Displaying 20 results from an estimated 200 matches similar to: "Initial values of the parameters of a garch-Model"
2011 Jan 20
1
Problems with ecodist
Dear Dr.Goslee and anyone may intrested in matrix manipulate,
I am using your ecodist to do mantel and partial mantel test, I have
locality data and shape variation data, and the two distance matrixs are
given as belowings. When I run the analysis, it is always report that the
matrix is not square, but I didn't know what's wrong with my data. Would you
please help me on this. I am quite
2007 Sep 18
0
[LLVMdev] 2.1 Pre-Release Available (testers needed)
On Fri, Sep 14, 2007 at 11:42:18PM -0700, Tanya Lattner wrote:
> The 2.1 pre-release (version 1) is available for testing:
> http://llvm.org/prereleases/2.1/version1/
>
> [...]
>
> 2) Download llvm-2.1, llvm-test-2.1, and the llvm-gcc4.0 source.
> Compile everything. Run "make check" and the full llvm-test suite
> (make TEST=nightly report).
>
> Send
2008 Jan 28
0
[LLVMdev] 2.2 Prerelease available for testing
Target: FreeBSD 7.0-RC1 on amd64.
autoconf says:
configure:2122: checking build system type
configure:2140: result: x86_64-unknown-freebsd7.0
[...]
configure:2721: gcc -v >&5
Using built-in specs.
Target: amd64-undermydesk-freebsd
Configured with: FreeBSD/amd64 system compiler
Thread model: posix
gcc version 4.2.1 20070719 [FreeBSD]
[...]
objdir != srcdir, for both llvm and gcc.
Release
2008 Feb 03
0
[LLVMdev] 2.2 Prerelease available for testing
Target: FreeBSD 6.2-STABLE on i386
autoconf says:
configure:2122: checking build system type
configure:2140: result: i386-unknown-freebsd6.2
[...]
configure:2721: gcc -v >&5
Using built-in specs.
Configured with: FreeBSD/i386 system compiler
Thread model: posix
gcc version 3.4.6 [FreeBSD] 20060305
[...]
objdir != srcdir, for both llvm and gcc.
Release build.
llvm-gcc 4.2 from source.
2010 Jun 18
1
12th Root of a Square (Transition) Matrix
Dear R-tisans,
I am trying to calculate the 12th root of a transition (square) matrix, but can't seem to obtain an accurate result. I realize that this post is laced with intimations of quantitative finance, but the question is both R-related and broadly mathematical. That said, I'm happy to post this to R-SIG-Finance if I've erred in posting this to the general list.
I've
2010 Mar 11
0
Multiple comparisons with a mixed effects model
Hello,
I have used R in the past to conduct multiple comparisons on standard linear models, but am a bit confused as to how to go about doing it with a mixed effects model.
I am conducting a bioindication study using carabid beetles in which I have four treatment types (forest harvest types with varying levels of canopy structure retention), and am using canopy closure percent as a covariate in
2007 Oct 02
0
Variable selection in R
Disclaimer : Short of having local statistical expertise at hand, I'm using
this list because I use R for variable selection in the context of linear
multiple regression but the questions I have relate more to basic statistics
than to R per se. Please redirect me to another appropriate list if such a
list exists.
I have the very common problem of identifying which (subset of) variables
are
2008 Mar 06
2
How to hold a value(Mean sq) with a string
Hi all:
Can someone advice me on how to hold the residuals
Mean sq value on a string
so it can be used in other calculations.
I was trying something like this:
Msquare<-dfr$Mean sq but fails..Thanks
dfr <- read.table(textConnection("percentQ
Efficiency
1.565 0.0125
1.94 0.0213
0.876 0.003736
1.027 0.006
1.536 0.0148
1.536 0.0162
2.607 0.02
1.456 0.0157
2.16 0.0103
2008 Mar 07
0
How to Estimate Covariance by Week based on a linear regression model
Hi all:
I have always used SPSS to estimate weekly
covariance based on a linear regression model
but have to hard code the model Std. Error and the
Mean-Square and then execute
one week a the time. I was wondering if someone
could give me an idea on how to estimate
weekly(WK) covariance using the summary and anova of
"dfr"(lineal model below). I have
to do this for 52
2011 Jul 24
0
[LLVMdev] [llvm-testresults] bwilson__llvm-gcc_PROD__i386 nightly tester results
On Jul 24, 2011, at 3:02 AM, Duncan Sands wrote:
> A big compile time regression. Any ideas?
>
> Ciao, Duncan.
False alarm. For some reason that I have not yet been able to figure out, these tests run significantly more slowly when I run them during the daytime, which I did for that run. I checked a few of the worst regressions reported here and they all recovered in subsequent
2004 Aug 19
2
glmmPQL in R and S-PLUS 6 - differing results
Greetings R-ers,
A colleague and I have been exploring the behaviour of glmmPQL in R
and S-PLUS 6 and we appear to get different results using the same
code and the same data set, which worries us. I have checked the
behaviour in R 1.7.1 (MacOS 9.2) and R. 1.9.0 (Windows 2000) and the
results are the same, but differ from S-PLUS 6 with the latest Mass
and nlme libraries (Windows XP).
Here
2007 Aug 30
2
How to multiply all dataframe rows by another dataframe's columns
Hello,
I have two data frames, X and Y, with two columns each and different numbers
of rows.
# creation of data frame X
Loc1.alleles <- c(1,5,6,7,8)
Loc1.Freq <- c(0.35, 0.15, 0.05, 0.10, 0.35)
Loc1 <- cbind( Loc1.alleles,Loc1.Freq)
X <- data.frame(Loc1)
#creation of data frame Y
Loc2.alleles <- c(1,4,6,8)
Loc2.Freq <- c(0.35, 0.35,
2005 Apr 14
4
data manipulation
Hello,
my question is about the data handling.
I have a data set that is lined as:
4 1 17 1 1
-5.1536 -0.1668 -2.3412 -0.5062 0.9621 0.3640 0.3678 -0.5081 -0.2227
0.8142 -0.0389 -0.0445 -0.0578 -0.1175 -0.1232 0.8673 -0.1033 -0.0796
-0.0341 -0.1716 -0.1801 -0.7014 0.6578 0.5611
4 1 17 2 1
-5.1536 -0.1668 -2.3412 -0.5062 0.9621 0.3640 0.3678 -0.5081 -0.2227
0.8142 -0.0389 -0.0445
2009 May 08
1
Merging two data frames with 3 common variables makes duplicated rows
I am new to R (ex SAS user) , and I cannot merge two data frames without
getting duplicated rows in the results. How to avoid this happening without
using the unique() function?
1. First data frame is called "tmv" with 6 variables and 239 rows:
> tmv[1:10,]
temps nom prenom sexe dist style
1 01:59:36 Cyr Steve H 45 free
2 02:09:55 Gosselin
2009 Aug 27
1
(no subject)
dear sir,
my data larger than this example but is of the following format:
y x Age
30 0.0323 O
24 0.0389 Y
158 0.058 Y
120 0.0581 O
100 0.0471 Y
102 0.0615 Y
160 0.0546 O
i ma making a scatter plot of y~x and want to specify different coloured and filled shaped for the points according the the third categorical variable A.
the code i have managed is :
plot(y~x,pch=as.numeric(factor(Age)))
2011 Jul 24
2
[LLVMdev] [llvm-testresults] bwilson__llvm-gcc_PROD__i386 nightly tester results
A big compile time regression. Any ideas?
Ciao, Duncan.
On 22/07/11 19:13, llvm-testresults at cs.uiuc.edu wrote:
>
> bwilson__llvm-gcc_PROD__i386 nightly tester results
>
> URL http://llvm.org/perf/db_default/simple/nts/253/
> Nickname bwilson__llvm-gcc_PROD__i386:4
> Name curlew.apple.com
>
> Run ID Order Start Time End Time
> Current 253 0 2011-07-22 16:22:04
2008 May 08
2
anova p value extraction
hello all,
Quick question, how do I get the p value out of the anova?
Thanks,
Paul
> pb<-aov(as.numeric(diff[5,16:33]) ~ grF)
> summary(pb)
Df Sum Sq Mean Sq F value Pr(>F)
grF 3 2.7860e+10 9.2867e+09 4.2236 0.02534 *
Residuals 14 3.0783e+10 2.1988e+09
---
Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 '
2004 Dec 02
1
treatment contrasts and summary.lm
Dear list members,
I have a 2-factor ANOVA where the summary.lm output looks like this
(using treatment contrasts):
Value Std. Error t value Pr(>|t|)
(Intercept) 0.0389 0.0220 1.7695 0.0817
as.factor(Block)1 0.0156 0.0066 2.3597 0.0215
as.factor(Block)2 -0.0018 0.0037 -0.4857 0.6289
as.factor(Block)3 -0.0007 0.0026 -0.2812 0.7795
2007 Nov 24
5
how to calculate the return?
Hi, R-users,
data is a matrix like this
AMR BS GE HR MO UK SP500
1974 -0.3505 -0.1154 -0.4246 -0.2107 -0.0758 0.2331 -0.2647
1975 0.7083 0.2472 0.3719 0.2227 0.0213 0.3569 0.3720
1976 0.7329 0.3665 0.2550 0.5815 0.1276 0.0781 0.2384
1977 -0.2034 -0.4271 -0.0490 -0.0938 0.0712 -0.2721 -0.0718
1978 0.1663 -0.0452 -0.0573 0.2751 0.1372 -0.1346
2012 Feb 28
1
Interpreting the Results of GLM
Hi, I'm wondering if you can help me, this is a really simple query but I
keep getting confused. I have run a GLM to see how boldness varies over
time following a particular treatment. The results are as follows...
Call: glm(formula = boldtwentyfour ~ treatment + boldcontrol)
Deviance Residuals:
Min 1Q Median 3Q Max
-1.7577 -0.5469 0.0456 0.5515 1.5327