Displaying 20 results from an estimated 7000 matches similar to: "Performing a glm binomial model"
2004 Aug 17
5
Bug in colnames of data.frames?
Hi,
I am using R 1.9.1 on on i686 PC with SuSE Linux 9.0.
I have a data.frame, e.g.:
> myData <- data.frame( var1 = c( 1:4 ), var2 = c (5:8 ) )
If I add a new column by
> myData$var3 <- myData[ , "var1" ] + myData[ , "var2" ]
everything is fine, but if I omit the commas:
> myData$var4 <- myData[ "var1" ] + myData[ "var2" ]
the name
2014 Apr 11
6
crear variable en base a nombre de columnas que tienen un 1
Buenos días.
Hoy ando un poco (o bastante) espeso y no doy con la tecla de una cosa
que seguro que es muy simple..
Pongo un ejemplo.
var1 <- c(rep(0,3),rep(1,2))
var2 <- c(rep(1,2),0,0,1)
var3 <- c(rep(1,2),rep(0,3))
var4 <- c(rep(1,2),rep(0,3))
datos <- data.frame(fila=1:5,var1, var2, var3, var4)
datos
datos
fila var1 var2 var3 var4
1 1 0 1 1 1
2 2 0
2013 Mar 25
2
Faster way of summing values up based on expand.grid
Hello!
# I have 3 vectors of values:
values1<-rnorm(10)
values2<-rnorm(10)
values3<-rnorm(10)
# In real life, all 3 vectors have a length of 25
# I create all possible combinations of 4 based on 10 elements:
mycombos<-expand.grid(1:10,1:10,1:10,1:10)
dim(mycombos)
# Removing rows that contain pairs of identical values in any 2 of
these columns:
mycombos<-mycombos[!(mycombos$Var1
2014 Apr 11
2
crear variable en base a nombre de columnas que tienen un 1
Carlos, en principio si sería algo así, sólo que en vez de quedarme con
todas las columnas var1 a var4 tuviera sólo 3, ya que en mis datos no
hay ningún caso que tenga el valor 1 en más de 3 variables..
Había llegado a una solución (mucho menos elegante que usando reshape),
que implicaba un for sobre las filas.
Jorge, creo que tu solución me vale.
Muchas gracias a los dos..
Saludos
El
2008 Mar 19
4
plot with diffrent colour and plotting symbols
Dear mailing list members,
I am a new R user, I would like to plot the follewing data
var1 <- c(1,2,1,1,2,1,2,1,2,2)
var2 <- round(rgamma(10,2,1)/0.1)*0.1
var3 <- c(0,1,0,1,0,0,0,0,1,0)
var4 <- c(1,2,2,2,1,1,1,1,1,1)
Var <- data.frame(var1,var2,var3,var4)
Var <- Var[sort(Var$var1),]
tt <- Var$var1+((runif(length(Var$var1))/6)-(0.5/6))
labelname <- c("time 1",
2008 Aug 07
2
List of "occurrence" matrices
R users,
I don't know if I can make myself clear but I'll give it a try. I have
a data.frame like this
x <- "var1,var2,var3,var4
a,b,b,a
b,b,c,b
c,a,a,a
a,b,c,c
b,a,c,a
c,c,b,b
a,c,a,b
b,c,a,c
c,a,b,c"
DF <- read.table(textConnection(x), header=T, sep=",")
DF
and I would like to sum all the combinations/occurences by a factor
(letter in this case) between
2012 Oct 17
2
loop of quartile groups
Greetings R users,
My goal is to generate quartile groups of each variable in my data set. I
would like each experiment to have its designated group added as a
subsequent column. I can accomplish this individually with the following
code:
brks <- with(data_variables,
cut2(var2, g=4))
#I don't want the actual numbers, I need a numbered group
data$test1=factor(brks,
2009 Sep 21
5
More elegant way of excluding rows with equal values in any 2 columns?
Hello, dear R-ers!
I built a data frame "grid" (below) with 4 columns. I want to exclude
all rows that have equal values in ANY 2 columns. Here is how I am
doing it:
index<-expand.grid(1:4,1:4,1:4,1:4)
dim(index)
# Deleting rows that have identical values in any two columns (1 line of code):
2011 Apr 04
2
reading from text file that have different rowlength and create a data frame
Hi R-experts
I have many text files to read and combined them into one into R that are
output from other programs. My textfile have unbalanced number of rows for
example:
;this is example
; r help
Var1 Var2 Var3 Var4 Var5
0 0.05 0.01 12
1 0.04 0.06 18 A
2 0.05 0.08 14
3 0.01 0.06
2011 Apr 04
4
merging data list in to single data frame
Dear R community members
I did find a good way to merge my 200 text data files in to a single data
file with one column added will show indicator for that file.
filelist = list.files(pattern = "K*cd.txt") # the file names are K1cd.txt
.................to K200cd.txt
data_list <-lapply(filelist, read.table, header=T, comment=";", fill=T)
This will create list,
2006 Jan 11
1
updating formula inside function
Dear R-Helpers
Given a function like
foo <- function(data,var1,var2,var3) {
f <- formula(paste(var1,'~',paste(var2,var3,sep='+'),sep=''))
linmod <- lm(f)
return(linmod)
}
By typing
foo(mydata,'a','b','c')
I get the result of the linear model a~b+c.
How can I rewrite the function so that the formula can be updated inside
the function,
2012 Mar 10
1
Use different panel functions with lattice
Hi,
I have a data.frame df with
names(df) = c("Var1", "Var2", "Var3", "Var4")
and I plot data with
xyplot(Var1+Var2~Var3|Var4, data=df)
I want to use different panel functions for Var1 and Var2.
How can I do ?
Something like :
panel.mypanel = function(x, y, ...) {
if (Var1) panel.Var1Panel(x, y, ...)
else panel.Var2Panel(x, y, ...)
}
2017 Oct 10
1
About multiple panels with limited space in-between
Hi R users,
I have a question about plotting. The following two datasets are an
example. What I have in mind is like the attached figure, but just have two
rows, top row is for DF1, bottom row is for DF2. The top and bottom rows,
have x-axis as var1, var2, var3, etc, while the y-axis represents A. For
each row, only the leftmost panel has y-axis ticks and label. For the two
rows, only the bottom
2012 Jan 10
4
Sum of a couple of variables of which a few have NA values
Dear everyone,
I have looked all over the internet but I cannot find a way to solve my problem.
In my data I want to sum a couple of variables. Some of these
variables have NA values, and when I add them together, the result is
NA
dat <- data.frame(
id = gl(5,1),
var1 = rnorm(5, 10),
var2 = rnorm(5, 7),
var3 = rnorm(5, 6),
var4 = rnorm(5, 3),
var5 = rnorm(5, 8)
)
dat[3,3] <- NA
dat[4,5]
2010 Nov 08
2
Several lattice plots on one page
Dear all,
I am trying (!!!) to generate pdfs that have 8 plots on one page:
df = data.frame(
day = c(1,2,3,4),
var1 = c(1,2,3,4),
var2 = c(100,200,300,4000),
var3 = c(10,20,300,40000),
var4 = c(100000,20000,30000,4000),
var5 = c(10,20,30,40),
var6 = c(0.001,0.002,0.003,0.004),
var7 = c(123,223,123,412),
var8 = c(213,123,234,435),
all = as.factor(c(1,1,1,1)))
2011 Aug 29
2
splitting into multiple dataframes and then create a loop to work
Dear All
Sorry for this simple question, I could not solve it by spending days.
My data looks like this:
# data
set.seed(1234)
clvar <- c( rep(1, 10), rep(2, 10), rep(3, 10), rep(4, 10)) # I have 100
level for this factor var;
yvar <- rnorm(40, 10,6);
var1 <- rnorm(40, 10,4); var2 <- rnorm(40, 10,4); var3 <- rnorm(40, 5, 2);
var4 <- rnorm(40, 10, 3); var5 <- rnorm(40, 15,
2007 Oct 15
2
Variable which has the maximum value of DF
Hi,
Suppose I have a data.frame like this
Lines <- "var1 var2 var3 var4 var5 var6
0 2 1 2 0 0
2 3 7 6 0 1
1.5 4 9 9 6 0
1.0 6 10 22 3 3
"
DF <- read.table(textConnection(Lines), skip=1)
names(DF) <- scan(textConnection(Lines), what = "", nlines = 1)
How do I find the
2007 Jul 03
2
vertically concatenating data frames
Hi,
what is the recommended way to vertically concatenate 2 data frames with
the same column names but different number of rows?
My problem is something along these lines:
df1 <- data.frame(var1=var1,var2=var2,var3=var3) # nrow(df1)=1000
df2 <- data.frame(var1=var4,var2=var5,var3=var6) # nrow(df2)=2000
I tried df <- c(df1,df2), no success. stack does not seem to be
appropriate
2008 Oct 12
1
Conditionally skip over "for(..){" and "}"??
Hi Folks,
I'm wondering if there's a secret trick to achieve the following.
I have some big code for analysis related to a named variable,
which will be one of several in the columns of a dataframe, and
I would like to be able to choose between a run for just one of
these variables, or a run which loops over them all.
So, for a single run, I could have the following kind of thing
in a
2010 Jul 29
3
Fwd: duplicates
-- Eredeti üzenet --
Feladó: Dévaványai Agamemnón <devavanyai@citromail.hu>Címzett: r-hel@r-project.org, r-hel@r-project.orgElküldve: 2010. július 29. 16:29Tárgy : duplicates
Sorry!
I try it again
Dear R Users!
I have a dataframe with duplicatecases. Var1 duplicated by var2.
var1 var2 var3 var4 var5
1 4 500 1 2
1 3 200 2 5
1