Displaying 20 results from an estimated 10000 matches similar to: "retrieving variables values from a function"
2009 Mar 25
2
"[.data.frame" and lapply
Dear all,
Trying to extract a few rows for each element of a list of
data.frames, I'm puzzled by the following behaviour,
> d <- lapply(1:4, function(i) data.frame(x=rnorm(5), y=rnorm(5)))
> str(d)
>
> lapply(d, "[", i= c(1)) # fine, this extracts the first columns
> lapply(d, "[", j= c(1, 3)) # doesn't do nothing ?!
>
> library(plyr)
2009 Mar 25
2
"[.data.frame" and lapply
Dear all,
Trying to extract a few rows for each element of a list of
data.frames, I'm puzzled by the following behaviour,
> d <- lapply(1:4, function(i) data.frame(x=rnorm(5), y=rnorm(5)))
> str(d)
>
> lapply(d, "[", i= c(1)) # fine, this extracts the first columns
> lapply(d, "[", j= c(1, 3)) # doesn't do nothing ?!
>
> library(plyr)
2009 Apr 14
2
subset dataframe by rows using character vector?
Dear List,
I'm stuck on what seems like a simple indexing problem, I'd be very grateful to anyone willing to help me out.
I queried a dataframe which returns a character vector called "plot". I have another dataframe from which I want to subset or select only those rows that match "plot". I've tried subset, and also the "which" command.
plot
2008 Jun 18
2
highest eigenvalues of a matrix
DeaR list,
I happily use eigen() to compute the eigenvalues and eigenvectors of
a fairly large matrix (200x200, say), but it seems over-killed as its
rank is limited to typically 2 or 3. I sort of remember being taught
that numerical techniques can find iteratively decreasing eigenvalues
and corresponding orthogonal eigenvectors, which would provide a nice
alternative (once I have the
2009 Jun 25
3
grid.polygon() + color gradient
Hi,
I wonder whether there is a way to generate a polygon (a triangle in
my case) with color gradient using grid.polygon() in package grid?
I tried something like
library(grid)
grid.polygon(x=c(0, 0.5, 1), y=c(0.5, 1, 0.5), gp=gpar(col=NA,
fill=colorRampPalette(c("green", "lightgray"),
space="Lab")(200)))
But am only
2008 Apr 03
1
data.frame or list
Dear R list,
I'm having difficulties in choosing between a list or a data.frame,
or an array for the storage and manipulation of my data (example
follows). I've been using the three for different purposes but I
would rather like to know which is more adapted to what task.
Here is the data I'm currently working on: 200 observations, each
observation being a vector of length
2009 Apr 16
3
segment between points on different plots
Hi,
I need to draw a line segment between two points on different plots in the
same multigraph.I've tried looking at the zoominplot function in plotrix but
havent understood much.any help is appreciated
~Aks
[[alternative HTML version deleted]]
2008 Nov 09
1
[Rd] Re Bessel functions of complex argument
Dear all,
I'm writing a code that requires Bessel functions with complex argument.
Searching the list, I found the continuation of a thread I initiated a few
months ago:
http://tolstoy.newcastle.edu.au/R/e4/devel/08/03/0746.html
As I understand, the most promising option would be to use the fortran or C
implementation of Amos,
2008 Feb 03
1
distances between points in R^3
Dear R helpers,
I'm trying to write a numerical scheme for a boundary integral method
to solve an electromagnetic problem. This requires the computation of
the distance between points at the surface of an object (a sphere, in
my example). Here is my code,
> require(rgl)
> r<-1
> size<-10
> theta<-seq(0,2*pi,length=size*2)
> phi<-seq(0,pi,length=size)
> pc
2008 Feb 18
2
question on function arguments
Hi,
I have two small issues with my R code, no big deal but curiosity
really. Here is a sample code,
>
> x <- rnorm(1:10)
>
> foo <- function(a = 1, b = list(x = c(1:10), y = c(1:10))){
>
> for (ii in seq(along=b$y)){
>
> print(x[ii] + b$x[ii])
> }
>
>
> }
>
> foo() # default OK
>
> foo(b=list(x=1, y=c(1:10))) # only the first
2009 Mar 27
3
Ploting a matrix
Hi evrybody,
in a matrix consisting of 49 columns, I would like to plot all columns
against the first in 48 different graphs.
Can you help me?
Thank you in advance
Sebastian
--
***************************************************************************************************************
Dipl. Biol. Sebastian Krug
PhD - student
IFM - GEOMAR
Leibniz Institute of Marine Sciences
Research
2009 May 27
3
Axis label spanning multiple plots
Hello
I need to plot 3 graphs in a single column; the top two plots have the
same title, and I would like it to be written only once, centered
horizontally and spanning the two plots. Something like
t +------------+
| |
i | |
| |
t +------------+
l +------------+
| |
e | |
| |
1 +------------+
t
2009 Mar 09
3
How to write a function that accepts unlimited number of input arguments?
Dear R-helpers:
I am an R newbie and have a question related to writing functions that
accept unlimited number of input arguments.
(I tried to peek into functions such as paste and cbind, but failed, I
cannot see their codes..)
Can someone kindly show me through a summation example?
Say, we have input scalar, 1 2 3 4 5
then the ideal function, say sum.test, can do
2008 Apr 26
6
quasi-random sequences
Dear list useRs,
I have to generate a random set of coordinates (x,y) in [-1 ; 1]^2
for say, N points. At each of these points is drawn a circle (later
on, an ellipse) of random size, as in:
> N <- 100
>
> positions <- matrix(rnorm(2 * N, mean = 0 , sd= 0.5), nrow=N)
> sizes<-rnorm(N, mean = 0 , sd= 1)
> plot(positions,type="p",cex=sizes)
My problem is to
2009 Mar 14
3
[OT] two question about color space.
Hi there,
I try to plot visible light spectrum (380nm~780nm) with color
corresponding to the specific wavelength. However, I don't find a
function that could do this.
Another question, it's possible to plot a color space chromaticity
diagram like this:
http://upload.wikimedia.org/wikipedia/commons/thumb/0/02/CIExy1931.svg/300px-CIExy1931.svg.png
Thanks in advance!
Jinsong
2008 Jul 03
1
ggplot2 legend for vertical lines
Dear all,
The following example code produces a graph with ggplot2, to which I
add several vertical lines of arbitrary colors. I am not satisfied
with the legend: it automatically adds some vertical lines which I'd
rather not see (they confuse the reader rather than add information
in this case).
> library(ggplot2)
> dfr <- data.frame(values = sin(1:50/10),
> fact =
2009 Apr 03
2
Help pasting string as object name
I have a data frame containing monthly observations of the 'density' of each US state, recorded in variables named "density.AL", "density.AK", "density.AZ", and so on for all 50 states. The data frame (called d) also contains a variable called "Date" which is encoded as a string in the format "Jan-09", "Feb-09", etc.
I also have
2008 Apr 12
1
lm() of one matrix against another
Hello R list,
I have two matrices of identical dimensions, and I want to fit a
straight line for each pair of columns and plot the resulting lines.
I got it to work with a for loop, but there must be a better way,
> n<-5
> N<-10
>
> data.x<-matrix(1:(n*N),ncol=n)
> data.y<-matrix(1:(n*N) + rnorm(n*N,sd=1),ncol=n)
>
>
2008 Dec 10
4
tapply within a data.frame: a simpler alternative?
Dear list,
I have a data.frame with x, y values and a 3-level factor "group",
say. I want to create a new column in this data.frame with the values
of y scaled to 1 by group. Perhaps the example below describes it best:
> x <- seq(0, 10, len=100)
> my.df <- data.frame(x = rep(x, 3), y=c(3*sin(x), 2*cos(x),
> cos(2*x)), # note how the y values have a different
2008 May 04
1
adaptive optimization of mesh size
DeaR list,
I'm running an external program that computes some electromagnetic
response of a scattering body. The numerical scheme is based on a
discretization with a characteristic mesh size "y". The smaller y is,
the better the result (but obviously the computation will take longer).
A convergence study showed the error between the computed values and
the exact solution