similar to: What is going on?

Dear R users, A colleague of mine asked me how to write a script (an executable text file containing R code) in R. After I showed him, he said that after extensive searching of the R archives, he had not found anything like these techniques. He suggested that I share these methods to enable others to leverage R as a better alternative to bash/perl scripts. So in the interest of giving back to

On Wed, Nov 8, 2017 at 9:33 AM, Rafael Avila de Espindola < rafael.espindola at gmail.com> wrote: > Rui Ueyama <ruiu at google.com> writes: > > >> If you are creating an executable and if your executable is not > >> > position-independent, you're using Initial Exec model by default > which is > >> > as fast as variables accessed through

On Tue, Nov 7, 2017 at 8:16 PM, Rafael Avila de Espindola < rafael.espindola at gmail.com> wrote: > Rui Ueyama <ruiu at google.com> writes: > > >> So I am strongly against removing either non TLSDESC support of support > >> for the relaxations. > >> > > > > It's still pretty arguable. By default, compilers use General Dynamic > model

Hello, I am new to R. I often collect data at multiple sites and need to create separate graphs (such as scatterplots or histograms) of specific variables for each site. I have tried to do this by splitting the data frame and then using lapply, but it seems that the graphing commands cannot be called as functions. Here is a sample of my data, called "seeddist2": site

Sorry for the off-topic post, but I guess someone else may hit the same issue.... Having developed a rails application, I now need to put GPL text and a copyright notice at the start of each source file. For the .rb files, this will look like: # Copyright 2006 Robert Jones........... and for the .rhtml files it will look like: <!-- Copyright 2006 Robert Jones......... Can anyone think of

Hola, ¿qué tal? Tengo el siguiente problema. Me llegan (simplificando) cadenas del tipo 1,2,"algo"; 3,"cosa"; 4,2,3,7; y tengo que partirlas por el caracter ";" para meterlas en una lista. Lo hago con strsplit y no tengo problemas... ... hasta que recibo cadenas como 1,2,"algo;todo"; 3,"cosa"; 4,2,3,7; en las que existen puntos y coma

I have an lapply function call that I want to parallelize. Below is a very simplified version of the code: url_base <- "https://cloud.r-project.org/src/contrib/" files <- c("A3_1.0.0.tar.gz", "ABC.RAP_0.9.0.tar.gz") res <- parallel::mclapply(files, function(s) download.file(paste0(url_base, s), s)) Instead of download a couple of files in parallel, I get a

Hello, I am trying to convert BY to a data frame, consider the following example: exampleDF<-data.frame(a=c(1,2),b=c(10,20),name=c("first","second")) exampleBY<-by(exampleDF,with(exampleDF,paste(a,b,sep="_")),               function(x) {                 data.frame(                     name=as.character(x$name),                     a=x$a,                    

Dear R Users, I have 12 data frames, each of 12 rows and 2 columns. e.g. FeketeJAN MEAN SUM_ AMAZON 144.4997874 68348.4 NILE 5.4701955 1394.9 CONGO 71.3670036 21196.0 MISSISSIPPI 18.9273250 6511.0 AMUR 1.8426874 466.2 PARANA 58.3835497 13486.6 YENISEI 1.4668313 592.6 OB 1.4239179 559.6 LENA 0.9342164

Hi, I am trying to format some data (example matrix "m" below) for which each data point has 2 associated values separated by a comma. I want to replace values <3 with "0" to give the example output below. I have got as far as: out<-lapply(strsplit(m,","),as.numeric) Failed to identify anything along the lines of "[out<3]<-0" that works... Thank

---------- Forwarded message ---------- From: Kevin Clark <kevin.clark at gmail.com> Date: 01-Sep-2006 20:31 Subject: Dealing with exec? To: James Mead <jamesmead44 at gmail.com> Hey James, Sorry to bug you. I was curious how you''d handle a call to exec in a method you were testing. Kernel.stubs(:exec)... doesn''t seem to work but I''m not sure where else an

I have very large csv files (up to 1GB each of ASCII text). I'd like to be able to read them directly in to R. The problem I am having is with the variable length of the data in each record. Here's a (simplified) example: $ cat foo.csv Name,Start Month,Data Foo,10,-0.5615,2.3065,0.1589,-0.3649,1.5955

Hi, I''m trying to be really, really sure that a specific service is not running. The central part of this looks like that: service { ''foo'': ensure => stopped, enable => false } -> package { ''foo'': ensure => purged } The astute reader will notice that on the second run puppet will complain that the init script for foo is

Hi there, I have a problem about lapply, strsplit, and accessing list elements, which I don't understand or cannot solve: I have e.g. a character vector with three elements: x = c("349/077,349/074,349/100,349/117", "340/384.2,340/513,367/139,455/128,D13/168", "600/437,128/903,128/904") The task I want to perform, is to generate a list,

Hi Im confused by one thing, and if someone can explain it I would be a happy > rev(strsplit("hej",NULL)) [[1]] [1] "h" "e" "j" > lapply(strsplit("hej",NULL),rev) [[1]] [1] "j" "e" "h" Why dossent the first one work? What is it in R that "fails" so to say that you need to use lapply for it to get

I am new to R. I try to search the web but could not find the answer so I post it here asking for help. I have a csv file looks like this: (between two ==== lines) =========================== Machine Name,"Resource, Type","Resource, Sub-type","Resource, Instance",Date,,Data ->,,,,,, ,0.041666667,,,,,,,,,,, Time (HH:MM)

Hi All.... I''ve got this configuration to manage bind, I want the exec to be run whenever anything under /var/named or the file /etc/named.conf gets updated.... file { "/etc/named.conf": owner => root, group => root, mode => 0644, require =>

Hello, the package snow is not working on a windows cluster with MPICH2 and Rmpi. There is an error in makeCluster: launch failed: CreateProcess(/usr/bin/env "RPROG="C:\Programme\R\R-2.5.1\bin\R" "OUT=/dev/null" "R_LIBS=" C:/Programme/R/R-2.5.1/library/snow/RMPInode.sh) on 'cl1' failed, error 3 - Das System kann den angegbenen Pfad nicht finden. I

Hi all If I have a string, say "ABCDA", and I want to convert this to the sum of the letter values, e.g. A -> 1 B -> 2 etc, so "ABCDA" = 1+2+3+4+1 = 11 Is there an elegant way to do this? Trying something like which(LETTERS %in% unlist(strsplit("ABCDA", ""))) is not quite correct, as it does not count repeated characters. I guess what I need is

I am using gsub to remove numbers for each element of a list. Code is given below. testList <- list("this contains a number 1000","this does not contain") removeNumbers <- function(X) { gsub("\\d","",X) } outputList <- lapply(testList,removeNumbers) However, when I try to find the number of words in outputList as follows