapids" when they have values: data( barley ) with( barley, dotplot(variety ~ yield | year * site, layout=c(6,2) ) ) There are no panels for "Grand Rapids" when there are no values for "Grand Rapids": my.barley <- subset( barley, ! ( site ==

Suppose I wanted to plot the barley data like this: dotplot(variety ~ yield | year+ site, barley, strip = strip.custom(style = 4)) The factor levels are far too long for that to be useful. I can overcome that problem if I shorten the levels like this: dotplot(variety ~ yield | year + site, barley, strip = strip.custom(style = 4, factor.levels =

By considering this reproducible example #start code library(lattice) dotplot(variety ~ yield | site, data = barley, layout = c(1,6), index.cond= function(x,y){median(x)}, panel = function(x,y,...) { panel.dotplot(x,y,...) median.values <- median(x) panel.abline(v=median.values, col.line="red")

x.fun <- function( formula, data ) dotplot( formula, data ) x.grp <- function( formula, groups, data ) dotplot( formula, groups, data ) data( barley ) > x.fun( variety ~ yield | site, data=barley ) # no problem > dotplot( variety ~ yield | site, groups=year, data=barley ) # no problem > x.grp( variety ~ yield | site, groups=year, data=barley ) object "year" not found

Hi , Name rate HEALTHALLIANCE HOSPITALS, INC -1.06211747 MOUNT AUBURN HOSPITAL 0.50960291 STURDY MEMORIAL HOSPITAL 2.64233232 LAWRENCE GENERAL HOSPITAL 2.15628558 CAMBRIDGE HEALTH ALLIANCE 1.23623144 I would like use

How can I add an extra column containing the rank to a ragged array indexed by more than one grouping factors? E.g. with the barley dataset: How can I to add an additional column ``rank'' containing the rank of the ``yield'' of the different varieties in relation to the indices ``year'' and ``site'' to the barley dataframe? I achieved to calculate the ranks with:

Folks at R help, I can't quite get the panel function to work the way I want within barchart. I guess I'm still not understanding how to piece together multiple panel arguments, especially when "groups" is specified. Example: I want to be able to add the value of "yield" to each section of each bar in this graph: barchart(yield ~ variety | site, data = barley,

Dear R-users, i encountered some problems when trying to adjust the line width of the axes and stripes in a plot created with ggplot2. I use the "barley" dataset of the lattice package to illustrate my problem: library(ggplot2) library(lattice) barley[["SD"]] <- 5 limits <- aes(ymax=barley$yield + barley$SD,ymin=barley$yield - barley$SD) p1 <-