similar to: Adjusting the Axis in a histogram to the prespecified breaks

Displaying 20 results from an estimated 300 matches similar to: "Adjusting the Axis in a histogram to the prespecified breaks"

2008 Mar 21
1
hist function+label second y-axis
Dear Forum, hist(x$LAN_3,col="green",xaxt='n',yaxt='n',xlab="",ylab="",main="",type="l") I?d like to craete a line not a bar in the hist function, but regrettably I get only warning messages: 1: Grafikparameter "type" ist veraltet in: title(main, sub, xlab, ylab, line, outer, ...) 2: Grafikparameter "type" ist
2012 Aug 13
2
Standard introductory presentation
Hi Everyone In the Contributed Documentation part of the R Project website there are dozens of various documents explaining this and that on R. Furthermore there is also the document "Introduction to R". In my thesis I have been using R here and there, so I would classify myself as an intermediate user after about 3 years of using it, but I am in no sense a professional. I am now on a
2012 Aug 13
2
R table as integrable object for large Latex Documents - avoiding SWeave
Hi, I am wondering whether some of you have a pointer to an alternative. I am currently writing my thesis in Latex (several documents), well grown over time, I am sure many of you are familiar with the situation. Likewise I am doing the quantitative analysis with R, and again a lot of lines of more or less wellwritten code. The outputs are graphs (which one can wonderfully integrate as PNG objects
2009 Jul 29
1
Subtract matrices within arrays along indices
I have the following array: 3 dimensional object, one dimension being year. Object is 3*3*3 library(plyr, reshape) a1<-rep(c(2007,2008,2009),9) a2<-c(rep("a",9),rep("b",9),rep("c",9)) a3<-c(rep(c(rep(1,3),rep(2,3),rep(3,3)),3)) a4 <- rnorm(27) A<-data.frame(cbind(comp=a2,val=a3, year=a1, a4)) A1<-melt(A, id=c("year", "comp",
2007 Aug 23
1
figure-definition and heatmap question
Hello, I have two questions. I'd like to visualize data with a heatmap and I have the following testcase: x <- rnorm(256) nx <- x + abs(min(x)) nnx <- 255/max(nx) * nx x <- matrix(nnx, 16, 16) rownames(x) <-
2009 Feb 18
2
Re place Values within vector using Translation vector
Dear everyone I would like to change values in vectors doing a translation. i.e. I have a start vector giving me the levels in one vector (numbers 1 to x - rating) and then I have a second vector giving me the values to be allocated (loss probabilities), but the number of potential rating classes and loss estimates is still subject to a lot of discussion. Attached a simplified version of the
2011 Dec 02
1
Willkommen bei der "R-help" Mailingliste
Hello everbody, I am new to this mailing list and hope to find some help. I'm trying to get into the spatstat package and encountered two problems. First a graphical one: There is an example dataset called "finpines" which has several marks (http://www.oga-lab.net/RGM2/func.php?rd_id=spatstat:finpines) When I pass the given code from the website to R data(finpines)
2012 Oct 05
1
LaTeX consistent publication graphics from R and Comparison of GLE and R
Hi Everyone I am at the moment preparing my thesis and am looking at producing a few Organigrams / Flow charts (unrelated to the calculations in R) as well as a range of charts (barcharts, histograms, ...) based on calculations in R. For the Organigrams I am looking at an Opensource package called GLE at sourceforge, which produces the text part in Latex figures which is very neat and also in
2008 Mar 01
1
jpeg and margin text
Hi guys, I use R 2.6.2 and Windows XP. I’ve got the following question: I wrote a lot of text into the margin of a plot. When I use the “jpeg”-function, only a little part of the margin text is displayed in the final jpeg? Any ideas to change it? Source-Code: datenbankdaten<-data.frame(LETTERS[1:20],
2011 Nov 02
1
Generate a sequence of vectors of different length
Hi everyone After the following setup sector=2 # Define Number of Sectors sectors=LETTERS[seq( from = 1, to = sector )] # Name sectors No_ent=round(3/runif(sector)) # Number of entities per sector #Tot_No_ent=sum(No_ent) Goal is to get a List like (A1, A2, A3, B1, B2, B3, B4) where A is denoting an industrial sector and then a numbered sequence of companies within the sector. The step
2011 Jun 29
3
time series interpolation
Hi there, I?ve got a datatable in R which I try to interpolate with this and get the Error below: > new$temp<- approx(w03_11temp$temp, n = (nrow(w03_11temp)*5))$y Error in new$temp <- approx(w03_11temp$temp, n = (nrow(w03_11temp) * 5))$y : Object of type 'closure' not registered Any idea?? Thanks a lot. -- View this message in context:
2007 Sep 26
2
generate fourth vector based on known correlations
I am trying to generate a fourth vector,z, given three known and fixed vectors, x1,x2,x3 with corresponding known and fixed correlations with themeselves and with z. That is, all correlations are known and prespecified. How can I do this? Thank you, ben
2004 Jun 15
1
R: slope estimations of teeth like data
On 15 Jun 2004 at 13:52, Vito Muggeo wrote: > Dear Petr, > Probably I don't understand exactly what you are looking for. > > However your "plot(x,c(y,z))" suggests a broken-line model for the > response "c(y,x)" versus the variables x. Therefore you could estimate > a segmented model to obtain (different) slope (and breakpoint) > estimates. See
2008 Nov 03
1
qr() and Gram-Schmidt
Hi, Why the qr() produces a negative Q compared with Gram-Schmidt? (note example below, except Q[2,3]) Here is an example, I calculate the Q by Gram-Schmidt process and compare the output with qr.Q() a <- c(1,0,1) b <- c(1,0,0) c <- c(2,1,0) x <- matrix(c(a,b,c),3,3) ########################## # Gram-Schmidt ########################## A <- matrix(a,3,1) q1 <-
2003 Dec 23
1
plot.survfit
Hello, How do I get plot.survfit to draw a survival curve with prespecified time periods, say 1 month, 2, months, 3 months, 6 months, 1 year, 2 years etc) instead of the individual times of all events? Sincerely Fredrik Lundgren
2005 Jan 11
3
Kolmogorov-Smirnof test for lognormal distribution with estimated parameters
Hello all, Would somebody be kind enough to show me how to do a KS test in R for a lognormal distribution with ESTIMATED parameters. The R function ks.test()says "the parameters specified must be prespecified and not estimated from the data" Is there a way to correct this when one uses estimated data? Regards, Kwabena. -------------------------------------------- Kwabena Adusei-Poku
2002 Jan 26
1
Trouble with contrasts
Greetings, I have a nagging problem with contrasts and I can't seem to resolve it. A factor exists with four levels (lib1, lib2, con1, con2) and when I check the contrasts or set the contrasts to any of the prespecified ones, I do not get the exact contrasts necessary to test the theoretically relevant ones. I need orthogonal contrasts that look just like this matrix: con1 con2
2012 Mar 28
0
Major update: meta version 2.0-0
Version 2.0-0 of meta (an R package for meta-analysis) is now available on CRAN. Changes are described below. Yours, Guido Major revision R package meta linked to R package metafor by Wolfgang Viechtbauer to provide additional statistical methods, e.g. meta-regression and other estimates for tau-squared (REML, ...) New functions: - metareg (meta-regression) - metabias
2012 Mar 28
0
Major update: meta version 2.0-0
Version 2.0-0 of meta (an R package for meta-analysis) is now available on CRAN. Changes are described below. Yours, Guido Major revision R package meta linked to R package metafor by Wolfgang Viechtbauer to provide additional statistical methods, e.g. meta-regression and other estimates for tau-squared (REML, ...) New functions: - metareg (meta-regression) - metabias
2011 May 29
0
Use of cruel and unusal frame sizes
Hi, I've been developing an application using CELT for some time and, for simplicity, have restricted frame sizes to powers of 2. During final testing I tested with a sound interface (the Phonic Firefly 302) whose ASIO drivers are very restictive in what they accept, and have about 6 allowable frame sizes < 512, a lot of which are odd numbers. However some are even numbered, so