similar to: Changing histogram stack in qplot

R-users it appears I am leaning on your knowledge once again.  Is there any way to add a vertical line to a histogram and qplot "stacked" plot?  Here is my current attempt:   "qplot" approach attempt: qplot(Run, data = data_dataframe, breaks = breaks, fill = Temperature, main = short_title) + scale_x_continuous("Data") + scale_y_continuous("Freq")

Dear all, I am using the code as below   tdm <- melt(matrixToPlot)    p<- ggplot(tdm, aes(x = Var2, y = Var1, fill = factor(value))) +                   labs(x = "Mz", y = "T", fill = "D") +                   geom_raster(alpha=1) +                   scale_fill_discrete(h.start=1) +                   scale_x_continuous(expand = c(0, 0)) +                  

  Thanks again for the hints about adding the vertical line to the hist plot and in ggplot.  That worked great.    Based on that advice I've been flipping through the ggplot2 doc and ggplot-static\index.html webpage more looking for the answer to the next question.    Unfortunately, I haven't stumbled on a description of how to move around the location of the legend.    Here is what I

Hi , I would like to use ggplot2 to plot a matrix as an image. You can copy paste the following Data<-matrix(data=rnorm(900,80,20),nrow=30,ncol=30) lengthOut<-5 Lengths<- 15 library(reshape2) library(ggplot2) tdm <- melt(Data) ggplot(tdm, aes(x = Var2, y = Var1, fill = factor(value)),levels=seq(0,1,by=0.1)) +                   labs(x = "MHz", y =

I created this graph in ggplot and added ablines to the different facets by specifying with subset commands. As you might see, there are still a few issues. 1.) I would like to have the diamonds in a grey scale instead of colors. I accomplished this (see graph 2) until I overwrote the label title for the treatments and the colors came back (graph 1). I used these two commands: p=ggplot(data =

hi all this works <%= render :partial => "admin/works/work", :collection => @artist.works %> but this doesn''t <%= render :partial => "admin/works/worklist", :collection => @artist.works %> even though the partial _work.rhtml and _worklist.rhtml are identical. worklist.rhtml throws undefined local variable or method

Hi, Dummy data script and scripts are attached below. I would like to change the plot to look like this:

Hi, I've used the following command in qplot qplot(a$V1,geom="histogram",binwidth=0.15,fill = factor(a$V2),ylab="Frequency",xlab="Rate"); but the title in the legend shows up as factor(a$V2)...how can i change this? -- Rajesh.J [[alternative HTML version deleted]]

Hello all, I've been using the following qplot command: qplot(pixX,pixY, data=som, geom="tile", fill=rgb) + scale_fill_identity() + opts(aspect.ratio = .75) + facet_grid(unitX ~ unitY) Now I would like to convert it into the explicit ggplot grammar, so I can remove the extras: axes, labels, background, borders, facet labels, and extra white-space around the plot. (If anyone has

Hi all, I was trying to draw a stacked density plot like that : library(ggplot2); library(plyr) dat <- cbind(rnorm(300), rep(c(1,2), each=150)) ggplot() + geom_density(aes(x=dat[,1], fill=factor(dat[,2]), position="stack")) + xlab("") + ylab("") + scale_colour_manual(name = "Pallet", labels = c("X", "Y")) Here

Dear list, I would like to apply my own colours to a stacked area plot, done with qplot, but I have not succeeded... What do I have so far (I am dealing with the development of cover of specific groups of plants): library(ggplot2) library(RODBC) channel <- odbcConnect("myusername", case="tolower") sql <- "select trial, cover_of, dateofsurvey, cover from

Dear R-experts, Here below my R code working with quite a few warnings.? x11 and x12 are dichotomous variable (0=no and 1=yes). I substract 1 to ignore intercept. I would like not to ignore intercept. How to modify my R code because if I just remove -1 it does not work? y= c(32,45,65,34,23,43,65,76,87,98,7,867,56,45,65,76,88,34,55,66) x11=c(0,1,1,0,0,1,1,1,0,0,1,0,0,1,0,0,1,1,0,1)

Is this what you want? temp<-c(rep("Low",2),rep("Medium",2),rep("High",2)) light<-rep(c("Dark","light"),3) avg<-dat.avg2[,3] # se<-dat.avg2[,4] dat.avg.temp<-data.frame(cbind(avg,se)) dat.avg.temp<-data.frame(cbind(temp,light,dat.avg.temp)) dat.plot<-qplot(light,avg, fill=factor(temp),data=dat.avg.temp, geom="bar",

Dear all, I want some help improve my ggplot as following: Make the plottable area with grid, so is easy one to see where each box refers to x and y values. Add a color bar but with fixed values, that I want to specify. How   I can do those two? Before is some code what I have tried so far. Regards Alex

Dear, I am trying to visualise a time-progressing line (it's supposed to represent spread patterns) using brew package and Google Earth. The idea is to have a function which takes start and end point geographic coordinates, as well as number of intervals to chop the path up, and returns the collection of points segmenting this line. Unfortunately my calculations fail for large distances,

Hello list:) I have lots of values which I would like to get a histogram outline out of. An example of what I am talking about: testdata = runif(100) bbb = seq(0,1, by = 0.01) hist(testdata, breaks = bbb) I would like to get the outline of the resulting histogram. Now, I think that I can do this using the stepfun function. However, I am uncertain of how to get to the data the stepfun function

Not sure what you are trying to do here. The immediate issue is that you are getting 'y' on the RHS, because that is the 1st column in Dataset. So "for (i in 2:3)" might be closer to intention. However, a 0/1 regresson with no intercept implies that the mean for the "0" group is zero, and with two regressors that the mean is zero for the (0,0) group. Looking at the

In conducting studies of animal orientation and displacement, I need to produce circular histograms of angles (bearings in radians 0-2pi) where the centre of the circle indicates very few observations for a given bin of angles and outwardly concentric circles indicate greater frequencies of observations for a given bin of angles. I'd like not to have to write the function myself but I

I'm having trouble understanding the output from as.windrose(). For one thing, data on a boundary between sectors seem to be left out of the counts. I assume that explains the missing point in the output below (angle 45). Shouldn't one side of each sector interval be open, to include values such as my 45 in the example? Also, why does the angle 180 in my input apparently not result in

Hi everyone, I wonder if anyone knows the reason why the outputs of the same reprojection in r and arcgis are different?. The magnitude of the change can be up to 40 km in the poles. Basically, I have a database of points equally separated by one degree over the globe. In ARCGIS, I am projecting the data in GCS-WGS-1984 and then reprojected it to Berhmann to ensure equal area